Is this lecture series continuing soon? I hope so! It has been really great.
@algebraist_24Ай бұрын
I would like to know if the course continues in the autumn semester? I would be very happy with it. It would be nice to go through the Hatcher book.😊
@timelsen22363 ай бұрын
Thanks to you for explaining such confusing material so well!
@alvarotejedo78685 ай бұрын
When will next class be available?
@-minushyphen1two3796 ай бұрын
I paused every time you were about to calculate something (the cohomology and cup product on the torus, the same for the Klein bottle in Z coefficients, then with Z2 coefficients), which was a good exercise. This time I actually understood what was going on! (unlike the first time with homology)
@MathatAndrews6 ай бұрын
Excellent!
@fanalysis6734Ай бұрын
Maybe there could be a follow up on intersections
@infiniteseries621022 күн бұрын
When will it continue?
@md.mehedihasanrasel96843 ай бұрын
Need next lectures sir. Eagerly waiting for that sir.
@-minushyphen1two3796 ай бұрын
When I clicked on this video I thought you were going to multiply the torus and the klein bottle using the cup product, but then I realized it actually meant “evaluating the cup product on the generator cycles of the cohomology groups of the solids”
@xanderlewis4 ай бұрын
Just a quick off-the-cuff comment after seeing cohomology for the first time: since elements of the chain groups are Z-linear combinations of the generators (same thing as maps from the generators to Z), and elements of the cochain groups are homomorphisms from the free groups on the generators into Z (same thing as arbitrary maps from the generators to Z) and the addition operations on each coincide, aren’t they each (at least for Z coefficients) the same? I guess they might be, but the homology can differ because the boundary maps might differ. Also, I guess this has something to do with why the case of cohomology with Z coefficients is a special case and why in the torsion-free case they actually are the same.
@xanderlewis4 ай бұрын
I just realised I’m basically just observing that finite dimensional Z-modules are all isomorphic to their duals. Which is… I guess… a very standard fact.
@Desidarius_Erasmus996 ай бұрын
Sir I am watching you from India . You have done an extraordinary attempt to help us to overcome fear of algebraic topology . Sir this is my humble request to you please discuss about nets and filters too . This is also pretty confusing .
@ompatel90176 ай бұрын
Amazing video professor also expecting a course in intersection theory