Trigonometry Basics

Trigonometry Basics : LIVE Class at 8 PM Today!
Introduction of Trigonometry will be discussed in a simple way!
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At Manocha Academy, learning Science and Math is Easy! The school coursework is explained with simple examples that you experience every day! Yes, Science & Math is all around you! Let's learn every day from everyday life!

[@duggirambabu7792]

Q). *In a right angle triangle, if A = 90° and tanC = √3 then find sinB cosC + cosB sin C* Sol: *Method1:* tanC = √3 = tan60° ⇒C = 60° We know that A + B + C = 180° ⇒90° + B + 60° = 180° ⇒B = 30° ∴ *sinB cosC + cosB sinC* = sin30° cos60° + cos30° sin60° = (1/2)(1/2) + (√3/2)(√3/2) = 1/4 + 3/4 *= 1* *Method2:* *sinB cosC + cosB sinC* = sin(B+C) = sin(180°-A) = sinA = sin90° *= 1*

[@bestasphalt9player464]

This guys is single handedly better than my entire school with 50 teachers

[@AinaAsim-jl6hy]

I'm watchin this video in 2024😂

[@Damzel_Gould]

Same just now, I'm preparing for exam

[@ShackeriaDavis-ne6ue]

Same am preparing for a exam tomorrow😢. Hope mi pass😭😭

[@Damzel_Gould]

@@ShackeriaDavis-ne6ue Good luck ❤️

[@AinaAsim-jl6hy]

Good luck👍

[@user-tl8rh5re8s]

Same here 😢

[@bestasphalt9player464]

52 minutes and 25 seconds of pure master piece

[@kontrol_120hz6]

Not Gonna Lie but MANOCHA ACADEMY IS BETTER THAN BYJU'S

[@ManochaAcademy]

Thanks a lot :)

[@godswill2509]

true af

[@sfxabhi72]

Really

[@fastfire1322]

Yes

[@mk-142]

Absolutely right.

[@user-sj6hy8ze8c]

The answer is .... Tan C = √3 By trigonometric table, tan = √3, then C = 60° By angle sum property, ∠a + ∠b + ∠c = 180° 90° + ∠b + 60° = 180° ; 150° + ∠b = 180° ∠b = 180° - 150° ; ∠b = 30° By trigonometric table, Sin B = Sin (30°) = ½ Cos B = Cos (30°) = √3/2 Sin C = Sin (60°) = √3/2 Cos C = Cos (60°) = ½ Sin B x Cos C = ½ x ½ = ¼ Cos B x Sin C = √3/2 x √3/2 = ¾ From the equation, Sin B Cos C + Cos B Sin C = ¼ + ¾ = 4/4 = 1. So the answer to this equation is 1.

[@user-sj6hy8ze8c]

I have a doubt... Can we also solve this equation like this ↓? From equation, Sin B Cos C + Cos B Sin C By rearranging, Sin (B+C) + Cos (B+C) = Sin (30º + 60º) + Cos (30º + 60º) = Sin (90º) + Cos (90º) By trigonometric table, Sin (90º) = 1 Cos (90º) = 0 From the factorization, Sin (90º) + Cos (90º) = 1 + 0 = 1

[@duggirambabu7792]

​@@user-sj6hy8ze8c sinB cosC + cosB sinC = sin(B+C) + cos(B+C) *This is wrong.* *Formula:* sin(A+B) = sinA cosB + cosB sinA ∴ *sinB cosC + cosB sinC* = sin(B+C) *This is correct.* = sin(180°-A) = sinA = sin90° *= 1*

[@nihalMaTh]

sir i am in 9th std , and i had the curiosity to learn the basics of trigonometry, and my wish is now fulfilled only because of you sir, thank you sir

[@ashishpurohit7182]

you are in 9th me in 7th

[@ProdigySpiller]

I'm in 6th

[@myphysicsprof]

Playlist containing set of 4 long lectures on Trigonometry: kzbin.info/aero/PLn6POeOJkCuLVwh6RLfFDx0WnMhHocE0a

[@TubascoGaming]

❤From Kerala

[@nikhillsriram]

This Guy is saving my tution fee......... 😄😄😄

[@veerue6]

Me too

[@krk6058]

if it helps please like... for sin cos and tan theta if someone is using adjascent opposite and hypotenuse an easy way to remember this is Old Henry for O/H (opposite by hypotenuse for sin theta), And His for cos theta Old aunt for tan theta so the sentence formed will be Old Henry And His Old Aunt

[@vijayalakshmik4826]

Spending 52 minutes for this video is valuable, very very valuable.... And also Sir, I like your way of teaching.

