How to calculate miller indices of planes and directions in a crystal structure
Пікірлер: 41
@JohnDoe-eo8gi2 жыл бұрын
10 years of helping people solve Material Science problems. Thank you!
@Trikkie879 жыл бұрын
You sir, have some love and cookies and chocolate and all that is good in life. Where i couldnt for the love get it by the books explanation, after watching this tutorial 1 time im suddenly a miller indices expert. #faithinmaterialsciencesrestored
@Snagoot Жыл бұрын
this is literally the same 2 questions i have for my first assessment. thank you
@reignofhope10 жыл бұрын
and it's official, I not only don't care about school anymore, I actively resent it.
@claramelb74765 жыл бұрын
Hahahahaha I feel you!
@beowulf20s11 жыл бұрын
Wonderful explanation. I have not seen this procedure explained better.
@Korppuli11 жыл бұрын
Wow, I solved my homework thanks to this video. THANK YOU!
@AraujoMatt12 жыл бұрын
For crystal planes we consider all parallel planes to have the same indices. If a plane intersects the origin, it is more simple to calculate the indices of the plane by either translating it from the origin or choosing a different coordinate system. This way we avoid calculating a normal vector using more complicated math. In the drawing, the plane that is drawn will never intersect the y-axis because it is parallel to it. Therefore its intersect is zero. The reciprocal or zero is zero.
@AraujoMatt12 жыл бұрын
Khairy, Thanks for your comment. The Miller indices indicates a vector normal to the plane. There is no y-component to the normal vector of this plane so it must be zero. Quoting "Materials Science and Engineering", Callister and Rethwisch, 8th Ed: "A plane that parallels an axis may be considered to have an infinite intercept, and, therefore, a zero index."
@g.maleksmith843010 жыл бұрын
Do you think you could explain why it intersects the y axis at -(2/3) and not (2/3)? Thanks
@tmac13in349 жыл бұрын
+G.Malek Smith I think he meant why you intersect the z-axis at (-2/3) and not (2/3) not y-axis.
@tjaartopperman44686 жыл бұрын
You probably mean the z-intersection. That is where both x and y are zero. At x =1 we have z = 2/3, and at z = 0 we have x = 1/2 as shown. So you have: x = 1, 1/2,...,... and z = 2/3, 0,...,... . If we expand the series one step, then x = 1, 1/2, 0,..., and z would expand to 2/3, 0, -2/3,...,... So at x=0, and y=0, we have z = -2/3, which is our answer. No value of y will ever affect x and z since the plane is parallel to the y-axis, and that is why we can just force y to 0.
@tw0million11 жыл бұрын
super helpful for exam review. thanks!
@arinjayakhare301310 жыл бұрын
Wonderful Explanation
@mbekafaku437111 жыл бұрын
awesome explanation
@elyssa85524 жыл бұрын
May I ask why at 6:41 the intercept of z is - 2/3? Is it possible to imagine the plane going upwards instead? Thanks!
@majorblazer69083 жыл бұрын
If the plane goes upwards it would not intersect the z axis. So your only option is extending it downwards
@elyssa85523 жыл бұрын
@@majorblazer6908 Oh I get it! Thanks alot!
@suziee_ai20248 жыл бұрын
could you actually draw another cube that shows the line above projected from the origin?
@GautamKumar-cr7tw4 жыл бұрын
I thought it would be (403) and not (403bar). Could you please explain and correct me if I'm wrong.
@fikremariamgedefaw980810 жыл бұрын
the recprocal of 0= 1/0= is infinity
@abdelrahmangamalmahdy9 жыл бұрын
he should have written infinity and then converted it to be zero
@LNasterio10 жыл бұрын
The plane explanation was good, however the direction part was very confusing... I felt like I missed out part of the video???
@ip_v110 жыл бұрын
Has a bit of a mistake by taking the y intercept for the 2nd example plane at 0 instead of infinity but ok...
@AraujoMatt12 жыл бұрын
Fatih, perhaps that wasn't the best explanation. The indices are the normal vector(or one of the normal vectors) to all planes parallel to this plane. We don't want to calculate the normal because then we need an Equation for the plane and cross products etc. As I understand it we use the idea of a limit to say it intersects y at Infinity. 1 over infinity is 0. I just keep in mind what the normal vector must look like...in this case, It has no y component
@sanjidaakter546 жыл бұрын
how to draw planner structure having indices (001);(110);(110)
@HighTech6367 жыл бұрын
Great explanation.
@shitpostadmiralty29216 жыл бұрын
It's 1am, my materials HW is due in 7 hours... I cause my own anguish.
@fatihaltunay59112 жыл бұрын
You dont explain how the plane doesnt intersect the y axes. Please explain it...
@abdullahghumman57147 жыл бұрын
reciprocal of 0 is infinity.......bro y intercept is actually infinity!!!!
@cami_66222 жыл бұрын
2021 hadir
@jeenyus72011 жыл бұрын
You sound like microsoft sam. I like you, you're alright with me.
@shrivathsagkumar8 жыл бұрын
bro y did you take -2/3
@Martyr99918 жыл бұрын
+shrivathsa g kumar I'm assuming you're asking about the second example for the y-intercept. If you continued the plane downwards, it would intersect at -2/3. You can see this by looking at the line created on the x-z plane. Starting on the x axis, going one half x in one direction causes a positive 2/3 so going the opposite direction, going one half the opposite direction will cause a -2/3 which is also where it intercepts the z plane/axis.