Energy Mass Relation E = mc^2 | Physics with Professor Matt Anderson | M29-07

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Physics with Professor Matt Anderson

Physics with Professor Matt Anderson

Күн бұрын

Пікірлер: 21
@juniorcyans2988
@juniorcyans2988 Жыл бұрын
So clear so neat, then so easy to understand! I wish I could find theses videos last semester, but perhaps it’s the right time to review now.
@fizixx
@fizixx 2 жыл бұрын
Amazing how things are simplified with a little simple math.
@yoprofmatt
@yoprofmatt 2 жыл бұрын
Agreed. Cheers, Dr. A
@anasbenhmida8350
@anasbenhmida8350 Жыл бұрын
I really appreciate your work sir And I loved your way of teaching ❤❤❤ continue
@garffieldiscool1163
@garffieldiscool1163 2 жыл бұрын
Well exlplained professor. Diametional analysis is powerful mathematical tool.
@yoprofmatt
@yoprofmatt 2 жыл бұрын
Agreed. Glad you're finding these useful. Cheers, Dr. A
@itssherry7551
@itssherry7551 2 жыл бұрын
Amazing explanation sir🙏Thanks a lot
@sonukaushik
@sonukaushik 2 жыл бұрын
Amazing you are in concepting skills n building it... 🙏🍺🍺🍺❤
@yoprofmatt
@yoprofmatt 2 жыл бұрын
Thank you!Love the beer emoji. Cheers! Dr. A
@davidplanet3919
@davidplanet3919 5 ай бұрын
But to derive the energy-momentum-mass equation you need to set p = gamma*m*v and so you can’t set m=0 for a massless particle without also setting p=0. This means E = 0. Massless particles really have there own equation from QM E=h*f=p*c.
@SenneVorsselmans
@SenneVorsselmans 2 жыл бұрын
Albert Einstein initially wrote down the formula as m=E/C^2, basically proving mass = energy/infinity
@yoprofmatt
@yoprofmatt 2 жыл бұрын
Excellent historical reference. Cheers, Dr. A
@3bdul-3ziz38
@3bdul-3ziz38 2 жыл бұрын
Wait a minute P=mv , how it =h/λ or can I say mv=h/λ ?
@BasitKhan-zk3jv
@BasitKhan-zk3jv 2 жыл бұрын
Sir, what is meant by powerful relationship?
@qualquan
@qualquan Жыл бұрын
Making momentum = mass x velocity = massless ghost. (or spirit or soul)
@qualquan
@qualquan Жыл бұрын
Very superficial. Is the Kinetic photon massless? Not made clear. If so then P = momentum = mass x velocity. So how is P "massless"? IOW, how can a product (P) be nonzero if one of its factors (m) is zero? Might as well call P a spirit or a ghost since they are allegedly massless.
@eclipse369.
@eclipse369. 2 жыл бұрын
Photon is a slice of emr wave yes, but the emr wave is not a wave of photons lmao. Photon is man made construct. No Such thing as a photon particle.
@kenlogsdon7095
@kenlogsdon7095 2 жыл бұрын
Yup, "photon" is a transtemporal interaction; there is only ever a full spin "boson" exchanged between two half spin "fermions", with zero distance and zero time between the two in the "boson" lightlike frame.
@hightttech
@hightttech 2 жыл бұрын
This type of discussion is what i love about YT comments 👍.
@yoprofmatt
@yoprofmatt 2 жыл бұрын
Me too. Keep it up! Cheers, Dr. A
@islamisverygood
@islamisverygood 2 жыл бұрын
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