Math Olympiad Xˣ = 2 | Hardest Math Problem in the World | Algebra

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In this captivating KZbin video, we delve into the intriguing world of mathematics and explore the enigmatic Math Olympiad problem Xˣ = 2. Join us as we unravel the complexities of this challenging equation, widely regarded as one of the hardest math problems in the world. Through a comprehensive analysis of algebraic principles, we break down the problem step by step, providing viewers with a deep understanding of the underlying concepts. Whether you're a math enthusiast, a student preparing for a competition, or simply curious about the wonders of mathematics, this video is sure to captivate and challenge your analytical skills. Tune in to witness the beauty and intricacy of mathematical problem-solving at its finest.
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Basic Concepts of Maths:-
• Basic Concepts of Maths
Olympiad Mathematics:-
• Olympiad Questions
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[@roger7341]

Use fixed-point iteration, x←2^(1/x), starting with x=1.5, to obtain x=1.559610469462369... on my pocket calculator. How was x=e^[W(ln2)] evaluated? You just wrote down 1.5596 and didn't explain where it came from. That's no way to teach. Did you use Wolfram-Alpha to evaluate W(ln2)? If that is the case then why not just enter solve x^x=2 and it returns x=e^W(ln2)=1.55961? What did I learn from that? Nothing. To solve real-world problems, fixed-point and Newton-Raphson iteration are the best choice.