[@ManochaAcademy]

Glad to hear that

[@badhribhaskaran6187]

I think the answer for the homework question is 1, as tan 60 is √3/1. The hypotenuse will be 2 when calculated by Pythagoras theorem. Therefore, sin B=1/2 and B is 30. cos C=1/2 and sinBcosC is 1/4. cosB is √3/2 and sinC is √3/2 and cosBsinC is √3/2 * √3/2 = √9/4 = 3/4. When they are added 1/4+3/4= 4/4=1, so the answer for the question must be 1..

[@bhavanipakki3524]

For tommorow's exam u helped me a lot sir thank you very much

[@ManochaAcademy]

All the best

[@krk6058]

Thanks a lot sir for the explanation, i can picture a paper where i have already got everything correct

[@ManochaAcademy]

Most welcome

[@pushpdahiya3044]

Most Welcome

[@SHADOWFACTSINTELUGU]

@@ManochaAcademy sir the answer is 1 isn't?

[@sachingaware4142]

Hi 🤴🤴 king 👋😘😍😍😍❤️😍

[@sachingaware4142]

@@pushpdahiya3044 ilove you

[@thilak_4740]

sir....ur the only one teaching in english...most of the teachers take in hindi..i cant understand...im from tamilnadu....tq soo much for taking the class in english

[@ManochaAcademy]

You are most welcome

[@pranavabala006baskar2]

It's even more easier as we learned in school to call those formulas with sides, adjacent, etc... but here with calling it as perpendicular and hypotenuse like p/h, b/h, p/b makes it more easier than that type

[@chandranr9389]

What I did not learn in 1970s in my college now I learnt very easily. Now I am keen to learn this in my late 60s. Learning maths made easy. Follow this in schools/colleges,

[@drmeganathp9341]

Even my physics sir shows ur videos in online classes...... I m not at all joking..

[@Mikhail-tal-the-GOAT]

Same here

[@santhosh4966]

Here too

[@formaleditfanpage7879]

Ya

[@XYZ-up8rz]

Same here :"))

[@kumar7163]

kzbin.info/www/bejne/m2aVeqmfe6d1qJo

[@kgowtham5092]

Sir, the answer is 1 , here are the steps, angle b=30 degree, angle c=60 degree, 1/2×1/2+√3/2×√3/2=1/4+3/4, =4/4 that's 1

[@chanakyakakotiguptasvideo2650]

Perfect answer

[@ManochaAcademy]

Super! Right answer :)

[@infinitysumit7850]

Who u find angle b pls tell me

[@asrithaofficials11826]

Angle b=30

[@lucky_armyyy6596]

Hi sir! Hope you're doing great! My maths teacher had shared a memorandum with our class to help us remember the ratios of cos, sin and tan! I thought it would be easier for ppl to remember these ratios thru it, hence I would like to share it if you don't mind! It goes like this: 𝙎ome 𝙋eople 𝙃ave, 𝘾urly 𝘽lack 𝙃air 𝙏hrough 𝙋roper 𝘽rushing. The letters in bold refer to cos, sin and tan, whereas P, B & H refer to Perpendicular, Base & Hypotenuse respectively. Hope it helps! Also thank you for the wonderful video sir!

[@ManochaAcademy]

Nice mnemonic!! Thanks for sharing 😊

[@lucky_armyyy6596]

@@ManochaAcademy My pleasure sir! The credit goes to my maths teacher!

[@lucky_armyyy6596]

@BLACK SEVOU credit goes to my maths teacher!

[@Ramatulasi01]

Thanks for sharing

[@Ramatulasi01]

By the way are you BTS army?

[@poornimavyas7671]

You are one of the best teacher in the world sir, thank you for your support

[@ManochaAcademy]

Wow, thanks

[@sabchijmasthai]

Very good explanation sir ​@@ManochaAcademy

[@jjlrb_b]

I'm in class 7th, my bro said trigonometry is hard i just came to check it out and damn it is hard💀

[@shiftupz2064]

9th guys dont take trigonometry lightly if you want to acquire Engineering and other technical studies ahead .....i did take it lightly in my school days that time i was good at it but then i started taking it more lightly ...and now 21 yr old me watching it back right from beginning 🥲🥲🥲

[@binuphilip3347]

Can we call Base and Perpendicular as Opposite and Adjacent?? My maths teacher taught us like that!!

