Maximization & Minimization - 1 I Chocolate distribution Concept | LRDI | CAT 2024

[@amyepicduel1320]

Not just students but teachers should also learn from him

[@arnoldterry8689]

Good explanation, still relevant today and this channel is probably the best in terms of content that has been made available to the general public without any paywalls and free of cost. Definitely one of the best, if not THE best teachers out there for CAT. An alternate way to approach minimization problems is to calculate complements. If 91% of the students play Football, then 9% don't play football. Similarly 14% don't play Hockey, 15% don't play Cricket and 10% don't play Badminton. The minimum in this case would be 100-9-15-10-14=52% which is nothing but what was derived in the minimization distribution. I really hope there's a part 2 for maximization constraints (eg. the 70% Badminton case mentioned)

[@nitinparashar8977]

There are many such concepts in the market Sir.. but you have absolutely unleashed them. You take our thinking to different level. You know Sir, I am NIT passout and trust me Sir I am really good at Mathematics and I thought I my Mathematics is brilliant but only till I saw your videos and your Concepts. I am just blown away with your level of Mathematics. Hats Off Sir

[@apoorvavats1151]

I am so grateful to you. You are an angel for people who fear quants and LRDI. Thank you for your efforts, Sir.

[@curiousnawaab383]

a very basic concept explained in an excellent way , cat preparation cannot get more easy than this ,currently I am enrolled in a well reputed coaching bt sometimes they miss very crucial concepts like this ,bcz of which we struggle to practice questions , bt ravi sir is our saviour

[@spegeleisen]

how did your CAT end up going? how are you doing now?

[@MsRohitshaw]

if only i had found this channel 6 months ago. i'd be aiming for 99.5+ Percentile this Year.

[@ansumanrath4378]

Yes bro, I regret it now.

[@MsRohitshaw]

@@ansumanrath4378 Koi naa bro. Ho jayega iss saal. 😅 All the best.

[@ashishakatsuki137]

Explain this using chocolate distribution In a college each of 200 students in class is a member of at least one of the three clubs A,B,C .80 students are member of A , 90 students of B, and 100 students are member of C. Q. If 25 students are members of only A then maximum no of persons who are members of all three clubs?

[@siddhantpandey4154]

@@ashishakatsuki137 35?

[@dhruvgirotra637]

@@ashishakatsuki137 15

[@qwertykumr6848]

Thankyou Sir for such an amazing explanation!!!! I wish I had a teacher like u in my school days so that I won't have hated Mathematics this much!!! Keep making more videos for us it really helps!!!

[@shwetaraj7477]

seriously.

[@nitinparashar8977]

Ek hi Dil hai Sir, kitni baar jeetoge

[@hemantfuleriya7858]

A still better analogy is that which can be derived from the context, for example: In the question discussed above we can ask all the students to surrender their sports kit, to be redistributed so as to maximize/minimize number of students who play all 4 sports. chocolate concept sometimes confuses me. just a thought.

[@Rodha]

We have done lot of difficult sets in class, so its not confusing. I will upload few sets here also.

[@truptinarkhede4850]

@@Rodha sir please upload as soon as possible as i am facing a lot of difficulty solving these sets :)

[@amishamaheshwari2107]

No better way could anyone explain concepts as effortlessly and amazingly as you do sir. Have recommended your channel to my friends too. They all were in awe of you. Thank you sir. ❤️❤️❤️🙏🙏

[@angeshkumar3064]

Have you completed your mba

[@vinaykapil1413]

I watched 4 videos to get a concept which is easy and is accepted logically in my thought process

[@mayankojha1]

I'm solving all your questions on this channel after completing your DILR courses in recorded form. Thanks, sir.

[@ayushmishra3283]

How is your prep going .I am also going to give CAT 2023

[@prathameshjadhav7008]

I have a doubt, in case of finding the minimum number, you first gave one chocolate to each, as per the condition, then 3 chocolates to max possible number, then why can we give 2 chocolates as well, and then see what number of 4 chocolates have to be given ? basically give one--> give 3--> give 2--> then cherck for 4??

