Chemical Equilibrium | Chemistry | Prelim Preparation | Mlungisi Nkosi

[@wizzy717]

To the person reading this:Even though I don't know you,I wish you the best of what life has to offer❤

[@MlungisiNkosi]

Thank you

[@palesapertunia5748]

When they are talking about a blessing they were referring to you 😇😇 your videos are really helpful 👌 . To actually think that i have been struggling with maths and science until you came . I would like to take this moment and Thank you for your help 😇😊😊

[@MlungisiNkosi]

It’s my pleasure 😇

[@buyile_beverly]

As a class of 2022 we have to make Mlungisi Nkosi trend in January because wow 🔥 👌

[@MlungisiNkosi]

Thank you so so so much 😊

[@kholofelosekgobela8037]

Mr Mlu your the best sir..YOU UNMATCHED I pray God blesses you

[@MlungisiNkosi]

Thank you so much

[@zinhlethwala1165]

And how is it to get 0.81 when we divide 0.162 by 2 instead of 0.081 .. I think there's a mistake there sir

[@MlungisiNkosi]

Yes it is a mistake. Apologies

[@faith-yx1fz]

great video,just what I needed😄but how is it 0.81 for the number of moles reacted for Iodine🤔I got 0,081

[@sealamothapo6882]

You are right ... sir made a mistake there.

[@MlungisiNkosi]

It was a mistake. Askies

[@ntwisisochauke3495]

sir is y not supposed to be 0.0981?

[@her5299]

Thank you sir🎉

[@MlungisiNkosi]

You’re most welcome

[@Chioma133]

Hey sir there might have been a mistake with the change in concentration in 6.2 but the steps to finding the answer really helped... Thank you so much...🙌🏽😩♥️

[@MlungisiNkosi]

I’m glad it helped and sorry about the mistake

[@pabalelomasha6438]

good evening sir hope you well. quick question sir how is the forward reaction endothermic if it was decreased

[@MlungisiNkosi]

It depends so much on temperature, that the moment it’s removed, the rate goes plunging down

[@siyabonganhlanhla]

Hi sir I have a question about KC So there's a question I once saw I'm not sure was it sup or what so they gave us the statement and the equilibrium so the question was to calculate I think the initial moles of a certain company and obviously the KC value it's the same because they didn't change the temperature The question was calculate the initial moles if the equilibrium was re-instated so my question is how do I use the given information of the initial KC to calculate the re-instated equilibrium

[@buyile_beverly]

Sir do you have a video on *REACTION RATE* graphs with regards to Le Chatelier's principles and not the chemical change ones

[@MlungisiNkosi]

Yes I do… Check chemical equilibrium playlist

[@zinhlethwala1165]

How it is possible sir to get 0.162 on change in mold of 2HI while we started with zero Wasn't is supposed to be 0-0,162 then we get -0,162 so that when we check by adding equilibrium and change in Mol we can get zero ..please assist there I'm getting confused

[@ntandokazimtsweni7096]

Im confused too

[@noktee5961]

is ur answer also 0.098 mol?

[@noktee5961]

then 24.893g

[@tshiamomfetane835]

since 2HI is a product,it's going to be positive

[@tshiamomfetane835]

@@noktee5961 mine is

[@lehlohonolokhakhane5695]

Mr Nkosi canyou please do question 7 up to question 9 for chemistry paper 2..that we just written today please sir .. your videos do really help.. which I appreciate sir.

[@MlungisiNkosi]

Please send a soft copy to my email

[@Sandiso04]

Mr you you see to have made a mistake with the KC calculation the moles for I2 were 0.081 not 0.81

[@MlungisiNkosi]

Thank you 😊

[@sbahlesbahlee1754]

Sir there is a problem

[@hlengiwesimelane6665]

Tough Tough Tough but Thank You

[@MlungisiNkosi]

But you pulled through