At 49:15, the subset signs are reversed, affecting the implications. Sigma-algebra implies algebra, and algebra implies semi-algebra.
@marcoguitarsolo8 жыл бұрын
Thanks for pointing that out - it threw me off for a sec
@bappaghosh3846 жыл бұрын
At 38:00 while proving sigma algebra monotone class theorem he is using boot strapping and good set principles, I think the collection B should be th following B={ E subset of M(A): A^c is in M(A)}, instead of B={ E subset of X: A^c is in M(A)}. same for the boot strapping.
@KidAFateen5 жыл бұрын
Shouldn't it be An is a superset of An+1 or An+1 is a subset of An at 2:09 ?
@Vic-de6ud6 жыл бұрын
at 36:46, isn't is enough just to show that M(A) is algebra and then applied the previous theorem that: algebra that is also monotone is sigma-algebra? Thus leads to S(A) is included in M(A) directly? What is the necessity of also showing M(A) is closed under unions?
@Vic-de6ud6 жыл бұрын
Oh never mind, it requires that closed under union together with closed under complement to show that M(A) is an algebra.
@shuaiwang56064 жыл бұрын
wondering what pens he is using... looks so smooth..