I am always so impressed both with the Olympians and the mathematicians who created such intriguing problems. I would enjoy seeing a breakdown of the other problems.
@agytjax4 ай бұрын
Glad to see Presh back to posting challenging and ponder-worthy problems !
@alexandrubivolaru40764 ай бұрын
I always understand each step he explains on this channel. I would love to see other difficult problems explained by him rather than anyone else. Hopefully he will solve another IMO problem soon
@doscurantismo4 ай бұрын
Please could you upload a video in which you describe the hardest one? Great video as always.
@zmaj123214 ай бұрын
You NEED to cover problem 5!!! The solution is so easy, and I think it would be a perfect video for your channel.
@thegreatgreenarkleseizure19944 ай бұрын
I have always loved geometry, even though I haven't 'used' this kind of math all that much in life. I find the whole set of concept fascinating, and making proofs was my favorite part of it all. Using rule x to show y is just so fulfilling. All that to say, I had to pause and rewatch a LOT in this particular video, not just because some of the concepts I was either never fully taught, or simply don't remember. Once I finally followed along with all of the details, it all made perfect sense, and while I certainly could never have come up with this in my own ability, I still got the joy from seeing it all come together. On thing though, in the future, when doing all of the angles and showing how they are the same, if you could color or somehow label the angles other than the strict
@waheisel4 ай бұрын
Wow! I could follow all the steps of the solution, but am glad I quickly gave up on trying to solve this one. I never would have come close!
@hello75384 ай бұрын
I can tell how expert geometrists can easily think of this. Firstly, they would see that L and K are midpoints, and immediately take a homothety of 2 centered at A on triangle LIK. After that, they will immediately notice the parallelogram and complete it, since it would fit with point I after the homothety. After that, label the angles on the parallelogram, find which angles are same to the angles that are labeled, and the problem kind of just falls apart. I’ve been into Olympiad geometry for a while, so I somehow just recognize this kind of stuff lol. Also, this is an easy geometry problem compared to most out there in Olympiads. Any expert in olympiads will probably agree with this.
@epicbird084 ай бұрын
“wrong solution, just use barycentric instead” - my roommate at mathcamp
@wintersfan4 ай бұрын
Hi Epicbird!
@epicbird084 ай бұрын
@@wintersfanhello
@_i74134 ай бұрын
BAN
@loekvanderzijde17014 ай бұрын
Skull
@KupoPallo4 ай бұрын
Do the students get these questions in English only? As a Finnish math teacher I did not know what "circumcircle" meant, so I probably would second guess myself and end up not solving this. With the help of Google I found out it's "ulkoympyrä" which directly translates to "outer circle" or "outcircle". With this knowledge I was able to solve this in roughly 1 hour. Great problem, will be giving this out in Finnish to gifted students as a challenge. Now, I have to find the rest of these questions and see if I get stumped with the 2,3,5 and 6 :)
@pangzb964 ай бұрын
I'm sure there are translated versions of the test
@randombanana6404 ай бұрын
We also get it in our own languages.
@tollspiller20434 ай бұрын
You may request (and get) the exam in up to 3 languages
@iMíccoli4 ай бұрын
I think the name Internacional math Olympiad speaks for itself no? Each country is given the test in their own native language.
@hoangnhan66124 ай бұрын
if you participate in IMO, the test will actually be in your own language.
@z000ey4 ай бұрын
@13:15 I don't think you need to prove that length AI is equal to length IQ since as AC is parallel to XQ and AB is parallel to YQ (by the question), the formed quadrilateral is a rhombus with inscribed circle omega thus I is the center of it and divides the diagonal exactly in two same lengths (no proof needed per se) Looking forward in the video, I see you're having Q' that "maybe" has some connection to Q, and you proved it actually is the same using the prior proof of lengths AI and IQ / IQ'... BUT... why prove all that if you have a circle inscribed in a triangle, then two parallels of two triangle sides that tangent that circle form a rhombus AX'QY' that has the same circle inscribed?!? The definition of a rhombus is exactly a quadrilateral with four same length sides of which two opposite are parallel! And the center of an inscribed circle into a rhombus always divides the two diagonals in halfs! That is by definition!