[@xoxodelphi]

you could, you can even denote those by random letters

[@ramyasamudrala4812]

I am 10 class while seeing this lesson in textbook is like🤯but when I listened ur class it’s looking easy and I gained confidence thank you sir🥰

[@saatvikkalra6061]

Yup same looks way harder than it actually is

[@karunya_06]

Q A=90°, B=30⁰, C=60⁰ = SinB (1/2) x cosC (1/2) + cosB (√3/2) x sinC (√3/2) = 1/4+3/4 = 4/4 = 1 Answer 1

[@apurvakumardani172]

Yes😄

[@anjalikv6599]

Words are not enough to thank you Sir . Please keep on uploading new videos.You're a life saver.

[@elisabethmuzingwa8000]

thank you for making our maths much more easier

[@ManochaAcademy]

Happy to help!

[@TennesseeZ]

Thank you for making the english language much more stupider.

[@elisabethmuzingwa8000]

@@TennesseeZ i don't blame you

[@padmanavapaul8215]

Your lessons are absolutely amazing... I love it the way you make it interesting.

[@iamtharunraj]

I love how he teaches us from his heart. Really appreciated sir. Thanks Alot!

[@Hani_x_.]

After watching lot of videos I came across your one. Very detailed and beautiful teaching. You are best than my teacher at school😅

[@chiranthr4194]

Iam in 8th class and iam preparing for jee and it helps me a lot

[@eswarathummala3685]

I told to my friends to listen to your classes when I was listening in pandemic you helped us a lot you are much better than our school teachers .

[@VIJAYKUMAR-ei3vq]

Respected sir...what instruments and software ,you are using to make these videos....please tell me

[@pondurususeela987]

the answer for the home work question is 1\4 + 3/4 which is 4/4 i.e the final answer is 1

[@shivanimaurya7187]

It was a prestigious explanation. Thanks sir I don't have sufficient words for praising you.

[@jecelcapantoc4215]

Thank you so much sir. You make it simple and relevant. Keep it up.

[@vasundharawanne2004]

Very understandable 😊.. thank you for this..

[@want2learn]

Excellent teaching!! Thanks for this great video.

[@manjunathtondihal6100]

if i have teachers like you in my 12th i may be in different position ... thank you sir... i finally learned trigonometry ...thank you so much... and the answer is 1.

[@leonswhxre]

is it easy? because im having problems too

[@brysonsam5468]

Better than byjus , vedantu , whitehat jr. , Brainly , topper,.....and anything else.... U are the best sir....not just to post a comment..... Really superb sir ☺️☺️..... Thanks a lot...🙂🙂 And sir when is your next live session...I'm waiting eagerly....plz do reply..

[@ManochaAcademy]

Thank you so much 😀 Notification will be given on You Tube

[@brysonsam5468]

@@ManochaAcademy ok sir...

[@ngngarum9128]

I have never ever found such a great teacher like u sir, the way sir teaching is one of my my favourite teaching type it makes me to understand very well

[@preethamreddy2834]

Thank you i was struggling with this concept and you made it easy for me

[@ssaisrikanth2237]

Yes sir plzz do make a video on iit maths class 9 syllabus

[@dieudonekabika1834]

Hi, I thank manocha academy for all. I'm a student but not in India and I'm in a secondary school. I was asking about the inverses in trigonometry. How do the work? Cause I have not heard about them.

[@izzah3949]

This is so helpful, all my basic concepts of trigonometry are clear..😁.. I've been looking for a video with such great explanation.... thanks a lot!

[@SukhdavKaushik-st3ql]

For guys who don't understand I explained you have seen protractor which is shaped like D We use D to draw angle we draw 90°angle which is called right angle a right angle have 3 side hypotenuse adjacent and opposite the diagnol line is hypotenuse right to it is opposite and left is adjacent When you take length of adjacent and make it square the make square with opposite side which number is given is given then you got square of hypotenuse in math it is called Pythagoras theorem a²+b²=c² Adjacent is 3cm opposite is 4cm Then according to Pythagoras theorem 3 square is 9 and 4 square is 16 and a²+b²=c² 9+16=25 and √25=5 length of hypotenuse is 5 cm

[@ssk111]

I wish I had a math teacher like you. Thank you sir!

[@nileshdekhane595]

The answer to the HW question is 1.

[@ManochaAcademy]

Excellent!! Right answer!

