Elimination of Left Recursion - Solved Problems

[@nikita3543]

Bro is really coocking, he able to exmpain everything he do.

[@martian0x80]

I had a stroke reading this.

[@Zaky-ne7zi]

​@@martian0x80I stroked while reading this

[@yahiabouda]

Thank you for the simple explanation!

[@sajjadsaiyed9636]

Thanks for the best explanation ❤

[@Forever._.curious..]

Thankss for making it up reasonably well

[@osamozilla7898]

Thank you, just thank you! You're INCREDIBLY good to explain, just THANK YOU!

[@MaxPicAxe]

your videos are really good

[@sanskruti2908]

thank you so much!! I've been meaning to understand this since forever

[@anushkabhatnagar3642]

Thank you

[@tanjack9484]

Hello, your videos are superb, when will the rest of the course be updated please? Also, can your courses be transferred to Chinese video sites?

[@vijayalaxmiyalavigi6232]

Thank you sir for such a nice explaining

[@darknunmul8149]

Thank you for making it seem so easy

[@radmehrtalebi6818]

great video it would be great if you do one for not immediate left recursiveness

[@MarthalaPadmaja]

Nice session 🎉

[@sudhanshusumanprasad1022]

Please create a similar playlist for bottom-up parser as well.

[@nesoacademy]

This chapter is already uploaded, please follow the link www.nesoacademy.org/cs/12-compiler-design

[@birukgetachew9084]

thank you so much for this video

[@nizamfarooqui5950]

Yiu doing great job thank you soo much ✨❤️

[@samerkeyrouz3160]

Thank you so much

[@sarahmedouni8844]

is 3:03 correct? i feel like that formula is not enough to cover the first grammar as the first grammar can derive a string of terminals and the second can't what am i missing?

[@mountainace6296]

i don't see how the first one is correct either, shouldn't it be p→q + p ∣ q

[@lezhu6856]

It still can, just produce epsilon with the second production when needed. That epsilon is the important part.

[@LipishaGupta]

Too good!

[@alphasciencetutor1252]

just perfect

[@sandipsinha2537]

Good tution

[@RealArashKH]

Is it possible to save the collection of entire alpha ( {a1,a2,a3,..} ) and beta ( {b1,b2,b3,...} ) in two new non-terminals ? so i would have to extra rules of B--> b1,b2,b3,... and have my A grammar rule as : A --> BA`

[@abhishekvanenooru2869]

Super anna

[@jamessmith-zu1ix]

can u just write it like this ? A-->α*A' instead of writing α1 α2 α3

[@asheshkumarrath9927]

Hari hari