@jay-jaykay37074 ай бұрын
this...points deducted for being too complicated and not using the most elegant solution...by definiton/construction we have 2 pairs of parallel lines with equal distances, so its a rhombus, so the circle centre lies on both diagonals, so all the length and angles match, thats super straight forward...using 2/3 of the video time of the proof on the most obvious part and only 1/3 on the actually difficult parts is a bit ridiculous...
@leif10754 ай бұрын
DEAR GOD surely you can solve this without construcijg BCQ which I don't see Anyone any math grnius thinking of..or inscribed angle theorem..so why do this?? Please solve a way ppl.will actually think of..
@BigAsciiHappyStar4 ай бұрын
Proving AI = IQ is a must. Otherwise how do you prove that angle LIK = angle BQC?
@z000ey4 ай бұрын
@@BigAsciiHappyStar please observe with more concentration: You've a triangle and it's inscribed circle with the center I You now translate the sides AC and AB so that they tangent that inscribed circle also on the other side of it. They intersect in a point Q. If you draw a line between the two tangent points you WILL get a straight line that has the length of 2 radii of the inscribed circle, and that is also the length of the sides of the new quadrilateral, as they are parallel in pairs. And all four are the same length and equal 2 radii of the inscribed circle. By doing this you get a rhombus BY DEFINITION, as the two pairs of tangents/sides are PARALLEL and also are of the SAME LENGTH. These two characteristics are the definition of a rhombus. A rhombus also has one inscribed circle by known proofs in Euclidian geo, and it is THE SAME circle as the triangle inscribed circle. Also by prior euclidian proofs you know that the rhombus has 2 diagonals (that are perpendicular one to each other, but this not used here, so no need), and that one of them is longer and the other is shorter. Also you know that by prior proofs the two diagonals intersect exactly in the point of the center of its inscribed circle. Also the diagonals are split in half by their point of intersection which is also the center of the inscribed circle. Thus, due to proofs done in Euclidian geometry already 2500 years ago, you KNOW that Q = Q' and AI = IQ
@oliverfiedler85024 ай бұрын
my first thought: too many trees, so i guess someone didn't see the forrest ;-)
@zdrastvutye4 ай бұрын
for someone whow only knows the perpendicular formula developed from the coordinate product instead of the bisector of angles, the centerpoint of the inner circle of a triangle will be the result of a repeated calculation: 10 print "mind your decisions-geometry question to the worlds best math" 20 xg1=0:yg1=0:xg2=1:yg2=1:xpu=1:ypu=0:gosub 120:gosub 570:print"test", xlu,ylu: 30 lab=0.8:lac=0.7:lbc=1:la=lab:lb=lac:lc=lbc:lh=(la^2+lc^2-lb^2)/2/lc 40 h=sqr(la^2-lh^2):xa=lh:ya=h:xb=0:yb=0:xc=lbc:yc=0:dim x(2,3),y(2,3):rem den innenkreis berechnen*** 50 x(0,0)=0:y(0,0)=0:x(0,1)=lh:y(0,1)=0:x(0,2)=lbc:y(0,2)=0:x(0,3)=lh:y(0,3)=h 60 xm1=0:ym1=0:r1=0:xvi=1000:yvi=850:n1=2:n2=3:xm2=0:ym2=0:r2=0:gosub 630 70 x1=x(0,0):y1=y(0,0):x2=x(0,2):y2=y(0,2):x3=x(0,3):y3=y(0,3):gosub 550:xm1=xlu:ym1=ylu 80 r1=sqr((x1-xlu)^2+(y1-ylu)^2):gosub 630:@zoom%=@zoom%*1.1 