Measuring Inductance with A Pulse and Oscilloscope

  Рет қаралды 36,795

ElecTechie

ElecTechie

Күн бұрын

Пікірлер: 48
@kennethstover4427
@kennethstover4427 2 жыл бұрын
I am fascinated by your use of a pulse. I’m definitely going to try this. I’ve written a program in Fortran to find the needed unknowns and would be happy to share it.
@GaryMcKinnonUFO
@GaryMcKinnonUFO 2 жыл бұрын
Fortran! I thought that had gone the way of Latin ;+}
@ik5hgl
@ik5hgl Жыл бұрын
I've been programming in Fortran since 1975 and it's been a long time since I've heard from someone who still used it who wrote, bravo👍
@martinkuliza
@martinkuliza 7 ай бұрын
well i have absolute respect for FORTRAN, i however have a humble spreadsheet in Excel that i'm happy to share with anyone........... Obviously after the Fortran option is exhausted and purely as a last resort :P
@kennethstover4427
@kennethstover4427 7 ай бұрын
@@martinkuliza I can see where Excel would work very well for this task.
@martinkuliza
@martinkuliza 7 ай бұрын
@@kennethstover4427 Indeed. i reduces a perhaps 15 minutes of calculation to finding the value of the inductor to perhaps (Considering you need to user cursors on the scope to get the frequency) Perhaps it reduces the time down to say 10 or 15 secods per inductor. Now when you have 5 inductor it doesn't really matter, when you however need to go through a bucket of 200 or so that you need to test, it matters quite a lot, it can be the difference between taking 1 week to go through it vs perhaps 1 to 2 hours. I say a person should do it manually a few times first so as to not get lazy , but once you do say 10, it's ok to do the other 190 with a spreadsheet because the spreadsheet gets the formulae in your head
@paulh0029
@paulh0029 4 жыл бұрын
You can also calculate the Q of the inductor. By counting how many Cycles it Goes down to 0.707 of the Peak voltage Times 4.53
@calculatingcapibara2914
@calculatingcapibara2914 2 жыл бұрын
This will be difficult, as the 56 pF in serie with the 50 ohms output of the pulgenerator will affect the Q seriously, I expect. Even the ringing frequency is affected by the dempening, although I do not expect that to be of great effect.
@kiminowazzz
@kiminowazzz Жыл бұрын
Thanks for the details!
@ElecTechie
@ElecTechie Жыл бұрын
You bet!
@hamimadiamla
@hamimadiamla Жыл бұрын
Thanks for your videos, interesting
@ElecTechie
@ElecTechie Жыл бұрын
Glad you like them!
@christineelnas1514
@christineelnas1514 Жыл бұрын
I 've learned a lot
@j.phillips4810
@j.phillips4810 9 жыл бұрын
Very nice clean demo N2CUA. I especially like the theory intro and conclusion. AK4GG
@ElecTechie
@ElecTechie 9 жыл бұрын
+J. Phillips Thanks
@GaryMcKinnonUFO
@GaryMcKinnonUFO 2 жыл бұрын
Thanks for the detail.
@jellymaecanete
@jellymaecanete Жыл бұрын
I didn't understand it that well because its so hard but nice video mister
@ElecTechie
@ElecTechie Жыл бұрын
Thanks
@calculatingcapibara2914
@calculatingcapibara2914 2 жыл бұрын
Thanks for the video. Did you account for the presence of the 56 pF? I guess the L will be roughly 15 % lower than given here.
@itsm.eraa08
@itsm.eraa08 Жыл бұрын
Amazing!🙌
@ElecTechie
@ElecTechie Жыл бұрын
Thank you 🙌
@domingacanumay6026
@domingacanumay6026 Жыл бұрын
So nice☺️
@ElecTechie
@ElecTechie Жыл бұрын
Thanks 😊
@alfredkennedy816
@alfredkennedy816 Жыл бұрын
How do you maximize the time that the inductor takes to establish a field and the time that it takes to discharge in order to repeat immediately to eliminate the short circuit?
@martinkuliza
@martinkuliza 7 ай бұрын
