Euler's Theorem #7 for Homogeneous Function in Hindi (V.imp) | Engineering Mathematics

[@anandchauhan1206]

7:53 pe n=1 and 11:2 pe dekho sir n= 0 how is it possible ? because both question degree will be 0 then ?

[@ariaaria6104]

there is already a x in multiplication with sin function , so if we go according to rule x to the power 0 will come out and when both x and x to the power zero will be multiplied, the power will be add up and (1+0) = 1 .

[@tejveersingh.__]

Always love your video's sir.. Thanks..👍👍

[@yougetchandan]

sir what if i shift sin inverse to the left side in first question and solve it using the previous method of substitution?? then x and x in the numerator and dinominator cancel each other and I am not getting the answer.

[@damansharma6737]

That isn't possible in this case

[@nainacreationvm5979]

Woh x^0 hoga toh xpartial tanu ka partial x ki respect meh tan constant treat hoga differentiation 0 hoga same y ke case meh hoga but u function h toh partialu/ partialx hoga same y ke sath bhi then xpartialu/ partialx +ypartialu/partialy =nu and n=0

[@banarasi_andaz]

best explanation sir , dout ekdam clear ho ja rha h🙏🏻🙏🏻👍🏻👍🏻

[@MathComMentors]

Thanks for the compliments Bache... Continue to watch Online on KZbin only and share the channel with your friends classmates and Juniors...

[@banarasi_andaz]

Hamre sare frnds apka hi channel dekhte use se padhte h maths Main BCA kr rha hmm

[@EducatorAdarshkumarchandra]

You are very nice teacher Because you teach best ofyour students .. so thanks but I request you sir ji . You solved more questions for practice so you make more videos of questions practice on every topics .. .. I am student from rajkiye engineering callege mainpuri b tech mechanical engineering .. thanks

[@satyamrawat4079]

SIR please tell that what if I shift the sin inverse to the left side in the 1st question and then solve it by the substitution method? Then x of the numerator and denominator gets cancel out by each other and then only y is left. Then the answer is not coming.

[@nainacreationvm5979]

Woh x^0 hoga toh xpartial tanu ka partial x ki respect meh tan constant treat hoga differentiation 0 hoga same y ke case meh hoga but u function h toh partialu/ partialx hoga same y ke sath bhi then xpartialu/ partialx +ypartialu/partialy =nu and n=0

[@Informative229]

Best presentation

[@MathComMentors]

Thanks Dear and Keep watching.. Check the Free Study Material and Store section in my App play.google.com/store/apps/details?id=co.lynde.zmffm

[@vipulbhardwaj1672]

Sir 12th min me jo ques h usme... Pehle qstn me x rais to power 0 lia h kyuki degree zero h ... But second me x raise to power 1 lia h udr b degree zero h explain sir?

[@MathComMentors]

Bache what is ur exact doubt?..

[@MathComMentors]

I m not getting it.

[@kiran23kadali]

Sir how y^2/x

[@anandchauhan1206]

sir aise to fist question ka bi ans 0 hoga ? jaisa ki apne second me btaya then n=0

[@umerbhat7377]

same doubt here ....

[@MathComMentors]

There is extra x in First question... Whose power is 1 so n= 1 in first question

[@Rohitkumar-gn4fp]

1st Q me aapne x¹ liye h, aur sb me x⁰ ye confuse kr rha h sir

[@MathComMentors]

First question main x Diya hua hai.. So x¹ 2nd question main x nahin diya hai so x⁰

[@study-point489]

Good explain sir

[@anbarulhaque4720]

y ka power 2 kaise

[@MathComMentors]

I have taken 3 examples to demonstrate the facts... they r not related to the given question...

[@swetathakur2873]

thank you so much sir ..

[@mahmad8766]

Nice lacture

[@MathComMentors]

Thanks for the feedback Bache... Please share the channel with your friends classmates and Juniors...

[@piyushsharma3612]

Sir can i droubt my dought

[@MathComMentors]

?

[@archanayadavyadav9212]

Sir .6b.ki.sawal.partial.diferential

[@MathComMentors]

Please discuss on WhatsApp bache

[@nandamore5705]

Sir can I whats up my doubt

[@MathComMentors]

Sure .... . please share the channel with ur friends, classmates and Juniors

[@alipopatiya1239]

This Question is getting repeated again and again in IMU CET

[@archanayadavyadav9212]

Bade.size.me.likha.karo.sir

[@MathComMentors]

Thanks for the feedback bache, Will do care in future

[@NeelamYadav-yx1by]

Thanks sir

[@shivamrana2796]

👏👏

[@MathComMentors]

Thanx for the feedback bache... please share the channel with ur friends, classmates and Juniors

[@shivamrana2796]

Yes sir , I did it I have shared this channel with my friends 😁

[@shashank_kishore_]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[@bhartibhalla4540]

👍👍👍👍👑

[@nefcodes]

thank you very much.

[@amanagnihotri6871]

Thank you sir