[@zahariastoianovici8590]

I think that using the “base” and “perpendicular “ is confusing when work with a different angle. 50 years ago when I learned trigonometry we used “side opposite to angle” and “side close to angle”

[@AkhilGaming2]

Very good teaching easily understandable. Well done 👍👍

[@travuscott5052]

🙋Solution ; Given :- A = 90° To find :- SinBCosC + CosBSinC......... (1) Solution :- TanC = 3 under root C = 60° In a right triangle the sum of angles is 180 we know 90°and 60°so, the third is 30°. B = 30° Putting values in (1): = (Sin30°)(Cos60°) + (Cos30°) (Sin60°) = (0.5) (0.5) +( /3÷2)(/3÷2) = 1 Ans.

[@shagufta1748]

After replacing the values how do u get the calculation down like 0.5.. Explain....

[@shivendratripathi3274]

@@shagufta1748 Check the table..... Sin30 = 1/2 = 0.5. Same goes with other values too.

[@prajval_7]

How If you cancel those you should get 1+1 = 2 But how 1

[@taelous_jeon]

@@prajval_7 It's pretty simple dear... Substituting the values, we get 1/2 * 1/2 + √ 3/2 * √ 3*2 => 1/4 + 3/4 .......{√ 3*√ 3 = 3} => 4/4 {same denominators, thus we simply add the numerators} = 1 {after cancelling the final answer is 1} Hope this helped! ^-^

[@shagufta1748]

@@shivendratripathi3274 ok

[@preetham2398]

There is a unique way of teaching in you sir.Thank you .even the tips for the exams are very useful for all of us.🎊🎊

[@ManochaAcademy]

Most welcome

[@salonikumar8429]

Sir you really explain very well...... Thank you for the explanation of this chapter

[@jack_frost5905]

The best maths teacher ive ever seen on KZbin, God bless you sir

[@teamrtg7000]

For better Iq, for better education, for better qualification join manocha academy👍🏻

[@ManochaAcademy]

Thanks for liking

[@gaminguniverse3976]

u are a genius sir . never have i understoood trig that easy anywhere.

[@swfwallah8815]

Thanks sir you helped me a lot I am learning basic for physics work power energy (resolution of vector)👍

[@AliAsgar-qd9zl]

This so good I started trigo tday and got the hang of it Thx for superb explaination

[@chandranpaniker3048]

Thank you sir for giving these kind of excellent explanation. I understood very clearly

[@ManochaAcademy]

Glad to hear that

[@I_Programmer_]

Sir i am in class 8th and i am interested in learning trigonometry from now and these are good videos given by you 🙂👍

[@LoliLicker9696]

For me it's more like I NEED to learn it for physics 😭

[@idkwhoam1lol]

AND I AM IN CLASS 7 🙂😂

[@totalgaming7205]

Really you are guiding us in excellent way. Ans:1

[@hiteshyakkala6309]

Superb explanation sir you made us understand in a very short period of time in a easy way

[@Tr_IBS]

sinBcosC + cosBsinC = 1 Thank you

[@NeelSaiAtluri]

Sin(-) = Opp/ Hypo Cos(-)= Adj/ Hypo Tan(-)= Opp/ Adj. CSC (-)= Hypo/Opp Sec(-)= Hypo/ Adj Tan(-)= Adj/Opp

[@Mikhail-tal-the-GOAT]

Thanks bro 😁

[@santoshvhanmane7198]

Sir you are great I was thinking this lesson was too Hard but you make it too simple ❤️❤️❤️

[@techcroods1007]

Hey sir it's helping me for my cycle test for my term 1

[@harishsundar3041]

Thanks for the video I understood

[@prajeenk6946]

Thanks for the explanation sir, your explanation is very awesome

[@ManochaAcademy]

You are most welcome

[@vivekreddy1918]

Sir this was truly inspiring It was soo up to the point Ur the best teacher that I have seen so far U made it seem so easy Hats off Sir !

[@bojjasreeja5678]

Thanks for teaching sir,I understood better than school teaching. Thanks You are teaching best sir thank you sir.

[@KALRAJfitness]

😘😘 thanks beta 🤗

[@bestasphalt9player464]

Thank you so much sir ! Your help means a lot to me and you definitely deserve a sub !

[@arogya_grg]

Real video starts from 1:31

[@LannievelleDegamo]

your a great teacher. Thank you so much.

