Algebraic Topology 22: Cup Product of Torus & Klein Bottle

  Рет қаралды 2,352

Math at Andrews University

Math at Andrews University

Күн бұрын

Пікірлер: 17
@Helmutandmoshe
@Helmutandmoshe 5 ай бұрын
Is this lecture series continuing soon? I hope so! It has been really great.
@algebraist_24
@algebraist_24 Ай бұрын
I would like to know if the course continues in the autumn semester? I would be very happy with it. It would be nice to go through the Hatcher book.😊
@timelsen2236
@timelsen2236 3 ай бұрын
Thanks to you for explaining such confusing material so well!
@alvarotejedo7868
@alvarotejedo7868 5 ай бұрын
When will next class be available?
@-minushyphen1two379
@-minushyphen1two379 6 ай бұрын
I paused every time you were about to calculate something (the cohomology and cup product on the torus, the same for the Klein bottle in Z coefficients, then with Z2 coefficients), which was a good exercise. This time I actually understood what was going on! (unlike the first time with homology)
@MathatAndrews
@MathatAndrews 6 ай бұрын
Excellent!
@fanalysis6734
@fanalysis6734 Ай бұрын
Maybe there could be a follow up on intersections
@infiniteseries6210
@infiniteseries6210 22 күн бұрын
When will it continue?
@md.mehedihasanrasel9684
@md.mehedihasanrasel9684 3 ай бұрын
Need next lectures sir. Eagerly waiting for that sir.
@-minushyphen1two379
@-minushyphen1two379 6 ай бұрын
When I clicked on this video I thought you were going to multiply the torus and the klein bottle using the cup product, but then I realized it actually meant “evaluating the cup product on the generator cycles of the cohomology groups of the solids”
@xanderlewis
@xanderlewis 4 ай бұрын
Just a quick off-the-cuff comment after seeing cohomology for the first time: since elements of the chain groups are Z-linear combinations of the generators (same thing as maps from the generators to Z), and elements of the cochain groups are homomorphisms from the free groups on the generators into Z (same thing as arbitrary maps from the generators to Z) and the addition operations on each coincide, aren’t they each (at least for Z coefficients) the same? I guess they might be, but the homology can differ because the boundary maps might differ. Also, I guess this has something to do with why the case of cohomology with Z coefficients is a special case and why in the torsion-free case they actually are the same.
@xanderlewis
@xanderlewis 4 ай бұрын
I just realised I’m basically just observing that finite dimensional Z-modules are all isomorphic to their duals. Which is… I guess… a very standard fact.
@Desidarius_Erasmus99
@Desidarius_Erasmus99 6 ай бұрын
Sir I am watching you from India . You have done an extraordinary attempt to help us to overcome fear of algebraic topology . Sir this is my humble request to you please discuss about nets and filters too . This is also pretty confusing .
@ompatel9017
@ompatel9017 6 ай бұрын
Amazing video professor also expecting a course in intersection theory
@md.mehedihasanrasel9684
@md.mehedihasanrasel9684 3 ай бұрын
Next lectures please dear professor
@ikechukwumichael1383
@ikechukwumichael1383 6 ай бұрын
Much Appreciated Sir
@abdelfattahelachab2404
@abdelfattahelachab2404 4 ай бұрын
Please, the name of this teacher
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