Millikan's oil drop experiment to determine charge of an electron - Chemistry

This chemistry video for Grade 10-11 students demonstrates R. A. Millikan's oil drop experiment to calculate the charge of an electron.

[@thekingbeyondtheg8]

I need glasses, I thought it was milkman

[@cheesenugget9845]

Same LMAO

[@cezhou2412]

Lol

[@dilawar4150]

Lol

[@Sushil2k4]

You're not alone bro.... 😂

[@holycat---------]

😂😂😂😂

[@gerunkwon2598]

By clicking on it.... Good luck on the test tomorrow.

[@alex6027]

Thanks

[@amiragaripov8136]

it's actually next period, ngl

[@beepityboop7325]

thank u

[@logicalapple_3274]

damn 6 yrs ago , how much has time changed for you?

[@trivikhariharan2032]

@@logicalapple_3274 6 months ago, how much has it changed for you?

[@elearnin]

Happy to know that our video was helpful :)

[@ashoksundari1234]

No..mmi don't understand your slang ..... because I am from Andhra Pradesh , INDIA

[@sakaraiarabenu6985]

@@ashoksundari1234 listen during class time

[@zitscx886]

@@ashoksundari1234 do u mean his accent?

[@ashoksundari1234]

@@zitscx886 yes

[@vykuntaraomajji4761]

@@ashoksundari1234 same bro nenu A.P nunche

[@WilliamSchlott]

The modern world is built on knowledge like the kind in this video.

[@mrkilroy100]

Thank goodness for scientific notation and today's calculators. I wonder if scientists have double checked all these "constants" figured out before the 20th century. One wrong decimal place could give exponentially wrong conclusions if applied as would not knowing all ionizing energies passing the atoms and variations of gravitational fields since such small exact numbers are sought. A different number would be found whether at sea level or in Denver at new moon per say. Great video.

[@zitscx886]

That's why they carry out experiments so many times.

[@shmerox7683]

They do indeed double check experiments. That’s actually the reason why e= 1.602 • 10^-19. Millikan calculated 1.59 ich • 10^-19.

[@anketmohadikar8767]

​@@shmerox7683wow ,cool

[@elearnin]

We are equally glad that this video was helpful to you :) Happy Learning!

[@kavitabajpai4954]

Elearnin I didn't understood the calculation if you can provide the calculation it would be better

[@uniqueone4097]

Thanks A Lot ❤️❤️👍

[@ATHARV224]

From India bro🇮🇳....great explanation ❤

[@johnsilverlargo]

Too difficult to me the math operations , but the graphic and your explanation is very interesting.

[@BYSMA4th]

Your lightbulb uses calculations on resistance by using the charge of an electron. Even more complicated is the photoelectric effect, which converts some amount of photon packets into electric charge, or vice versa. That is basically a solar panel or LED light. The charge of an electron determines what size of resistor, capacitor, inductors, etc we use in all electronics. Initially numbers seem meaningless but one number can be very important in making things work efficiently.

[@Yepp31]

Complicated😅

[@arneshpal7702]

​@@Yepp31nah, class 12 shir

[@HowTo5min-co3ni]

Thanks a lot for helping me out with my assignment.💞

[@rizz-shortz499]

One of the best topics in my life .... just picked it up in 1 mint ........

[@akashkumarsingh6493]

U made my concept crystal clear

[@28shreejaypandey35]

Thanks a lot sir ...... It helped in understanding the experiment a lot easier ....

[@heshamyahya6266]

I loved this one Thanks you helped me in my presentation

[@1voryscar901]

Speed up to 1.25 for normal speed

[@beepityboop7325]

lmfao thank u

[@varunjain6501]

Thanks

[@himalbamzai-wokhlu2065]

Thank you This makes so much sense now

[@antonylawrence7266]

What a mind to think up this experiment, clever bugger !

[@jg394]

I did this experiment, but I did not use X-rays. The oil drops were sprayed in between the plates, perpendicular to the lens so as not to dirty them. Some of the drops had a charge, and others even had double or triple charges. Most of them didn't.

[@dishaasingh5444]

im just curious.. how are you doing after almost 10 years =)

[@jg394]

@@dishaasingh5444 I have given up on plans to get a PhD. That was one of the options I was considering 10 years ago. I haven't made videos for over a year as my family has moved and I am building a farm. My professional life is pretty much over now and I am semi-retired. My kids are growing up and leaving home too so I am getting ready to be a grandpa.

