I used some strange wording in starting the proof of ceva's theorem. A better way to think about it is, given 3 concurrent cevians, we give each of the points masses m_a, m_b, and m_c so that the center of mass lies at their intersection. Then we can find the ratios between the sides using that. And to match what I was trying to say in the video, this center of mass isn't fixed, the center of mass can be moved to the location of concurrency of any given cevian, and they allow us to compute lengths without using math. I hope this clears up any confusion (if there was any) :).
@tujan75984 жыл бұрын
How does this problem have 18 solutions on it's aops page?
@SlippingHexagons4 жыл бұрын
I have no idea lol
@anthonyhe76794 жыл бұрын
I like to watch this and pretend I understand what's going on
@SlippingHexagons4 жыл бұрын
I see lol
@anthonyhe76794 жыл бұрын
@@SlippingHexagons How's school lol
@SlippingHexagons4 жыл бұрын
@@anthonyhe7679 School's pretty good, but I've had a lot of busywork lately :(. How about you?
@anthonyhe76794 жыл бұрын
@@SlippingHexagons Yeah same :( At least I got shelton :D