Thank you for these lectures. Around 9:30, Prof says the output of a linear system is zero when the input is a zero function, but proceeds to prove it by considering alpha = 0and not u=0. It is not clear how it follows that the zero function will result in a zero output. Edit: Never mind. I got it. Any zero function can be expressed as alpha times a non-zero u(t) where alpha=0. By the definition of linearity this will produce a zero output.
@nirajaltekar4006 жыл бұрын
Excellent introductory explanation of stability of equilibrium points. Thanks
@EngBandar16 жыл бұрын
At 23:31, you said "in case multiple equilibrium points", linear systems has a single equilibrium point at the origin. What do you mean by multiple equilibrium points for linear systems? Any clarifications? thanks.
@EngBandar16 жыл бұрын
That is not true. The linear system must satisfy superposition and homogeneity properties. Even a straight line equation that doesn't pass through the origin is not considered as a linear system.
@shanshanbond70402 жыл бұрын
great lecture. got it right how i wanted to understand this
@To_the_right_side9 ай бұрын
thunk very much professor from algeria
@nafizgt97617 жыл бұрын
when x=4, 3x-2, 14 or 10?
@nurisezer932 жыл бұрын
1 billion
@tanajimalusaray7 жыл бұрын
What are we perturbing ? Why were worry about equilibrium point ? Why are we doing this analysis ?
@rejathsimon90016 жыл бұрын
tanjimlusary The differential equation practically represents a system(eg: a car, robot,etc) and perturbances are unwanted disturbaces acting on the system(eg: air wind acting on a quadcopter, etc).... You can probably try to relate these into real world and I guess that is the best way to learn control
@federicocelletti43939 жыл бұрын
12-2=10 not 14. But good video anyway.
@ravikhandelwal29963 жыл бұрын
At this stage, pointing out such mistake is not good. If you have technical doubt..then point it out...