Mesh Analysis with Supermesh | Solving for i1, i2, and i3

Mesh Analysis with Supermesh | Solving for i1, i2, and i3

[@Electrical-Engineering-Notes]

*Mesh Analysis Playlist* : kzbin.info/aero/PLQLdKyBqWCjqJmPraFRLutDh2nG9TfDUh

[@Electrical-Engineering-Notes]

Thevenin’s Theorem kzbin.info/aero/PLQLdKyBqWCjptDMyRIJ79rbAV4K6t30gh&si=emZb0_VpQnjcbVCx Superposition Theorem kzbin.info/aero/PLQLdKyBqWCjrzVapyz49z3qVsW5XSMA7P&si=GWLjn0yziBpH-iEr Source Transformation kzbin.info/aero/PLQLdKyBqWCjoFv91tOfyc_2Cqv9CvPFis&si=QPmhd6GmKnodQb0h Mesh Analysis kzbin.info/aero/PLQLdKyBqWCjqJmPraFRLutDh2nG9TfDUh&si=ExL7Y3jO0VV44giC Nodal Analysis kzbin.info/aero/PLQLdKyBqWCjqB2LEk7PYLx7vImC0BdLBO&si=n6SAFbUA0n1vGv81

[@Electrical-Engineering-Notes]

Sinusoids and Phasors kzbin.info/aero/PLQLdKyBqWCjqN64a474ynXxGELinfxWT4 Thevenin’s Theorem | Sinusoidal Steady-State Analysis kzbin.info/aero/PLQLdKyBqWCjoeagQpyk9BiPjH6yyAOjpo Nodal Analysis | Sinusoidal Steady-State Analysis kzbin.info/aero/PLQLdKyBqWCjo-bSF5ZHgv0wtnw2ZANJID Sinusoids kzbin.info/aero/PLQLdKyBqWCjrZPpDbUBjXnyaMnFKfCM4h Two Port Network kzbin.info/aero/PLQLdKyBqWCjrZYNs7ni2BRZm133ljYn-y&si=4wHR9VyXt4N99Plg Impedance Parameters kzbin.info/aero/PLQLdKyBqWCjoarKwT_f87o5h29ylLeIQy&si=Dsh4OOH2qhQ_3Wz5 Impedance and Admittance kzbin.info/aero/PLQLdKyBqWCjpabLO97-Q_lfXigABp1W9a&si=64QeDDPGA1-eZGZN Impedance Combinations kzbin.info/aero/PLQLdKyBqWCjq-2fjpsMd_9pr17ThoXT8q&si=YudOV8aNlUBWstzt Equivalent Impedance kzbin.info/aero/PLQLdKyBqWCjo4kLUwxELT3AlXxWA5omFi&si=HjnycQliAqw7Kstl Impedance kzbin.info/aero/PLQLdKyBqWCjrgbj8jXdDFhazZ3QVja2Jl&si=z9VfDDFGN6Uf3304

[@Electrical-Engineering-Notes]

Multiple Choice Questions (MCQ) : kzbin.info/aero/PLQLdKyBqWCjoxOSibfv6vXba6O3wke5Qt&si=RAqbT8f50pIW8Ycc

[@Electrical-Engineering-Notes]

Install the app : play.google.com/store/apps/details?id=electrical.electronics.engineering

[@Electrical-Engineering-Notes]

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[@aminhazem4553]

Thank you sooo much

[@nihadhossain8404]

thanks

[@ramasamyjegadeesan4327]

The calculator is what type.Is it real or an app ,pl reply

[@Smile_TV1]

Why didn't you use the 1ohm resistor below the current source?

[@hylexsenpai5282]

all branch elements will be neglected (current source and resistors that are in the branch) when we write supermesh equation

[@parthdeshpande8019]

because If there is any resistor connected in series with a Current Source it is neglected...So In Conclusion that 1Ω Resistor will not affect the circuit. so We can remove it

[@parameshdruthik]

tq sir

[@miriamabaleimatuku8278]

There is a 1ohm resistor in between as well, so its not a Supermesh

[@parthdeshpande8019]

It is ..because If there is any resistor connected in series with a Current Source it is neglected...So In Conclusion that 1Ω Resistor will not affect the circuit. so We can remove it

[@siddharthalladdinedits7905]

Sir in the equation why we should not take 4[i3-i2]why its only 4[i2-i3]??

[@saplays9289]

Because we are moving in direction of i2 so considering it more larger than i3

[@thanujasekuri4557]

Bro that 10i3 in 2nd equa6

[@ramprasadmandal2908]

❤

[@SheEngineer]

You missed the one ohm resistor

[@vivek_sankath]

no he didnt missed it actually reduced from circuit as any resistor in series with current source is not considered

[@avinashkryadav5690]

In equation 1 how it should be -6

[@shiblihassan4269]

- voltage drop so -6

[@Thrla007]

Bro onu purilaaa 😂 ne exam panuva nu patha ne ena bro apdiye padichitu erukaa 😂

[@LightEnergyy]

i1-i2=3 no?

[@gwgodson696]

After that you have to substitute I1 in other 2 equations. You can get answers ..

[@ahmedjubyer9670]

yamete kudasaiiii 😢

[@aqilaiman2030]

Why didn't you use the 1ohm resistor below the current source?

[@aqilaiman2030]

is it because the resistor is in inner loop?

[@hylexsenpai5282]

all branch elements will be neglected (current source and resistors that are in the branch) when we write supermesh equation

[@aqilaiman2030]

@@hylexsenpai5282 ok, thank you. noted

[@avinashkryadav5690]

In equation 1 how it should be -6

[@mdmozammilhusain5600]

Because current flow negative to positive