STRAIGHT LINES 01/SLOPE OF A LINE- DIFFERENT METHODS TO FIND THE SLOPE/CLASS 11/MATHS 1(B)

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[@MPCFRIEND19]

At 00:19:00 its -tan15 but not tan15. In over look i forgot to keep. I regret for that...plz correct while you note it down.

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S sir i observed first onpy while u r explaining. Tq for informing or clarifying my doubt.

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Okk sir

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Sir please addition and product of vectors

[@shravanishravani3417]

🙏Sir..why could we take only tan∅,why don't we have to take sin∅ (or)cos∅ etc.... Could you explain this

[@Teja.B1619]

@@shravanishravani3417 that's a good doubt suppose mee daggara two points vunnayi (x1,y1) and (x2,y2). Then, sin(theta) = opp/ hyp ikkada hyp value enthante sqrt ((x2-x1)^2+(y2-y1)^2) ante distance b/w the points ana maata like wise cos ki kooda denominator lo distance rayali. So using tan avoids that amount of calculation and effort of time consumption. Ade tan teesukunte it will be opp/adj opp = y2-y1 and adj = x2-x1. Meeku cot kooda teesukovachu kada ane doubt ravochu but standard gaa okati follow avvalani tan teesukuntunnaru. Hope you got my point

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Correct ga chepparu

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Sir your explanation of concept is very good.I cleared most of the doubts

[@gireeshkulakarni995]

Slope Concept explanation is very clear with each minute point. Thank you sir.

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Thanks alot sir 🙏🙏 Naku first straight lines ante chala bayam undedi mee video chusaka ayyoo inthenaa anukunnanu thanks sir.. meeru inter 1st yr lo unna chapters anni videos cheyandi sir please 🙏🙏 ..

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Sir, your teaching is very good. Here we observe tan165 degrees equql to -tan15

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