[@mayapunj9555]

Sir where are the videos of clock, blood relation , direction based questions and networking .

[@a.nachyuth8672]

Sir your explanation is amazing.. Keep it up 😀

[@raghavrohilla8241]

Sir thankyou for such valuable and easy to understand lessons🙏🏻🙌🏻

[@shristisingh2909]

Great Concept!!

[@shiny5336]

Thank you sir for explaining !!

[@yashborse5769]

Superb concept Ravi sir.

[@roshanmanduri3490]

Now i'm craving for chocolate.

[@karnamharini3770]

wonderful classes

[@suryavoroy3527]

very nice concept,sir!

[@manroopsingh3230]

Nice concept explained

[@D_Jain]

Thanks for the video

[@hritikkumar6746]

Thanku sir:)

[@hiteshahlawat4886]

Thankyou for making this video ❤️

[@sakshammehra7367]

Thank You Sir

[@anirudhdalvi3569]

What is thr order of these videos? Its all haywire

[@animecraze2304]

thank you sir🙏

[@singhanki-98]

Superb concept sir😊

[@shivankkumar5191]

Nice explanation ❤💯

[@harikavolam7123]

if 91% play foot ball, 86% play hockey,85% play cricket,90% play badminton. why Cant we take min(91,86,85,90) i.e 85 as max number of people who play all 4 sports?. please answer

[@priyanshisingh9112]

Damn same doubt...

[@Masseytractorsdsr]

because all student play atleast 1sport

[@ramradhakrishnan2351]

@@Masseytractorsdsr what do you mean "Bcz everyone plays atleast 1 game" For that we already given 1 chocolate to all But condition is given that only 85% of students play cricket Then how can more than 85% ppl can play all 4 sports 🤔 #kuch_bhi

[@Masseytractorsdsr]

@@ramradhakrishnan2351 there were total of 352chocolates to be distributes if i give 100 that is 1to each student i will be left with 252. hope till here u have no problem. Now to maximize 4chocolates of which 1 we have already distributed to everyone we can now give 3more to each person. so we were left with 252 students so 252divide by 3 gives 84. I Hope u got it. if u have any doubt feel free to ask here.

[@ramradhakrishnan2351]

@@Masseytractorsdsr I'm soo sorry i thought 85% se jyada aa gya hai all 4 sports khelne walo ki value so i thought ki it's violating the condition but it's 84 totally fine Sorry

[@sumittawani]

A market research group conducted a survey of 1000 consumers and reported that 720 consumers liked product A and 450 liked product B. What is the least number of consumers that must have liked both products? Key in the value how we will aply this method into this problem ?

[@bidyutparnamitra3287]

Here, the number of chocolates = 720 + 450 = 1170 to be divided among 1000 people. To minimize the number of people getting two chocolates each we will have to maximize the number of people getting one chocolate each. So we will give one chocolate to everyone, ie, 1000 chocolates are given. We are left with 170 chocolates. Now each person has one chocolate each and we are left with 170 chocolates. These 170 chocolates will be given to 170 people. So the minimum number of people liking both products is 170.

[@hrishavranjan4797]

7:56 should we not worry abt type of chocolate? what if 2 football chocolates are given to same guy

[@ayushkumar7497]

thanku sir

[@apurvutkarsh2520]

best teacher ever

[@vagrant.lifelogue]

thank you sir :)

[@rushikeshpatil2922]

SUPERB ....

[@pranavkottappurath6806]

[@Konn_hai]

Done 👍🏻 26 September 2024

[@bhaskarbawaly8515]

1 small doubt, as I know I am wrong, but struggling to find out the exact logic or the language that why we can't we make the minimum of 4 chocolate people zero(0)?

