Moments of inertia with triple integrals (KristaKingMath)

[@JustinAdG14]

Very helpful, thanks! Do you also have a video where you explain other forms instead of cubes?

[@ShoTime017]

Omg. Thank you!!! 😊

[@ambadyaravindh3635]

How y2+z2 come anyone please? 1:53

[@MeThOs28]

Your voice and the little lisp really matches your personality well...

[@allinonebyhamzee5786]

its helpful thankss

[@kristakingmath]

You're welcome, I'm so glad it helped! :)

[@connermagnuson6400]

why not factor the k to begin with?

[@Neueregel]

useful formula

[@astrotaco_bps]

..but where did y^2 + z^2 come from 1:49 ...

[@infinityinf1]

Danish Fiesta Distance from the x-axis or Rx

[@canerakbas9313]

but how ?

[@thedorantor]

​@@canerakbas9313 because linear: F = m*a, and rotational: torque = F*r = (m*r^2)*(a/r). This is true since F*r = m*a*r (you multiply r on the left, so you multiply r on the right. But since we work with rotational acceleration 'alfa' and not with a, we reorder the equation to m*r^2*alfa). m*r^2 is the inertia component. In this example, we work with Cartesian coordinates (so the 'r' is replaced by x,y,z) and since Pythagoras theorem states that r^2=x^2+y^2 (or z^2, depends on the axis of rotation), you'll get the described formula.

[@imashnake_7151]

Choose any point within the cube and find the distance between this point and the x-axis.