[@NasirUddin-ru4si]

Can I ask about the last sum,that how u took that identities when it is given that tita is30

[@ranuballa8788]

Sir app ki tara koi dunia mah education nahi dae sakta ☺☺

[@ManochaAcademy]

Thanks a lot. Share with your friends

[@h.gnawabzade7560]

kzbin.info/www/bejne/ipbWfqxuoKmopJY Dekho

[@sidhiqhasherin7156]

I have my exam tmw and ur my life saviour thank you so much sir 💜

[@xoxodelphi]

how did you do

[@ManochaAcademy]

Happy to help

[@sidhiqhasherin7156]

@@xoxodelphiI did great 😃 this video was much helpful to me .

[@akularameshbabu5103]

I have a doubt can we say that "sin" is inversely proportional to "cosec " because you have written it as sin = 1/cosec

[@praveendubbaka9328]

Sir, when do we use this type of sin, cos etc...??

[@mahalakshmi3073]

Thank you so much for sharing this sir 😊❤️ it's really very usefull ✨

[@sallasrisailam4585]

Sir..U r teaching is very good...I am understanding very well..tq sir

[@ManochaAcademy]

Most welcome

[@user-vk8yf9uf9f]

Thanks!!! It really hekped me for my math week in school!

[@ManochaAcademy]

Welcome!

[@godspell2720]

i wish I had a teacher like you in my school days

[@sarahahmed2036]

i never understood trigonometry in school and tutions but somehow i understood by watching this video?😭 thank you

[@riyachoudhry4921]

I am in 9th but wanted to learn this trigonometry before my 10th. Now thinking why students are afraid of this chapter? I don't think so it's too hard to understand... By the way you explained it very well sir. Thank you..!!🤓🙃

[@mr-black_rock321]

how ab=bc? are we taking specify the type triangle to understand the tan 0 value?

[@manoharatmanoharat6855]

Thank you so much sir for understanding trigonometry basic

[@chichoraboysgaming3893]

SIR YOUR EXPLAINING IS EXCALENT 🙏

[@midinmallapu4019]

Legends are the one who watches this vedios to get full marks. But prays to God before exam to get 28 marks 😂

[@F..................]

It is true

[@ayeshaKhan77777]

Ikr

[@tayebwagerald2398]

Find the values of x between 0° and 360° satisfying the equation, 10sin²x+10sinxcosx-cos²x=2.

[@duggirambabu7792]

10Sin²x + 10SinxCosx - Cos²x = 2 ⇒10Tan²xCos²x + 10TanxCos²x - Cos²x = 2 ⇒Cos²x(10Tan²x + 10Tanx -1) = 2 ⇒10Tan²x + 10Tanx -1 = 2(1/Cos²x) ⇒10Tan²x + 10Tanx -1 = 2(Cos²x + Sin²x) / Cos²x ⇒10Tan²x + 10Tanx - 1 = 2(1 + Tan²x) ⇒8Tan²x + 10Tanx - 3 = 0 ⇒8Tan²x + 12Tanx - 2Tanx - 3 = 0 ⇒4Tanx(2Tanx + 3) - 1(2Tanx + 3) = 0 ⇒4Tanx - 1 = 0 or 2Tanx + 3 = 0 ⇒Tanx = 1/4 or Tanx = -3/2 ⇒x = Tan⁻¹(1/4) or x = Tan⁻¹(-3/2) = - Tan⁻¹(3/2) ∴ *x = Tan⁻¹(1/4) + n * 180°* or *-Tan⁻¹(3/2) + n * 180° where n ∈ Z* Given x between 0° and 360°, x = Tan⁻¹(1/4)+ 0° or -Tan⁻¹(3/2) + 180° or Tan⁻¹(1/4) + 180° or -Tan⁻¹(3/2) + 360° ∴ *x = 14.036°* or *123.69°* or *194.036°* or *303.69°*

[@GiduduEmma-cx7no]

Your the best teacher

[@BADBOY-pj7pb]

Ur very helpful sir

[@ManochaAcademy]

Glad to hear that

[@chethikarunakar3029]

Tq sir I am understand better than other videos 😊

[@seshasayeesudharsan7938]

What if the value of theta is given is it required for answering

[@ranibollepalli]

Understood very well

[@noyes5256]

Your explanation with your fluent language ....is best 😊😊

[@prasoon7916]

yes

[@singarapallijayanna8700]

Good explain sir🙏 l inspired to your class

[@mrpandey8578]

Hi sir

[@truptistalentsandlifestyle9803]

That was amazing....!!! Didn't know when it finished. Thanku so so so much sir

[@wanderlust1178]

Sir please conduct a live session for this year students pls.. not a day passes by without ur video I want u to conduct another live

[@ManochaAcademy]

Will soon do

[@wanderlust1178]

@@ManochaAcademy thankyou sir