90 sw=sqr(la^2+lb^2+lc^2)/100:swx=sw/10:ym=sw:xg1=lh:yg1=h:xg2=lbc:yg2=0:goto 230 100 xg1=0:yg1=0:xg2=lh:yg2=h:r2=ym: 110 xpu=xm:ypu=ym:gosub 120:goto 150 120 a11=xg2-xg1:a12=yg2-yg1:a131=xpu*(xg2-xg1):a132=ypu*(yg2-yg1) 130 a21=yg1-yg2:a22=xg2-xg1:a231=yg1*(xg2-xg1):a232=xg1*(yg1-yg2) 140 a23=a231+a232:a13=a131+a132:return 150 gosub 570:dgu1=sqr((xlu-xpu)^2+(ylu-ypu)^2)/lab 160 dgu2=r2/lab:dg=dgu1-dgu2:return 170 xm=swx:gosub 100 180 dg1=dg:xmu1=xm:xm=xm+sw:xmu2=xm:gosub 100:if dg1*dg>0 then 180 190 xm=(xmu1+xmu2)/2:gosub 100:if dg1*dg>0 then xmu1=xm else xmu2=xm 200 if abs(dg)>1E-10 then 190 else return 210 gosub 170:xg1=lbc:yg1=0:xg2=lh:yg2=h:yp=ym 220 gosub 120:gosub 570:ru=sqr((xlu-xpu)^2+(ylu-ypu)^2):df=(ym-ru)/ym:return 230 gosub 210:rem print xm,ym:stop 240 df1=df:ymu1=ym:ym=ym+sw:ymu2=ym:gosub 210:if df1*df>0 then 240 250 ym=(ymu1+ymu2)/2:gosub 210:if df1*df>0 then ymu1=ym else ymu2=ym 260 if abs(df)>1E-9 then 250 270 print xm,"%",ym:xm2=xm:ym2=ym:gosub 630:rem l1 und l2 durch drehung um 180 grad berechnen 280 xcu=xm2:ycu=ym2:xu=xa:yu=ya:gosub 300:x(1,0)=xv:y(1,0)=yv:rem print xv,yv:stop 290 xg11=lh:yg11=h:xg12=lbc:yg12=0:xu=0:yu=0:gosub 300:xg21=xv:yg21=yv:goto 310 300 xv=2*xcu-xu:yv=2*ycu-yu:return 310 xu=lh:yu=h:gosub 300:xg22=xv:yg22=yv:gosub 350:x(1,1)=xlu:y(1,1)=ylu:x(1,2)=xa:y(1,2)=ya 320 xu=xa:yu=ya:gosub 300:xg21=xv:yg21=yv 330 xu=lbc:yu=0:gosub 300:xg22=xv:yg22=yv:xg11=0:yg11=0:xg12=lh:yg12=h 340 gosub 350:x(1,3)=xlu:y(1,3)=ylu:cls:gosub 630:goto 380 350 a11=yg12-yg11:a12=xg11-xg12:a131=xg11*(yg12-yg11):a132=yg11*(xg11-xg12) 360 a21=yg22-yg21:a22=xg21-xg22:a231=xg21*(yg22-yg21):a232=yg21*(xg21-xg22) 370 a13=a131+a132:a23=a231+a232:gosub 570:return 380 x1=xa:y1=ya:x2=xm1:y2=ym1:dx=x2-x1:dy=y2-y1:xm=xm1:ym=ym1:dl=dx^2+dy^2 390 px=(x1-xm1)*dx:py=(y1-ym1)*dy:p=2*(px+py)/dl:q=((x1-xm1)^2+(y1-ym1)^2-r1^2)/dl 400 dis=p*p/4-q:if dis
@ejrupp95553 ай бұрын
What's the name of the routine? SeaWolf? Cause it's a gosub?
@zdrastvutye3 ай бұрын
@@ejrupp9555 thanks for your aattention but what do you really want?
@Doktor_Vem4 ай бұрын
I honestly feel like this is more of a reading comprehension and visualization excersize than a math excersize
@reveal-n7z4 ай бұрын
Not really, for if you give this to your English prof/teacher I’m pretty sure they won’t be able to solve it
@ceilingfun21824 ай бұрын
@@reveal-n7zgood point
@julienchalimon46434 ай бұрын
Reading, compréhension and visualization are parts of mathematics imo
@reveal-n7z4 ай бұрын
@@julienchalimon4643 fair enough, so this is still very much a math challenge 👍
@noskillman65074 ай бұрын
That's the easy part. IMO problems are brutal
@kaspervanoverbeek40644 ай бұрын
At around 15:30 you concluded that AI = QI with some good calculations, But couldn't you also say that becouse: X'Q -> AY' and: AX'-> Y'Q, With a circle midpoint I, And because the circle is in the middle of the square, Which should mean that: AI = QI And X'I = IY'?
@viktor.tsonev4 ай бұрын
I think its much easier to prove that AX'QY' is parallelogram and AI as bisect is also a diagonal and I is the center
@z000ey4 ай бұрын
Not only a parallelogram, but a specific one, a rhombus. All sides have the same length. Thus center of inscribed circle is half of both diagonals.
