May 2022 SAT Math (Calculator): Explained by a Perfect Scorer (Must Know SAT Hacks and Strategies)

[@preppros]

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[@ashatefriedrice8876]

I’m 3 minutes from taking it, you made me a lot more confident thank you🙏

[@MarkLewis-dz8pp]

Just got your book; best I've seen; great job guys!

[@preppros]

Thanks!

[@cmken8643]

omg, thank you so much, I was going to buy a course that explains it, but you offer it for free. Thank you!!

[@preppros]

Glad it was helpful!

[@HJT55]

29:23 Did you really need to convert everything to inches? I solved it more easily by writing 4/9 = x/(12y)

[@preppros]

Nope, that works! I just slightly misinterpreted the question on first seeing it and added an unnecessary step.

[@asadsaleem]

Q 25 at 24:52 how is (x - 5 )^2 is equal to (x - 10x ) please explain I'm really confused

[@preppros]

Hi Asad, It's not. I'd rewatch that portion of the video; I think you just missed the +25. I expand (x-5)^2 to x^2-10x+25. If you go back to 24:30, you will see this. Hope this helps!

[@asadsaleem]

@@preppros i saw that my question was (x-5)^2 expanded is ( x-10+25) from where does that 10x come from? X^2 is same 5^2 is 25 from where does that 10x came from? It's what that's confusing me . It will mean alot if you can explain it simply thank you

[@preppros]

@@asadsaleem This is a common algebra mistake. You cannot just square both terms. (x-5)^2 can be written as (x-5)(x-5). Hopefully this helps you see that we are multiplying two binomials here, so we need to multiply it out using FOIL (First, Outers, Inners, Lasts) or using the commonly taught box method. Using Foil, we get x^2 - 5x - 5x + 25. When we combine the like terms, we get the 10x in the middle. Hope that clears it up!

[@asadsaleem]

@@preppros thank you this is very clear means alot ❤️

[@annabela7953]

how does A have less standard deviation than B in question number 28, isn't it farther to the mean compared to B?... plsss someone explain

[@preppros]

Hi Annabel, check out this video where I go back through standard deviation in a bit more depth kzbin.info/www/bejne/bmeviqRtqspgf6M This should help you understand the concept better!

[@annabela7953]

@@preppros thanks a lot :)

[@luluayed9755]

For Question 36, which chapter can I refer back to study that content?

[@preppros]

Shapes. The main concept you want to recognize here is that if you are solving for distances, it’s always a great idea to look to create right triangles to let you solve for missing lengths.

[@amycao5419]

For #36 on the calculator section, how do you know the triangle is a right triangle?

[@preppros]

Good question! When you draw the triangles, we know that the 2 sides that OW and OY are radii, so they must have the same length. Since these two sides are the same length, we create an isosceles triangle, so the angles at W and Y must also be equal. We are told that WY is bisected so WZ = ZY. Using SAS (side-angle-side), we can tell the two triangles must be congruent. If the 2 triangles are congruent, the 2 angles in the must both be 90 degrees. The easier way to do this is to just know that any chord, which is a fancy math term for a line through a circle like WY in this question, that is bisected by a diameter of a circle creates a perpendicular bisector so the angles are always 90 degrees.

[@joshsingh1294]

Perfect!

[@bayan_gazmouz4205]

How is 3 less than 7 in number 17🤨

[@preppros]

Whoops! 3 is indeed less than 7. However, if you plug into the 2nd equation, you get 3 is less than or equal to 2, which is incorrect, so you can tell that A is incorrect.

[@mathlearning2947]

thanks

[@preppros]

You're welcome!

[@TheMalignoGames]

the 19 sucks. The question had to say that we have to start in Monday not in Sunday

[@preppros]

This is the common way the SAT sets up Median problems. To find the median you have to order your list of numbers from lowest to highest; to make your life a little more difficult the SAT will rarely ever give the numbers in order from lowest to highest so it's something to always watch out for and often the first step you should take to solve median problems.