Swap two Strings without using temp/third variable - Java Interview Questions -9

Swap two Strings without using temp/third variable:
Algorithm:
1) Append second string to first string and
store in first string:
a = a + b
2) call the method substring(int beginindex, int endindex)
by passing beginindex as 0 and endindex as,
a.length() - b.length():
b = substring(0,a.length()-b.length());
3) call the method substring(int beginindex) by passing
b.length() as argument to store the value of initial
b string in a
a = substring(b.length());
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[@nibeditajinu]

Seen some of your videos.. There are other KZbinr who explained these concepts But Must say this - The way you explain ,is extraordinary, it just get typed into memory ( human Lol) and never get erased

[@ckumar89]

one more: s1=s1+s2; s2=s1.replace(s2, ""); s1=s1.replace(s2, "");

[@uyghurfilms3450]

How many “thank you “ is enough for your efforts? Lol thank you from my deep heart

[@soumyacc4209]

Hi Naveen, Your videos are amazing and worth watching. It gives more confidence to viewers and helps a lot to attend any interviews and apply this concept in real projects. Your framework videos are just WAW! and your way of breaking and explaining the concepts is beautiful. My best wishes to you.

[@sahilkhenat1817]

I wrote little different logic by using strip function in Python and it worked. #Swap StringsPython a = "hello" b = "world" print(a,b) a = a+b difflength= len(a) - len(b) b = a[0:(difflength)] a = a.strip(b) print(a,b)

[@pradeepb6914]

Thank you Naveen for your efforts. Solution of above using replace function String s1 = "Hello"; String s2 = "World"; // Using replace s1 = s1.concat(s2); s2 = s1.replace(s2, ""); s1 = s1.replace(s2, ""); System.out.println(s1 +" | "+s2);

[@amitmoolchandani8945]

this will not work when s1 = "HelloWorld" and s2 = "World"

[@sruthitenneti3821]

we can use replaceFirst instead of replace

[@Itsme1n1ly]

Nice edge case ❤

[@hi-ks4rl]

More interview java videos will be useful.your approach is very easy to understand.

[@artimandale8286]

Amazing explanation, thank you Naveen

[@durdonatursunova292]

Hi Neveen, Thank you for your time. All videos are very useful.

[@SmartProgramming]

helpful tutorial, thank you, keep it up 👍👍👍👍

[@gauravakash8237]

one more String a= "akash" String b= "Gaurav" System.out.println("The new value of a will be " + b.Substring(0) ); System.out.println("The new value of b will be " + a.Substring(0) );

[@priyankagoel4448]

Thank you Naveen ,it's really helpful

[@clearaj710]

Can you please explain a program which is checking the drop down string values are in alphabetical order?

[@elkememet701]

Thanks

[@kalaimohan5421]

Thank u

[@sunilreddymallela]

Why css selector is faster than xpath , if it is fast why most of the automation engieers are preferred to write mostly custom xpath in place of custom css selectors

[@sajindraprasad]

Sunil Kumar Reddy Mallela css is faster but using css selector we cannot navigate forward or backward inside Dom.So xpath is used in this case

[@samshoaib6871]

One More Way ;-) String a = "Hello"; String b = "World"; System.out.println("A: "+a); System.out.println("B: "+b); a = a+b; b=a.substring(0, 5); a=a.substring(5, 10); System.out.println("A after swapped from Hello to: "+a); System.out.println("B after swapped from World to: "+b);

[@ashwinib5017]

This solution will work only if both strings is length 5 , Naveen s solution works for any string length

[@Itsme1n1ly]

It's not Scalable