3.6 Basic Theory of Radiative Transitions

[@darrenho3655]

Thank you so much for explaining this in a clear intuitive manner - super helpful for someone being introduced to the field of optics

[@jacobvandijk6525]

@ 4:26 I don't see what the displacement of one electron has to do with a dipole. Yes, sometimes the charge is here, and sometimes it is there. But a dipole is a unit consisting of charges in two places at the same time! No displacement is needed to have a dipole. Just look at the HCl-molecule. So something isn't right here (no matter how nice these moving pictures from Wikipedia are, haha). By the way, an accelerating electron is a source of EM-radiation on its own. P.S. Again, your math is okay, Michael, but your physics isn't on the same level. That's why you became a chemist.

[@j.kon1201]

Thank you for this video! Truly helpful.

[@lyuan1513]

thank you for the video, was really helpful

[@lincolnford2229]

Thanks for the lectures.

[@RonaldStrange-x1o]

Thank you for the clear explanation. Could you explain how the oscillator strength can be obtained from vibrational peaks in the infrared? Is that similar and what about rotational satellites?

[@renn4489]

Great lecture Can you answer a question regarding it?

[@mevansthechemist]

Certainly, fire away!

[@renn4489]

@@mevansthechemist as I read the intensity of a transition is equal to the matrix element of dipole moment(transition dipole moment) squared. And was wondering why it's so and how it's connected to the selection rule and the vector r you discussed Is that also true, that knowing transition dipole moment we can reconstruct the spectrum ?