IIT-JAM 2017 LINEAR ALGEBRA COMPLETE SOLUTION

[@jnvststudy233]

Tysm sir for this amazing video lectures love and respect ❤️🙏 bht acha padhate hai aap ... crystal clear concept 👍

[@shalusharma633]

in question 4 option 1, if X is diagonaizable then its minimal polynomial will consist of linear combinations and unique eigen values.. and hence it will have n independent Eigen vectors which makes basis of R^n.. with dimension n.. if eigen values are not unique then eigen vectors may not have dimension n

[@mathematicalPathshala]

Yes correct, and we have given that X is diagonalizable so if we collect eigenvectors we will have basis.

[@jaydeepnagar5857]

Question 7 sir, whr a column vector, how Rank(a. a^T) = 1

[@mathematicalPathshala]

Rank of AB is less than or equals to rank(A),rank(B)

[@keshavchaturvedi4015]

Rank(AA^T) =rank of A

[@zebaafreen5054]

Sir , 6th ques me ..matrix 4x4 ka hai toh dimension uski 4*4=16 ...hoti na ..

[@mathematicalPathshala]

Look at M like a linear map, it is a linear map from F^4--->F^3

[@ramsinghkuldeep11]

U graet

[@jainishpatel3031]

bhai got no chill in lockdown.. btw nice work bhai👍👍

[@mathematicalPathshala]

Thanx brother😀

[@jainishpatel3031]

@Hudson Shawn we dont care you enjoy hacking your gf intsa😂

[@AtoZ-il4no]

Sir, What are you currently doing PhD or anything else

[@mathematicalPathshala]

Msc

[@AtoZ-il4no]

M(x)=M^2+M+1=0 Operating inv(M) M+I+inv(M)=0 M+In(M)=-I So eigen values are -1,-1,-1.... All Real

[@mathematicalPathshala]

Yes u are correct😀