@Anp1374 ай бұрын
THANKS SIR CONTINUED UPTO 8 DAYS AND I FEEL REALL A BETTER IMPROVEMENT IN MYSELF ❤❤ LOVE MATHEMATICS ♾️🔥
@vitalsbat23104 ай бұрын
Although I also found the geometric solution, i used trigonometry and found an elegant property that the angle bisector splits KIL into two angles that are equal to the base angles of ∆XPY
@Advith129874 ай бұрын
?
@vitalsbat23104 ай бұрын
@@Advith12987 what you don't understand? I can explain a bit
@Advith129874 ай бұрын
@@vitalsbat2310 the property
@xvh274r4 ай бұрын
Random question what do you think is harder making it to IMO or beating tidal wave
@Advith129874 ай бұрын
@@vitalsbat2310 the property you found
@Haivexx4 ай бұрын
why is BQC=KIL 9:56 is there a rule that Im missing?
@virendrakumarvishwakarma32024 ай бұрын
Midpont Theorem
@virendrakumarvishwakarma32024 ай бұрын
In ∆ABQ , L and I are midpoints of AB and AQ respectively. By the theorem, in a triangle the line joining two midpoints of any two sides is half of the 3rd side and PARALLEL TO THE 3rd SIDE. Hence, LI || BQ and taking AQ as transversal Angle AIL is congruent to angle ABQ Similarly on other side Hope you get it
@leif10754 ай бұрын
At 10:16 you made a mistake.it's angle YQX NOT angle YPX right?
@jorgebaccarcell4 ай бұрын
At 6:17, it should be A+C=180 AND B+D=180 (instead of OR).
@vxllabh093 ай бұрын
what he means to say that either one of the criteria imply the other so you just need to prove any one of them, it is the standar mathematical definition of that theorem
@mdsalimazad85634 ай бұрын
How should I approach these questions?
@EspecialMonster2 ай бұрын
Everyone:Cyclic Meanwhile him:seaclick.
@pradipkumardas30604 ай бұрын
Please provide us insights on harder questions from IMO
@opendstudio71414 ай бұрын
Proof that spiders instinctively know geometry. 😉
@mobananalicious7 күн бұрын
had me crying because i couldnt understand which angle he was talking about
@iamadooddood43314 ай бұрын
12:52 13:04 Lol XPB instead of XBP. Also, it'd have been faster if you'd noticed that AX'QY' is a rhombus.
@ggritans77484 ай бұрын
I solved it differently. First I labelled the intereection point of xxprime and yyprime as D. Said AXprimeDYprime is a parallelogram. Proved XprimeIYprime ate collinear and thus it is a rhombus. Then the solution is basically the same
@sanjeevkumarsingh81414 ай бұрын
Please share how you approach a problem you haven't seen it before
@jhpenguinn4 ай бұрын
Critical thinking, math isn't about memorising problems
@turbokaivuri83904 ай бұрын
You will build intuition by doing many problems
@Z-eng0Ай бұрын
Felt too complicated for me this time, but my problem wasn't that it was complicated, it was that usually when a problem is really complicated I feel it's better to show some enlightening information, like for example that even though 2 angles look like they're totally different and not the same they end up being the same, or maybe the cool theorems like Ptolemy's theorem or the pilot theorem, but in this case I didn't feel any point in the final destination of the proof if you get my point, like, it didn't feel like we accomplished anything after we reached the conclusion asked for by the problem, so I didn't really feel satisfied at all or content by the question itself
@youtuger4 ай бұрын
sweet sweet IMO. I remember the guys from math classes i went with flew to other countries to win awards and i couldn't because of some paperwork problems
@BennoRob954 ай бұрын
I feel like the colour coding and diagram itself could have been made clearer. I got stumped when the opposite inscribed quadrilateral angles were seemingly interchanged with the triangle angles and wasn’t sure if the two inscribed circles were being used simultaneously, if that makes sense
@damyankorena4 ай бұрын
Somehow I think this was even easier than P1, which was pretty trivial if you have general knowledge of the floor function
@tollspiller20434 ай бұрын
P1 was just really ugly in the solution - there are nice ones but you qickly realise the ugly approach works and under contest pressure you write that up. P4 at least uses some ideas.
@BSav-s4g4 ай бұрын
sir, can you please do for SINGA maths competition? competiton is on 31 august. deeply appreciated 🙏🏻🙏🏻
@OilCanHarry2U4 ай бұрын
I don’t know the answer to this question …but I do like seeing kittens playing in hay barns.