[@leenmcheik7862]

​@@jg394 i hope you are doing fine now 🌸

[@narayanaswamy2100]

IT IS VERY USE FULL TO UNDERSTAND

[@sushmamathi6419]

Ossum explanation💓💓 and lovely animation🤙🤙🤙🙏

[@janakmedicos9735]

Ingenious ingenuity.

[@_Hee_Tzu_]

Great explanation 🎉🎉🎉

[@_choudharytanu05]

Osm explanation ❤️❤️

[@Kashifnasir89]

Finally, i understand this

[@eurekaeducation1442]

Thank you for good work. But the value of J J Thomson experiment for specific charge for an electron is in the power +11 not -11. If you use the -11 value you do not get the mass of an electron.

[@kyradonohue3537]

I thought I just proved chem wrong...

[@ShadeMurk]

@@kyradonohue3537 😂😂

[@phaelynn]

Short and straight forward

[@GlynWilliams1950]

Very clear video

[@omkarchinnu3037]

1:51 Thomson's value(e/me)=1.758820 ×10^11 C/kg

[@i9tt]

Yeah thats true and C/Kg✅ not C Kg thats mean like C.Kg ❌

[@forreal79]

@@i9tt Look Carefully, its C Kg^-1, which is the Same thing as C/Kg. 😄

[@anilrawat7924]

It is the nice method to make us understand thanku sir so much

[@sakaraiarabenu6985]

how do you keep the oil stationery

[@the_eloquent_tongue]

Short and sweet

[@workforlife40]

Good explanation. Thanks

[@princessrabaha9835]

Such an informative video!!

[@hritika411]

Yup

[@euphoricohh_]

My goodness after 5 videos i finnally understood the experiment

[@jayashreekulthe9979]

Short and informative

[@TurkishAStudent]

British physicist Thomson had measured the ratio of electricial charge to the mass of an electron using a cathode ray tube in 1897.( İngiliz fizikçi Thomson, 1897'de katot ışın tüpünü kullanarak elektrik yükünün elektronun kütlesine oranını ölçtü.) Later a Millikan looked to determine the cahrge on electrons. (Daha sonra Millikan elektronların yükünü belirlemeye çalıştı. )The famous method that he devised between 1906 and 1914 to measure the charge e of an electron is known as the Millikan’s oil experiment. (Bir elektronun e yükünü ölçmek için 1906 ile 1914 yılları arasında geliştirdiği ünlü yöntem Millikan'ın yağ deneyi olarak biliniyor.)Using this method he calculated that the charge on an electron was about 1.6. 10 -⁹ coulombs.( Bu yöntemi kullanarak bir elektronun yükünün yaklaşık 1.6. 10 -⁹ olduğunu hesapladı.) In the Millikan’s oil drop method an atomizer produces oil droplets in the form of mist which are sent through a plate of electricial condenser. (Millikan'ın yağ damlası yönteminde bir atomizer, sis formundaki yağ damlacıklarını üretir ve bu damlalar, bir elektrikli kondansatör plakası aracılığıyla gönderilir.)There are different forces which act on the oil drop including gravitational electrostatic force due to electric field and viscous drag force (Elektrik alanına bağlı yer çekimi elektrostatik kuvveti ve viskoz sürtünme kuvveti de dahil olmak üzere, yağ damlası üzerinde etkili olan farklı kuvvetler vardır.) The rate at which these drops fall were measured by observing them through a micrometer eyepiece of a telescope. (Bu damlaların düşme hızı,bir teleskopun mikrometre merceğinden gözlemleyerek ölçüldü.) X-rays were passed through the chamber to ionize the air inside.( İçerideki havayı iyonize etmek için odadan X ışınları geçirildi.) On colliding with gaseous ions these oil droplets acquire charge.( Gaz halindeki iyonlarla çarpıştığında bu yağ damlacıkları yük kazanır.) The rate at which these droplets fall can be controlled by changing the strength of applied voltage to the plate. (Bu damlacıkların düşme hızı, plakaya uygulanan voltajın gücü değiştirilerek kontrol edilebilir. ) With this experiment the observed that the magnitude of electrical charge q on the droplets is always a multiple of electrical charge e.( Bu deneyle damlacıklardaki q elektrik yükünün büyüklüğünün her zaman e elektrik yükünden çok olduğu gözlemlendi.) That is q is equal to ne where n is equal to 1,2,3 and so on. (Bu, n'nin 1,2,3'e eşit olduğu durumda q'nun ne'ye eşit olduğu anlamına gelir.)Using the value of charge of the electron the mass of the electron me was then determined by combining Thomson’s value of e by me ratio. (Elektronun yük değeri kullanılarak, elektronun kütlesi daha sonra Thomson'un e değeri/me oranı birleştirilerek belirlendi.) The value shown is the value of the mass of an electron. ( Gösterilen değer bir elektronun kütlesinin değeridir.)

