Multiplexer using IC-74153 (Practical Demonstration)

Рет қаралды 23,241

Electronics By Shweta Chadha

Күн бұрын

Пікірлер: 23

@shivtiwari6885 11 ай бұрын

Mam make a video on implementating the boolean function using basic logic Practical demonstration too

@VikramSingh-cr7eq Жыл бұрын

Thankyouuu for making my doubts clear😍😇

@RoshanShah-j9f 10 ай бұрын

Ma'am if min term change like apne 1,2,6,7 kiya... If I will perform with 1,2,4,7 them circuit diagram change' ho jayegi?

@electronicsbyshwetachadha 10 ай бұрын

Yes. Min terms k accordingly c0, c1, c2 and c3 ki values ko calculate karna hoga and ho aapke connections honge.

@electronicsbyshwetachadha 10 ай бұрын

Check this solution kzbin.info/www/bejne/iZTXn5SBmbyihdEsi=pKS2OOsF8rCCe1cL

@Pb36walai Жыл бұрын

Thank🙏💐

@adityarajsingh6870 Жыл бұрын

We want a demonstration of all the experiments, ma'am, please.

@electronicsbyshwetachadha Жыл бұрын

Check this playlist kzbin.info/aero/PLUKuxwFRUnFHOWkx8hvBXYQE357cnatop

@snehasharma68705 11 ай бұрын

Mam pls upload binary to octal decoder practical

@RoshanShah-j9f 10 ай бұрын

Mam using max mapping ..krne se bhi same circuit diagram banegi

@electronicsbyshwetachadha 10 ай бұрын

Agar c0-c3 ki values different aa rahi hai to vohi connections karne honge. Ye sample connections hai given problem k.

@RoshanShah-j9f 10 ай бұрын

@@electronicsbyshwetachadha ma'am Maine min term 1267 liya ... Using max mapping co c1 c2 c3 ko different values mil rhi hai

@electronicsbyshwetachadha 10 ай бұрын

@@RoshanShah-j9f aapka truth table same hi aayega after execution as select lines aapne different variables liye honge. Agar mapping se karna hai to jo b values aa rahi hai c0-c3 ki, connect accordingly same hi result aayega final output truth table ka. This is just the easiest method which I have explained.

@Chaggars Жыл бұрын

Thanks🙏💐

@nothingmuch147 6 ай бұрын

Maam do this experiment with 2 outputs 1 for carry and other for sum

@electronicsbyshwetachadha 6 ай бұрын

Follow the same method. Write down the truth table one for sum and other for carry. Calculate c0, c1, c2 and c3 and then make connections accordingly. Two different connections will be done. One for sum and other for carry.