@agytjax4 ай бұрын
At 1:50, it is heartening to see India finish 4th this year. We have been doing great over the last few years, thanks in large part to the teachers in the month long training camp. It is only a matter of time, before we dominate IMO like we dominate the International Chess (expect for that odd Norwegian😀 )
@DhoklaAboveVadapav4 ай бұрын
I wonder If we will ever find a player better than magnus, or he will remain the undisputed king for infinity and beyond.
@agytjax4 ай бұрын
@@DhoklaAboveVadapav - People used to wonder the same when Fischer was in his prime and when Kasparov was unbeatable for over two decades. I am pretty sure, someone better will come along. I wish it is from India 😀
@DhoklaAboveVadapav4 ай бұрын
@@agytjax True. Surely someone will come. But I doubt in next 10 years.
@virendrakumarvishwakarma32024 ай бұрын
🔥
@Npc9914 ай бұрын
i would love to see one of the harder problems even tho im only in year nine :DD
@AAAEA0104 ай бұрын
You gotta tell us about the harder questions
@kirkn604 ай бұрын
Without a compass and straight edge, I would have a hard time making a legible diagram and some of the points might fall on top of each other. I assume that contestants aren't allowed to use drawing tools or software.
@MamtajK4 ай бұрын
They are provided all the tools needed such as geometrical tools, scientific calculators etc. They are even given snacks like cookies, bananas, energy/fruit drinks, dark chocolates etc too! Since they have to sit and think hard for 4.5hours straight.
@ktomeir4 ай бұрын
Instead of showing that Q and Q' are the same you could have described Q as the intersection of XX' and YY' and show that IA part of a parallelogram AX'Y'Q because it bisects X'AY' and therefore Q is on AP.
@leif10754 ай бұрын
Can't you solve this without the sickly quadrilateral theorem or imbibed angle theorem since I don't think a lot of ppl will think of them?
@bridgeon75024 ай бұрын
This is the International Math Olympiad. Every country selects its 6 best students to compete each year. They can't just have some simple, straight forward solution that anyone can think of. These students are the best of the best!
@leclerchannaburg61294 ай бұрын
This is very useful for gears inside of a motors engine creating torques. So the pistons could keep moving and they burst the gas, so you're able to drive your vehicle.
@agytjax4 ай бұрын
If you are serious, can you explain how or point to some resource available in public domain ?
@himanshujha76224 ай бұрын
We would definitely appreciate if you also bring vids for rest of the 6. This one is commendable, great explanation, even a 7th grader can understand this
@aryankushwaha70284 ай бұрын
Sir can you make video on geometry concepts
@marcinbednara38254 ай бұрын
Pozdrawiam z Polski! 😊
@barteqw4 ай бұрын
Witam serdecznie i również pozdrawiam 😊
@marcinbednara38254 ай бұрын
@@barteqw napisałem ten komentarz po polsku w kontekście tego zadania.
@barteqw4 ай бұрын
@@marcinbednara3825 wiem że pochodzi z naszego kraju
@logicfacts65744 ай бұрын
who creates these questions? 🤔😮😥
@pzelact43284 ай бұрын
10:16 u said angle QYC instead of QCY!!!
@MindYourDecisions4 ай бұрын
Good catch 😊 This was an alphabet soup so it was a challenge to say everything correctly.
@ejrupp95553 ай бұрын
The problem with the problem, initially, is the word jargon that math uses instead of modern english, like latin or Ole English, ya just don't know what they hell they saying. I talked this out with a 16 year ole and they got it right in about 15 minutes. Because when ya talk with someone ... you can use your hands and form a mental image in 3D rather than 2D ... even if it is a 2D issue ... you have no problem rotating the image in space and turning in a way to advantage you. But if you have to create the image you have to create the next D. It's easier to see it at the higher D and work backwards. Which goes to say what they did at this comp was harder IMO. and lets not forget the pressure they were under. me and the neighbor ... we were just chit chatting.
@AFSMG4 ай бұрын
Complicado. Sobre todo el poder dibujar el problema. Muchas gracias
@ACheateryearsago4 ай бұрын
It doesn't feelgood seeing that there are people who can solve this question while I cant get through half of the process, even though the process seems easy.