[@AliHamza-yr6ri]

Brilliant

[@DevaWhiteHood]

Thank you for good work!! >_< But... e/m = 1.758820 x 10^11 not 1.758820 x 10^-11

[@malithiaradhya3617]

yeah. i noticed that too

[@NickCasey]

how did i get to this part of youtube?

[@alaaabdulgafourswerakli8125]

thank u 4 this video

[@sultanakhan83]

Thank you sir for me to understand better in 11

[@Shareya_s]

I thought it's milkman😂😂😂

[@masumpatel6069]

Short and great

[@s.rafsunmahmud6298]

Awesome.Make more videos

[@auspolk]

Whether or not you can think of a use for it some very clever folk always can. Regardless, a better understanding of the universe is always wonderful.

[@GurjotSingh-qn2il]

where does electron goes ?

[@laibamalik6267]

Thanks 4 this

[@protontv7277]

good work i could finally understand it

[@shayaandanish5831]

Wait so what was the equation used to calculate the charge. How did we go straight to the mass?

[@learnersseries1167]

it was experimentally found with the help of voltage applied i guess

[@balramsingh5918]

qE + B = mg (1) B means buoyancy, Here viscous force will be zero , But for calculating radius of oil drop we have to take viscous force 6πnrv Viscous force + buoyancy will balance out mg when no electric field is applied so we will get radius of oil drop Putting radius in (1) we will get e

[@mohammedkhalander4826]

Thanks sir it will be helpful 👍

[@kushwanthsai49]

but how did he found out e?

[@lilly-tt2wl]

Really understandable thank uu

[@syedfarhanahmed3476]

Thanks a lot

[@aiswariyabsx1a582]

Thanks this vedio was helpful to me

[@JEE_vs_NDA]

Thank you ❤

[@sahanap2015]

Thank u keep it up👍

[@khushipahwa67]

Thanku soo much...👍❤️😎

[@vaishnavimohite8204]

Thank you sir

[@SumanMazumdar]

its too good man .. ;)

[@neerajay1400]

Thank you

[@AndreaRamirez-mf6bk]

I fell in love with the voice idk why

[@princec9151]

OMG it was so helpfull

[@i9tt]

Nice video

[@usmansaleem6610]

Thanks sir.g

[@SumanaMondal-vy6sj]

Thanks to understand

[@user-cu5oe7cu4l]

Who come after watching this in PW batch😂😂

[@user-ll6op7jh2d]

But why did we did that "e/e/me"??

[@skiznit]

i recently passed high school and didn't do anything close to this difficulty -_-

[@jitendrasahu2028]

Thanks bro

[@malikasad3557]

Sir tussi great oo

[@KusumitaArora]

i finally understood from the video but i have a doubt as to how the X-ray divided protons and electrons?

[@kushwanthsai49]

i dont know properly but im pretty sure at the time protons were not discovered.

[@ursulagwozdz1955]

The electrons smash into the nucleus and break up the nuclear force.This divides the protons and neurons into particles which interact and react with the electromagnetic field in the chamber.

[@ursulagwozdz1955]

@@justabhi3585 It is entirely possible and it happens.If an electron is close enough to the centre, the nucleus, which contains subatomic particles which are held by the nuclear force itself, which is very strong....but only in small distances.The electron force is maybe not as strong, but works between longer distances, so any electron that is suspended in any place within the wave or orbital rotation, can due to its force, break through the nuclear structure, and due to its force by nature can destroy or brake up the protons or neutrons.Neutrons then become neutrinos, which are even more divisible particles, and are actually radioactive.Also that is the purpose of cycletron or paticle accelerators is to speed up the intensity with which atoms and their particles are smashed together in order to study and discover new elements where possible.This is inorganic chemistry at work.Much of chemical discovery is due to these observations and studies.Please think and read before you post or admit you just do not know, that's ok.But l am not your Bro!

