Modulation Techniques

This EzEd Video explains
Modulation Techniques
Types of Modulation
Analog Modulation
Digital Modulation
-Analog Modulation
Amplitude Modulation
Frequency Modulation
Phase Modulation

[@abdoulsimpore1708]

I'm curious why no one has made a comment on this video. This guy presentation is amazing and extremely well done. Thank you very much

[@thisaccount9936]

Hello EzEd Channel, Great explanation and animation, straight forward, congratulations for this! Only some adjustments would be needed for wrong info: 5:26 wct instead of 2wct, because w=2pif. Error now is propagated until 5:45 At 6:56 fm=10^3, Ec=40, but the next must be corrected: 7:32 fm=10^2 and at 7:58 Ec=20 (F). Also at 22:40 the expression should be corrected in (wct). Wish you great lectures and keep going!

[@saqibsaqib6912]

You proved to be a light for me in this dark topic.

[@teodoramihuc9006]

This video helped me understand a lot of key-things. Thank you!!!!!!

[@EduLectureBd]

Correction: Frequency Spectrum of AM wave: eAM =...... cos(wct)

[@DarthLala106]

There is an error around the 8:00 mark where E(c) should be 40 but is written as 20.

[@jionemataere7825]

Thank you very much for your explanation, the best I hav heard

[@hafiz031]

At 5:27 in the trigonometric identity is 2cosAcosB = cos(A+B) + cos(A-B). We know cos(-theta) = cos(theta). So it is mathematically valid to write cos(B - A) instead of cos(A - B). If we do so then eventually we will get (wm - wc) instead of (wc - wm) and finally the bandwidth will be 2*fc instead of 2*fm. As we are getting two possibilities mathematically hence we cannot just ignore the alternate one. But so far I have never seen to use 2*fs as the bandwidth instead of 2*fm. But we are getting it mathematically. So what is the significance of it?

[@BacsPet96]

Correct me if I'm wrong, but in the equation shown at 5:35 the [ Ec cos (wc t) ] part should be [ Ec cos (2wc t) ] . Otherwise the video is really helpful!

[@wrichik_basu]

Please don't put in ads in the middle. They are distracting. When I am concentrating, suddenly an ad comes up, and I get a shock. Please don't do that. An ad in the beginning should be good enough.

[@EzEdChannel]

Thank You for your feedback +Wrichik Basu. Please visit our website www.ezed.in and enroll for the Basic Electrical and Electronics course to get an ad free content, plus notes, online tests , and much more.

[@saurabhmalpeddiwar8199]

nice explanation sir, thanks for video, can you please uploads more videos on analog and digital communication

[@mutiurrehman7467]

@8:06 : Ec=40 ; and (omega)Wm = 2pi* 10^3=1KHz

[@therealscience210]

which software you use to make these types of videos??

[@adifferentboy3038]

It is awesome . Thanks for this video.

[@anwarullakhan3801]

there is a mistake at lecture time 5:29 i.e cos2wct....it must be coswct

[@alanaquinojr]

Hi, Could you allow in the settings of this video the addition of new subtitles ? I want add a Portuguese version.

[@EzEdChannel]

Hi +Alan. Please email us the file and we will add the subtitles to the video.

[@eljohnfloralde8560]

Very well said. Kudos!

[@surajkushwah3221]

such a awesome video ...thanks

[@goyalmedicos]

thanks uuhh sirrrr....soo helpful helped in my mains paper

[@kaviyarasud8353]

clean exaplanation👍👌👌👌

[@JBrodo]

Example at 8:00, fm should be 100 Hz, not 1000 Hz, yes?

[@YoungsProton]

10^3 is 1000 ... why would it be 100 hz ?

[@thisaccount9936]

In the problem definition, fm=10^3=1000 Hz... wrong notation in the solving

[@Dipenparmar12]

amazing explanation....

[@ygyeh]

Dude, your derivation of AM freq spectrum got a notation mistake, 2Πfct must be wct

[@fahadnasir1286]

Thanks for making this nice and easy lecture vedio

[@EzEdChannel]

Thank You @Fahad Nasir . Please subscribe to our EZEd Channel to view more such videos

[@sultan28]

You do not describe the Phase Modulation briefly.Please do it.

[@Rajesh-uq3zy]

can u provide pdfs for the analog communications

[@EzEdChannel]

+Cherry, Please visit our website www.ezed.in for course content which includes notes.

[@Mauu_Ajjuu]

superb video

[@girishsuper5885]

very helpful.

[@amrithjayakumar2953]

Good explanation ..

[@yaminirawat7610]

Great lecture for college students

[@KhanMethodVideoLecture]

Good

[@EzEdChannel]

Thank You. Please subscribe to our EzEd Channel for more such videos.

[@nadezhdadimitrova4042]

Very helpful!

[@Arwokid]

7:39 what? it's 100Hz... since wm = 2pi*100...????????????????

[@JBrodo]

Right...? I feel crazy that isn't mentioned more in the comments?

[@hassanismail4221]

You Are The Amazing One

[@EzEdChannel]

Thank you +hassan ismail . Please subscribe to EZEd channel for more such videos

[@bj3485]

an image is analog? i dont think so....

[@arifulhasan1156]

excellent

[@tomkaminski8907]

sick editing :-D

[@astroboy602]

nicley explained

[@EzEdChannel]

Thank You +MIAN SAJAWAL SHAH. Please subscribe to our EzEd Channel for more such videos.

[@invitacionesdigitales1574]

everything was beutiful until you mentioned the mathematical formulas.

[@yasseryahia8250]

Thank you

[@EzEdChannel]

+the footballer . Please subscribe to our EZEd Channel to view more such videos

[@yasseryahia8250]

I've already done it with wix :D

[@khushifancy]

+the footballer ):s

[@yavuzyagmuryank9952]

Epic video

[@etjh0071]

heh the squidward meme was right here

[@hassanibadisaheralqaraghul9004]

Pdf please

[@EzEdChannel]

Please logon to www.ezed.in and subscribe to our BEE course. You will get the notes on all chapters

[@tchuneyanderson9747]

There’s a mistake!!!