You feed a rectangle wave into it and modify the duty cycle. so where a square wave would be 50% Duty cycle, Try putting your function gen on Rectangle Wave, 1KHz and put it on like 5% Duty cycle, but then in certain inductors that rings will over lap, so you'll need to use between 8% - 12% or maybe 10% Duty Cycle, Have a play around with the Duty cycle, that's your answer Note : on a rigol this waveform is not called Rectangle, even though it should be, it's called PULSE
@markalinz9639
@markalinz9639 Жыл бұрын
nice memo mister😍
@hubercats
@hubercats 4 жыл бұрын
Thank you for this instructive video. Can you explain in a bit more depth why the 56 pF cap is needed? And does it not interact with the other components to shift the resonance frequency?
@calculatingcapibara2914
@calculatingcapibara2914 2 жыл бұрын
The 56 pF is just a way to insert the excitation into the tank circuit. I expect however that this method will seriously affect the ringing frequency. I would like to see the result when using a straight resistor, much larger than the impedance of the tank components. Say 10 Kohms. I addition, I wonder how accurate the 290 pF is. It is a major factor to the accuracy here.
@ovidius2000
@ovidius2000 Жыл бұрын
anInductorWithIronCoreHasVariableInductance,DependentOnTheCurrentItCirculates?IfTheCurrentItsHigherTheInductanceLowersBecauseIronCoreSaturates?
@jadeplayyz
@jadeplayyz Жыл бұрын
New subscriber, Jade T. Banguis
@ElecTechie
@ElecTechie Жыл бұрын
Welcome aboard!
@martinkuliza
@martinkuliza 7 ай бұрын
IF ANYONE NEEDS HELP PUTTING THIS CIRCUIT TOGETHER, it's actually pretty easy, and i'm happy to help you, Let me know
@angelmaepadayogdog4690
@angelmaepadayogdog4690 Жыл бұрын
Ma'am si Angel Mae D. Padayogdog ni ma'am
@z08840
@z08840 2 жыл бұрын
waveform is "clean", but it's a mix of generator frequencies and tank circuit - the only "truly clean" form is a continuous sine with a constant amplitude - and amplitude of yours is not constant - and it's a result of mixing generator's and tank's frequencies and because of above you can't judge tank's frequency from max signal of spectrum - it has nothing to do with probes' setting - probe should be properly compensated with that variable capacitor on your oscilloscope schematics - resonant frequency shouldn't shift with properly compensated probe - only uncompensated probe will benefit in this regard
@calculatingcapibara2914
@calculatingcapibara2914 2 жыл бұрын
I am afraid you are mixing up the transfer function of a well adjusted probe with the load thatvany probe will always have on the circuit under test.
@calculatingcapibara2914
@calculatingcapibara2914 2 жыл бұрын
... that any probe will...
@ElecTechie
@ElecTechie Жыл бұрын
You have to realize the amplitude is not constant because it is being pulse which is also not constant
@martinkuliza
@martinkuliza 7 ай бұрын
No mate, Probes are relevant , You try this say on 10x Probe setting but your probe is on say 1X , You're going to have a problem, or if both probes are on 10X for example. the probe coming from the Siggen is going to be 1X, the probe going into the scope needs to be 10X if you don't do that, you'll get a shit signal Also, A Constant AC is not going to do the job as what we are trying to do is ring out the inductor for it's resonant frequency, AC is not going to reveal that
@martinkuliza
@martinkuliza 7 ай бұрын
@@calculatingcapibara2914 You didn't have to do that, You just go into your comment with the 3 dots on the side and select EDIT and change it
@AshleyfajardoFajardo
@AshleyfajardoFajardo Жыл бұрын
Hi maam ashley c. Fajardo cypress
@TheMorpheus017
@TheMorpheus017 7 жыл бұрын
are you w2aew bother? :D
@ElecTechie
@ElecTechie 7 жыл бұрын
No, but thanks .. thats one of the nicest things anyone has ever commented
@RSuarez66
@RSuarez66 4 жыл бұрын
He does sound like w2aew.
@francislusing7754
@francislusing7754 Жыл бұрын
Its very hard to do
@martinkuliza
@martinkuliza 7 ай бұрын
Not really
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