[@DanFrederiksen]

I think there are some vital aspects of this experiment that are not explained in this video... how could he possibly detect quantized speed with his naked eye..

[@NerdyPanDaDaDa]

Did he use a battery to charge the plates?

[@ursulagwozdz1955]

A Capacitor

[@roxannadelarosa1715]

muchas gracias aprendi mucho

[@ashoksundari1234]

Mucho mucho mucha gdgdehhjbcswthb....I don't know your language. ..... because I am from INDIA..the greatest country 😎.....

[@ManishRajput-cq5tj]

The value of e/m that charge density of electron is 1.75 × 10^11 not -ve it's +ve 11

[@ayeshanoor611]

Why he use microscope to record the value V1 and V2 ?

[@sannaxty]

I literally searched milkmans experiment on youtube

[@BLADE_PLASMA]

Here after 8 yeard

[@Studywithronak]

Can anyone tell ? ELECTORN IS NEGATIVELY CHARGED PARTICLE RIGHT SO WHEN WE ARE FINDING THE MASS BY USING CHARGE/MASS RATIO THEN WHY SIR IS TAKE THE POSITIVE VALUE 1.6×10^-19 C

[@as2ria]

Because mass is scalar and we only care about the magnitude of the charge which is the absolute value of the charge , so we can disregard the charge in our calculation

[@Studywithronak]

@@as2ria Thank you!

[@janakmedicos9735]

Milkinson oil drop experiment to determine the electronic charge.

[@bringo9385]

Hello Drangeid!!

[@colt4667]

Error at 1:50 5th line should read 10^11 not 10^-11

[@Kotommi]

Curiosity my friend, curiosity.

[@BADDRIVERSOFITALY157]

SALEMME SALEMME

[@TheBluePhoenix008]

How did he figure out the charge

[@ursulagwozdz1955]

Using Coulomb's Law.

[@TheBluePhoenix008]

@@ursulagwozdz1955 i was asking how he calculated it exactly but honestly I don't remember what I was thinking 2 months ago

[@spidystrac6218]

Me listening after 8 years

[@munnabhai21526]

So what can i do 😅😅..

[@user-zc6dn9ms2l]

By the way the electron charge theory ? At best is only valid inside the experiment

[@sandeepsuresh7670]

🔥

[@sakshamjindal8858]

Nobody: My smart ass in class 10th after learning that the charge of electron is 1.60217662 × 10-19 coulombs: I wanna know how

[@yashraj8483]

I didn't get it

[@aneelakhan7440]

👏👏👏👏👏

[@skeller90]

Can someone explain to me why X-rays (ionization energy), which removes electrons from a atom, can be used to enhance the negative charge of an oil sample? Maybe I misunderstood something in this process and this makes me crazy :S. Thanks for the possible answers! Good day!

[@justinl2462]

X-rays are the photons produced when electrons smack into atomic nuclei. What this video means is that electrons were shot at oil droplets releasing X-rays in the process. Likely this was done by heating up a Tungsten filament causing the electrons to boil off producing streams of electrons called cathode rays.

[@dhyaneshshivam4526]

E/m ratio is wrong .. correct it

[@sedaozoylumlu8102]

Keşke Türkçe altyazı koysaydınız :) ❤️

[@ticket1159]

aynen ya

[@sherlockpato3286]

ingilizce öğren

[@alkaagrawal6651]

who is here after nitant sir

[@manishjoshi2821]

In 0.34s Charge of electron should be -ve .

[@lalgerienne9976]

please i can underst good this video please trasnlet in frnch or arabic

[@ashoksundari1234]

Omg....I too want this in Telugu....but it won't

[@ocean4951]

I thought it said milkman...

[@nomainreason]

shut up and take my money!!!!

[@premshilakumari6754]

🙏😇👏👏‼️

[@SachinKumar-de8nd]

Any JEE aspirants

[@anshikadhiman1556]

Yeah🙋🏻