You should learn this trick!

Watch the video and learn the wonderful method!

[@MrSeezero]

There are 41,977 possible solutions to this equation. a = 0 and a = cos ((2pi)*k/41,976) + i*sin((2pi)*k/41,976) for k = 0 to 41,975.

[@extraanis]

From the De Moivre formula....🤔🧐 🫡😄 There is infinite solutions! There is 20989 principales solutions. A/ 2/41967/=20988. The 20988 ones are only the "principles" modulo 2π. -1 is 10495th ones (if i dont doing an error). 1 is the 1st of course 🎉🎉🎉 B/ 0 is the only null solution. It is the 20989th one.

[@roberttelarket4934]

Obviously by inspection alone a = 0, a = 1 and since the exponents are odd then a = -1. There may be others.

[@romank.6813]

Ну, для начала 54321-12345=41976, а не 31976. А во-вторых, где блять оставшиеся 41974 комплексных корня!?

[@jeanclaude637]

😅

[@RafaelRabinovich]

A = -1, 0, 1

[@jim2376]

0, 1, and -1 all work.

[@dimitriskontoleon6787]

Easy a =1, 0, - 1, and i(and - i)

[@lechiffre5078]

No.

[@ISTP-TCatboy]

-1, 0, 1

[@shanemcinally7092]

thank you 🍌🍌🍌