SSC CGL, SSC GD, RRB ALP | Pipes & Cisterns | Maths Topic Wise | Adda247 Tamil

[@Mani_0798]

answer for homework sum is OPTION C = 45 MINUTES. P=12(5) R=15(4) M=6(10) P+R-M = -1 P AND R opened for 5 mins= (5+4)* 5 =45( WORK) now all pipe opened so, every one minute 1 litre emptied by A+B-C EMPTY TIME = WORK/ EFFICENCY = 45/-1= 45mins (C)