NECO 2020 Question 3 | Addition of binary numbers

Neco 2020 problems and Solutions

[@Healthwithharry]

The 1st person to clearly demonstrate the process..African bro

[@gospelfloww]

Thankyou very much! Blessings from England 🙌 🙌 🙌

[@FatimaMajid-m4s]

You are really a good explainer.

[@VincentThabiso-ec4fr]

U a great tutor I ever seen❤

[@gladyschinyere7834]

Thanks alot Mr Tambuwal. You really explained this very well after watching lots of videos about this. Yours is the best

[@ajouajou845]

Thank you so much from South Sudan

[@acitynewsafrica7182]

Perfect explanation

[@dongamer5235]

Oh thank you so much i was having dout in this sum now it's clear

[@SameyJanice]

Wow great teacher good bless you

[@user-ek9jh2we5k]

thanks a lot

[@promiladevi7748]

Thanks from India

[@user-sh6wp4wq8n]

Thank you very much

[@Ahmad-Alamin]

Thank you, and thank you once again.

[@precioustoluwalope1585]

Thank You very much for this

[@aurora0534]

Thank you sir . From Sri Lanka

[@tambuwalmathsclass]

I appreciate it

[@bornifacewanjala4022]

Thanks sir for the tutorial

[@JESSIESUMANI]

Thank you sir

[@anycyclopedia]

THANK YOU!!!

[@asifnadeemasn5700]

Thanks sir

[@billionairegregory4651]

Thanks 😊👍

[@ekpeowai27owai65]

Cool

[@hassanlawal4855]

I do Appreciate it sir

[@tambuwalmathsclass]

🙏🙏🙏

[@eodjdmcars7781]

Wby subtraction? With 3 digit?

[@user-it4uc5cv4x]

What of if it's 10111,1101,111 how do I go about it

[@herbcruz4697]

Here's an alternate way to approach this problem. 2^4 2^3 2^2 2^1 2^0 1 1 0 1 1 = 2^4+2^3+0+2^1+2^0 = 16+8+0+2+1 = 27 11011 (in Binary) is equivalent to 27. 2^4 2^3 2^2 2^1 2^0 1 1 1 1 0 = 2^4+2^3+2^2+2^1+0 = 16+8+4+2+0 = 30 11110 (in Binary) is equivalent to 30. In the Base 10 World, we would have 27 + 30 = 57. Now, we can convert 57 to Binary. 2^5 2^4 2^3 2^2 2^1 2^0 1 1 1 0 0 1 = 57 = 32+16+8+1 = 2^5+2^4+2^3+2^0 Hence, in Binary, 57 is equivalent to 111001, which is the final answer to this problem.

[@tambuwalmathsclass]

I have a complete guide on the whole topic, but for the question I solved this is not the right approach as it takes more time and space. But it's preferable when the bases are different.

[@acitynewsafrica7182]

Perfect explanation