@z000ey4 ай бұрын
Don't worry, 99,9% of us can't either ;)
@iMíccoli4 ай бұрын
If you don't study for math Olympiads like we do that's completely normal lmao. The amount of work, and study we have to do for this problems is insane but interesting, fun and rewarding.
@tommyb66114 ай бұрын
Make a series with ALL these problems, and you can rename this video with the text in brackets first
@vmadhavan4354 ай бұрын
Hi presh!!
@chaossspy67234 ай бұрын
lol, massimo gobbino is one of my professors at unipi (calculus 2)
@TheBurzhuy4 ай бұрын
The only way USA can compete is to not show Russian team 🤣. In individual results a Russian got silver. Previous year Russia got gold in individual results. 💪 China and Russia are the strongest
@wintersfan4 ай бұрын
In this IMO 2024, the total score of Russian students are 185, China 190 and USA 192 So i don't know what you're talking about 😂😂
@TheBurzhuy4 ай бұрын
@@wintersfan i googled team members. china team members in 2023: Shi, Wang, Zhang, Liang, Sun, Jiang Usa team members in 2023: Liu, Wang, Lin, Zhao, Lu, Shen. major race in usa is white (around 60%), and asians are like 9-10%. I believe there were two asian teams and none from America or you are another state of china. From 60% of the nation there is no white who is smart anough? This is pathetic. Usa - United states of asia😂 P. S. Russian team in 2023 : Алиса Волкова, Роман Кузнецов и Эльдар Хисамутдинов, Александр Гнусов, Ратибор Коптилин, Павел Прозоров. At least 4 members are with clear Russian names.
@wintersfan4 ай бұрын
@@TheBurzhuy why are you bringing race tho? They are still American.
@TheBurzhuy4 ай бұрын
@@wintersfan because I can😋 I didn't say they don't have American citizenship. America can "buy" and import smart people, it is not a secret, it does it all the time. But the fact that it needs smart asians (10 % of population) to compete with china while the major race can't even represent the country in IMO tells a lot about education system. This is big respect for asian Americans and humiliation for the rest. Also, the fact that the only question you have is "why you mentioned race? " also tells a lot about western culture of the offended by anything. My country has not less nationalities than in US, probably even more (190+ nationalities, also no segregation zones for any of them 😉) , but i still can name races freely and this is not offencive to people (except for cases of true offenciveness).
@wintersfan4 ай бұрын
@@TheBurzhuy i am not offended by you saying about race. But IMO is about Math and bringing up race is irrelevant since the IMO is meant to represent the 6 best students in a country.
@Solysis54 ай бұрын
8:01 oh... thats AI in MindYourDecisions...
@leif10754 ай бұрын
I don't see why anyone would construct triangle BQC..right would anyone really, even Chat GPT SOB? So why not solve without that please?
@tollspiller20434 ай бұрын
Its very intuitive, it encompases both lines given and additionally lies on the angle bisector, so introducing the point Q should be the first thing to do
@leif10754 ай бұрын
@@tollspiller2043I'm sorry but it's not intuitive at all even if you complete the quadrilateral..i don't see how..intuition is subjective maybe?..and what angle bjsectpr are you referring to? ..and furthermore can't you solve without completing that quadrilateral with the parallel lines..thats something else thats nkt at all intuitive or organically logical so please solve without it. Wouldn't you agree with that? Thanks for answering.
@tollspiller20434 ай бұрын
@@leif1075 there are other solutions that dont involve Q but other points, e.g. a point R such that BIR are collibear and AR is perpendicular to BR. Point Q is the easiest and modt obvious one to introduce
@whitemountain48514 ай бұрын
I feel like the idea here is foresight - you know that the midpoint and the incenter are very badly connected so you want to “move” the angle
@BigAsciiHappyStar4 ай бұрын
@@whitemountain4851 that is exactly what I did first. I call this the Principle Of Most Disgusting - focus on the most disgusting part of the problem and work out how to make it less disgusting 😀
@brianmccormick83284 ай бұрын
That’s the easy problem on the exam? Wow.
