Perfect! Absolutely loved your clear explanation. Have been struggling with the sigma notation in matrix multiplication for over a decade. Finally got it!
@sirshabiswas30103 ай бұрын
Welcome back, Excellent Teacher! Not to mention but I was genuinely worried about you.
@pedropauloburigobastos3 ай бұрын
Good to see you back!! I really miss the videos, hugs from Brazil
@Mohamed.Soltan19913 ай бұрын
Welcome back 💖💖🌹🌹🌹
@user-wu8yq1rb9t3 ай бұрын
You back ....🎉 Great... Welcome back
@tomkerruish29823 ай бұрын
Welcome back! I was getting worried. Now, how about some cool Ma 108 or Ma 120 stuff?😁
@slavinojunepri76483 ай бұрын
Nice proof
@alipourzand64993 ай бұрын
Nice propf. What about consideting the determonant of the product of two upper triangular matrix which is the product of the determinant. And since the determinant of a triangular matrix is the product of the diagonal, this will imply that the diagonal of the resulting matrix is the product of the diagonals. Is this a sufficent condition to proove that?
@MuPrimeMath3 ай бұрын
You could use the result in the video to compute the determinant of the product of two upper triangular matrices. However, you cannot use the determinant to prove what the diagonal entries are, because there are many possible diagonal entries that could multiply to the same determinant. For example, [[1,0],[0,6]] and [[2,0],[0,3]] both have determinant 6.
@cycklist3 ай бұрын
Long time no see
@alejrandom65923 ай бұрын
First proof is nice, but you can make it nicer by using some notation and using contrapositive