Google Coding Question - Long Pressed Name (Two Pointers Approach)

[@sudharsansathiamoorthy3958]

Excellent explanation Micheal!! Keep up the good work!!

[@AlgosWithMichael]

Thank you, I appreciate it!

[@shankarsampath303]

Fantastic explanation. Thank you

[@vk4081]

Your explanation is too good. Keep doing more videos

[@AlgosWithMichael]

I'm glad they are helpful, thanks for watching!

[@luobohu8128]

Thank you for your video. It's so clear and intuitive!!! keep doing it bro!!!

[@AlgosWithMichael]

Glad you liked it!

[@MrSumitsharma786]

Hey michael how about doing this with single loop public boolean isLongPressedName(String name, String typed) { char ch1[]= name.toCharArray(); char ch2[]= typed.toCharArray(); int j=0,i=0; while(jch2.length) return false; if(i=0 && ch1[i-1]==ch2[j]) j++; else return false; } if(i

[@dragonnbyte]

Excellent explanation Muinos !! Thank you so much :)

[@dragonnbyte]

Subscriber++;

[@AlgosWithMichael]

Thank you so much!

[@AlgosWithMichael]

appreciation++;

[@tuanho4641]

Your explanation is really helpd. Please make more videos.

[@AlgosWithMichael]

Awesome, glad I could help!

[@geetusharma3923]

Very nice explanation . Keep it up. Thank you so much for adding valuable content ❤️ 😊

[@AlgosWithMichael]

Of course, thanks for watching!

[@ramkiran3685]

Hi Michael. I liked your videos' I want to pay but unable to do so. Can you please check the latest RBI guide lines from India and modify at your need ?

[@code7434]

thanks brother

[@AlgosWithMichael]

No problem man!

[@manelzerah]

this problem is easy type on leetcode, jesus... im fckd up

[@manelzerah]

thanks for the explanation tho