@iMíccoli4 ай бұрын
That's Olympiad math problems for ya
@placeholderfornow47664 ай бұрын
2nd easiest or easiest, and the difficulty ramping is brutal, even the 2nd problems on each day are significantly harder (except for problem 5 which was really easy this year)
@iMíccoli4 ай бұрын
@@placeholderfornow4766 P5 was so troll xD
@placeholderfornow47664 ай бұрын
@@iMíccoli ikr, i was in a group class where we solved 2024 imo for fun and half of us got it instantly while the other half were STRUGGLING
@iMíccoli4 ай бұрын
@@placeholderfornow4766 it must've been a nice class. But that outcome was kinda of what happened in the Olympiad based on the results and some comments I read.
@bosorot4 ай бұрын
Test for top 0.0001% from top 0.001% students. Not for most of regular human.
@bkj5564 ай бұрын
😮😊❤🎉
@SajidKhan-l3t7c4 ай бұрын
🥹🥹savebangladeshistudents
@CwalkNytho4 ай бұрын
This one gave me a headache
@desmondkgatla70054 ай бұрын
For 4 hour's it's doable
@huzefa64214 ай бұрын
5th Early Again.... WTH is going on 😅
@ssarmazi4 ай бұрын
What a monstrosity
@thaihienle15304 ай бұрын
I have a simpler solution, no knowledge of cyclic quadrilaterals required
@Problemsolving-gi3j4 ай бұрын
Share it then
@user-bg2ct4dy5k4 ай бұрын
20 minutes to do an hour program. Slow down and call out the points.
@gyanprakashraj40622 ай бұрын
KHAO PEEYO😂😂😂
@daddykhalil9094 ай бұрын
10:12 Extremely complicated with a jungle of letters and lines. Unfortunately...
@leif10754 ай бұрын
Surely there is a way to make it cleaer and a way tonsolve WITHOUT the inscribed a gle theirem since a lot of ppl no matter how genius will NOT recall that.
@wowyok45074 ай бұрын
ai solved this problem in 19 seconds :/
@redsolaris14 ай бұрын
Only after receiving the formalized statement of the problem in AlphaGeometry’s own language. They essentially cheated by translating the problems from english into machine manageable versions
@wowyok45074 ай бұрын
@@redsolaris1 yes but that doesn't change the fact that it gets it right in 19 seconds. Its just how computers work, and they're faster than us humans, accept that.
@MariusGjika4 ай бұрын
@@wowyok4507 The ai got 0 points on problems 5 and 3 though, it’s because they were more logic oriented problems and the speed of computers is basically useless when it comes to that
@wowyok45074 ай бұрын
@@MariusGjika ah yes, an ai that was created half a year ago won't get any better, yes agreed
@MariusGjika4 ай бұрын
@@wowyok4507I’m not saying it won’t get better, just that it’s not as powerful as you think. Till now in the field of combinatorics, it’s gotten nowhere(it got 0 points on both of the combinatorics problems), since theres something inherently different about this field which makes it difficult for ai to grasp. Though i am curious to see if it will improve significantly in the near future
@PowerX82864 ай бұрын
Do for class 7 mtg sof
@gregoryknapen91334 ай бұрын
Are you allowed a ruler and compass on the IMO? Otherwise this is just cruel.
@iMíccoli4 ай бұрын
Of course lol, you can't even do this problems without it.
@entropyachieved7504 ай бұрын
You lost me reading it...
@TheCheese2694 ай бұрын
u wot m8?
@leif10754 ай бұрын
I'm not sure whether to believe AI is already smarter or can be smarter than humans..if Presh couldn't solve it,does thatmean AI is smarter than him..and if most ppl.have so much difficulty with math are humans really as smart as we tout and aren't AI already smarter than a lot of ppl?
@robertveith63834 ай бұрын
Proofread what you write and spell out your words.
@crystallinegem38424 ай бұрын
Were you dropped in the head as a baby? This is why dependence on AI makes you completely useless
@JakeMarley-k6g4 ай бұрын
Based on how you wrote that, yes they most certainly are
@leif10754 ай бұрын
@@JakeMarley-k6glol.come on i was lazy and writing fast and autocorrect sucks so surely you don't mean that?
@JakeMarley-k6g4 ай бұрын
@@leif1075 I don't, I'm just messing
@gyanprakashraj40622 ай бұрын
ALMAA HII KAAFI HAIN ....
@natashok43464 ай бұрын
Presh you have a mistake. You did not use all letters in alphabet. My conclusion: it was not an Olympiad, it was linear work in shop for cashier. Competition should be interesting. I'm sorry Presh, be happy! 🤷♀️