The mathematical form of the multivariate normal (Gaussian) distribution, and five useful properties of this distribution
Пікірлер: 21
@FauzaanSharieff8 ай бұрын
Mr Baker's teaching is very well and clear! And am I the only one who thinks he looks and sounds like Woody from Toy Story?
@debasiskar46626 ай бұрын
Analogy with bivariate is shown very elegantly. Thanks.
@karina_tai5857 Жыл бұрын
Thank you! Concepts are very well-explained!
@aali49574 күн бұрын
Thank You, you helped me understand.
@esmaeilmorshedi35732 жыл бұрын
Perfect, Professor Baker!
@JianaMeng Жыл бұрын
very clear explanation! thanks
@ryanfox2478 Жыл бұрын
Clear explanation. Thank you.
@mlfacts79737 ай бұрын
Great video. Thank you!
@rahul_a225 ай бұрын
After finding so many videos over the topic my research ends here...
@abhinavdaggubelli9912 ай бұрын
But, we can't say anything about the independence b/w two random variables provided the Covariance between them is zero, right? Then how is 4th property working? Can you clarify please.
@sirkelvinmalunga11 ай бұрын
thank you!
@ks.44947 ай бұрын
Important concepts, clear explained! thanks
@klevisimeri6078 ай бұрын
Thank you!
@user-hr8uj4qw4k7 ай бұрын
Is there a way to derive the marginal pdf of each component X_i without resorting to the moment generating function?
@ankursingh55552 жыл бұрын
Thank you
@mohamedelmoghrabi51693 ай бұрын
Is it possible for a PDF copy of the lecture
@spyhunter00662 жыл бұрын
How can we get for n random x values in one data set , n mean values? I mean if I have a data set with Gaussian shape, shouldn't have only one mean and sigma. Bu the way, I have a histogram showing counts per channel up to 1024 channels for instance. The example you gave at the minute of 13.14, how would you construct it if you had one mean and one sigma but a vector of random variables as in my example I tried to explain above? (instead of having the mean and Sigma matrices) Actually, in that exmple at the minute of 15.00, you decided to change x matrix having x1 and x1 variables to x (underlined matrix with x1 vector and x2 vector . That confused everything.
@berke-ozgen10 ай бұрын
I hope this answers: In X vector, we have x1, x2 and so xn. These xi variables also a vector containing numbers. So X is initially a set of random vectors. Then you will have different mean values for each x1, x2 and so xi.
@inaswulanramadhani4036 Жыл бұрын
Excuse me, sir. Thank you for the video. But I don’t understand yet. Can you please give us an example about how to find variance and covariance of random vector, if expected values is real number?
@berke-ozgen10 ай бұрын
For variance, you need to construct an E[(X-E[X])]. E'[(X-E[X])] which is the second moment. This will give Var[X]. For the cov[X,Y], you should calculate E[X-mx, Y-my] .E'[X-mx, Y-my] (be careful because this includes Transpose.) Then you will have nxn matrix ((nx1) x (1xn) matrix gives nxn matrix). The diagonal of that matrix will include variances of each vector and the other terms are just covariances between related xi and yi. (m for mean) Hope that clears!