Algebra 67 - Deriving the Vertex Form of a Quadratic Function

The graph of a quadratic function in a single variable is always a parabola, and when the function is written in vertex form, we can identify the coordinates of the parabola's vertex simply by looking at the function. But how is the vertex form derived and why does it work? The process explored here involves shifting or 'translating' the basic quadratic function "a x-squared".

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i'm from Brazil, I've appreciated your lectures. thanks professor Von Schmohawk

[@coffeedesbeans]

This is an awesome way to learn algebra.

[@newgood0137]

I would like to know how is the vertex formula -b/2a derived?

[@Bedoroski]

In calculus, such a point is called an extrema. The x coordinate of the extrema is given the equation y'=0, where y' is the first derivative of our function f(x)

[@aaaaaaaaryan]

Nice animation.

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Why we using (scaled) x and y unit vectors here : 8:45 ?🙂

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Can you make a video about sinusoidal functions? I love your videos and learn from them somehow better than my math teacher who has to go at a pace that incidentally, reflects a sinusoidal function.

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We will be covering trigonometric functions in later lectures. But we still have some mathematical ground to cover before we get to that topic!

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MyWhyU Do you have a list of the episodes for trig and algebra?

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The playlists of Why U Algebra and Pre-Algebra videos include only the chapters which have been published so far. These lists can be found on the MyWhyU KZbin channel page and on the Why U website www.WhyU.org.

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MyWhyU Do you have a copy of the planned episodes?

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Thank you So much

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thank you

[@eksnq7660]

x^2=y √y=x And y=(x-3)^2 √y+3=x Conclusion- so"x" shifts 3 positive units

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Can you make a video about simultaneous equations?

[@MyWhyU]

Algebra chapters 35 through 63 are all on simultaneous equations!

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