Practice Word Problem: Jay's father is twice as old as Jay. In 20 years, Jay will be | Age Problem

[@syanggingo3263]

Thank you so much sa mga free tutorial nimo Ma'am❤️

[@hermans.rivera2212]

Thanks po maam

[@SisenVlog]

Thankyou po maam

[@frankgarcia4360]

ah nakuha ko pero iba solution, 2/3=0.66, 0.66*20=13.33, 13.33x3(3rd of 2/3)=39.9 or 40 yan edad ng tatay, tapos 39.9➗2 (part ng tatay na katumbas ay eded ni jay) =19.995 or 20

[@joseantonioiiicea8081]

masyadong time cosuming po ito, nagegets ko pano ito gawin pero matagal. sana pahabain pa ng csc duration ng exam, mag add man lang sana sila kahit 15 mins pa sana

[@me-gf4ct]

mam pa explain po nito para sa age problem, Abby is 5 years old younger than Leah. Four years later , Leah will be twice as old as old as abby. find their present age.

[@frankgarcia4360]

2/3 ng edad ng father which is 40 is 20? ano daw? hahaha

[@jcsanmiguel6270]

2/3 after 20 years. 20 + 20 = son's age.40 + 20 = dad's age. in 20 years they will be 40 and 60 respectively. 40 is 2/3's of 60

[@jcsanmiguel6270]

let x be the hours worked by heinrich 14 ( x + 10) + 12x = 3520 14x + 140 + 12 = 3520 26x = 3380 x = 130 Heinrich worked fo 130 hours that month and Wolfgang worked for 140 hours❤