Thank you, I had no idea that we are allowed to start from the back
@ShawAditya Жыл бұрын
Great explanation!
@ex0rrr Жыл бұрын
Wonderful lecture! Just a small doubt, in the case of all 1's should we consider MSB as 0?
@-shoya-ishida-3 ай бұрын
thank you
@unkonw9621 Жыл бұрын
love it !
@prashantdubey99844 ай бұрын
Sir we can also draw the mealy m/c using the 2 states .
@UroosaIftikhar5 ай бұрын
Hello sir! all of your vedios are good but i have a question if only input string is given like 101111000011 and the examiner says find the output but we dont have any state stable or state diagram than what's the procedure of finding the output.
@itskaur6938 Жыл бұрын
What if there are four one's??
@Mahanth. Жыл бұрын
make ALL 0 left to right imagine MSB as 0 make it 1 => 10000 (16, which is true for 1111[15] + 1(0) ) we always treat 1 trailling zero for SUM, and n trailling zeroes for MUL in for worst case ( and in Registers extra bits are discarded)
@kunalpatil42454 ай бұрын
take input as 01111 and proceed ,
@XYZ-w8bАй бұрын
cause in computer system 2's complement representation is used and when we have binary number like 111 (it is having the value -1) and when we use mealy machine or moore machine will get 000 so it is right which means -1 + 1 = 0 111 (which is -1) + 1 = 000 (which is 0)
@tusharmahajan-ng2ch11 ай бұрын
what if the input is 1 then how the output will be 10?
@namankatiyarkurmi75992 ай бұрын
what if binary number is 111 by this it is converted to 000 but in realty it should be 1000
@XYZ-w8bАй бұрын
cause in computer system 2's complement representation is used and when we have binary number like 111 (it is having the value -1) and when we use mealy machine or moore machine will get 000 so it is right which means -1 + 1 = 0 111 (which is -1) + 1 = 000 (which is 0)