[@smurbbehera4099]

Because it's a condition that everyone one should have atleast 1 chocolate

[@arnabdas1994]

How to calculate if badminton was played by 70 percent and rest data were same?

[@top5world786]

cant we use venn diagrams equations here

[@ankeshsingh2576]

No, we don not know the intersection parts

[@AnshuKumar-oj8ww]

@Top 5 world yes we can

[@mollyagarwal7051]

For minimum chocolates why can't it be 26 people? As 251/2= 126 people but only 100 are there. So the remaining 26 people will get 4 chocolates

[@prashant5974]

OMG, dear..... 252/2 i.e 126 pairs of chocolates to be distributed now, 100 will get 2-2 each so every one have 3 each. Now we are left with 26 pairs (52) chocolates. Now one person can get max of 4 chocolates ( aa only 4 sports) and they already get 3 each. So you have to give 52 ( 26 pairs) to 52 individual and 52 people will get 4 chocolates i.e they will play all 4 sports.

[@thebirdwatcher8198]

I have a doubt sir, how we can able to identify whether this question is able to solve by Venn diagram method or chocolate distribution method? Pls explain

[@himanshujoshi4023]

Sir, thanks for the video. I have a query. What if the question asked about max/min no. Of students playing exactly 2 games? Thanks in advance.

[@ankeshsingh2576]

Total chocolates=352 Total student =100, each student should get 1: chcolates left: 252: Now each has one chocolate, to maximise 2 : out of 252 chocolae we can give one more choclates to every student, so maximum no of students who can get exactly 2 will be 100. to find minimum number of students with exactly 2 chocolates we need to maximise students getting 4 chocolates, because after wards chocolates left for further distrubution will be lesser if we maximise students with 3 chocolates, solution: each student has 2 chocolates and we have 152 chocolates left, lets distribute 2 more chocolates among students : 152/2=76 so 76 students wil have 4 chococlates and 24 will have two chocolates exactly

[@nikitadas9671]

Min students playing exactly 2 sports= 0 Max. students playing 2 sports = 24

[@crackingcat1975]

@@ankeshsingh2576 for max case: we get 100 as answer but no sports has 100% students playing it, max % among them is 91% , so shouldnt max students playing exactly two sports should be 91?? and for MIn case: why 152/2 it should be 252/3 to maximise the 4 sports playing students. thus making max=84(lecture que also verifies it) and min=16

[@dineshkumarpanda7287]

i have a doubt as we have 352 chocolates to distribute among 100 people and max no of people should receive 4 chocolates, then can't we directly divide 352/4=88

[@mehakkaur4306]

No because the condition is that each st. Has to get atleast one chocolate as everyone plays atleast 1 game

[@ishasingh4736]

why does the maximum concept differ in this and the chocolate distribution(2) video, there it says we have to look if the number we have got is the greatest , if not then to do the process differently , but here you say that we have to see if we have least number of chocolates? i am confused

[@anishmoney01]

Sir shouldn't the maximum students playing be 50 As only 50 are playing hockey and at max only this can be the value of students playing all 4 sports

[@devanshvarshney9061]

It’s given in the percentage, not in any exact integer value. There is nowhere mentioned 50 play hockey. There is written 86%

[@vidhirotliwala687]

Sir if we remove this condition that all students play atleast one sport, how can we find minimum or maximum number of students who DIDN'T play any sport?

[@prathmeshvayal]

Then u have to solve it by venn diagram

[@CAT-nj1ue]

How to solve this question in 4set Venn diagram?? Anyone explain

[@abhinavkumar-qg6lj]

What will be the answer in case of maximum if only 70% people play badminton?

[@swatingle]

Can anybody please help me with this question..I am not able to solve it using the chocolate distribution method. 100 people are surveyed. 60 likes tea 70 likes cold drink 80 likes coffee Find the minimum and maximum number of people who like exactly 2 drink.

[@sreyashroutray811]

100 Students ---- 210 Chocolates Assuming atleast one chocolate with every student, any student can possess 1 or 2 or 3 chocolates Minimum Case: 1st transaction : 210 - 100 = 110 ( Each given 1) From the remaining 110 , give 2 to 55 students Therefore = (55*3)+ (45*1)= 210 , i.e 55 student with 3 chocolates each and 45 students with 1 chocolate each. Min : 0 Maximum Case: 1st transaction : 210 - 100 = 110 ( Each given 1) From the remaining 110 , give 1 more to every 100 students 110-100 = 10 Now all the 100 students have exactly 2 chocolates each. But we still have 10 more to go. Out of 100 students, 10 will get one more 100-10 =90 Therefore = (90*2)+ (10*3)= 210 , i.e 90 student with 2 chocolates each and 10 students with 3 chocolates each. Max:90 Hope this helps, Cheers !!

[@vartikabaranwal7310]

🔥🔥🔥

[@himanshu0921]

🙏🙏

[@vishalvaibhav3764]

I think max 85 choclates

[@ramradhakrishnan2351]

Yes sir... Are you sure??

[@SahilRamola]

Nope 84

[@AnshuKumar-oj8ww]

Then max students cant be 100 but lower.. 85 + 1 (from 86) + 5(from 90)+ 6 (from 91) = 96 only

[@kishoregiri5957]

i also think 85

[@kishoregiri5957]

please reply why it can't be 85

[@sakshianand873]

3 chocolate kaise leliye

[@allthingsb2b]

In some sets like in lrdi, where can we apply chocolate distribution concept and where can we get answer through equations ?

[@alok1937]

I am getting 81 as max students

[@ashishakatsuki137]

Can someone explain this question using chocolate distribution strategy ? In a college each of 200 students in class is a member of at least one of the three clubs A,B,C .80 students are member of A , 90 students of B, and 100 students are member of C. Q. If 25 students are members of only A then maximum no of persons who are members of all three clubs?

[@SahilRamola]

Please listen to sir carefully. In the beginning only sir said, signs for applying Chocolate distribution are 1. Maximum Minimum should be asked in question. 2. There should be overlapping situations and there should be no details given about students playing any 2 or other permutations. So , the question you posted can be done using Venn Diagram

[@kashyapparihar4681]

Is 40 your answer?

[@honestreviews5349]

Is 55 the answer

[@karthicprakash8277]

@@honestreviews5349 yes its the answer👍

[@himanshubarnwal934]

why cant maximum students be 85 ?, as 85 students who are playing cricket the very same student can play football, hockey and badminton.

[@Amar_2300]

you are right bro

[@rashikarkoon2721]

Same doubt

[@mradulkanskar23]

Bhai esa isliye nahi hoga because condition di hai ki every student plays atleast 1sport , agar hum 85 ans denge toh yeh condition fulfill nhi ho payegi

[@nikhilprajapati41]

HOW CAN YOU TAKE 100 STUDENTS KINDLY EXPLAIN

[@navyanarayan1624]

Because percentage is given. 100 students = 100% students. And 84 % and 52% is the answer.

[@hridiaramesh]

❤

[@aadyamishra404]

ughh this is confusing

[@shiny5336]

It is simple and explained very well. First thing is to satisfy condition that every student will have 1 sport 100 students -> 352 sports calculated 352 - 100 = 252 Now in case of maximum, Hume zyada se zyada logo ko distribute karna haina toh 252 ÷ 3 (100 student already have 1 sport allocated to them) Max = 84 In case of minimum, same ke pass 1 sport hai , toh ab 2 de do 100 *2 252 - 200 = 52 Ab yeh 52 students ko 4 sports Dena hi hoga coz woh excess hai I hope it helps😊

[@letstrytolearn5318]

Sir please language more than batter rhega aap hindi me sirf smjana concept clear and no doubt so you are request only used for the hindi language used

[@myronp5764]

U r studying for cat ....study in English only

[@SahilRamola]

No, we're more comfortable with english teaching.