I figured out the 2Idc^2 part. In Idc*I, Idc is a constant so it will come out of the integration. Now write I as Iac+Idc. Integration of Iac will be zero over a full cycle. Hope it helps. This is also why the average value is Idc.
@darshansonagara57596 жыл бұрын
thanks....
@dwinovianto12506 жыл бұрын
but this case is for half wave rectifier right? so the integration of Iac in full cycle isnt zero.
@apooravsingh63746 жыл бұрын
Yashodhan Manerikar thanks
@yajashgoplani67906 жыл бұрын
iac would not be 0 because we take the mode of integration it will add the mag. of +ve cycle and -ve cycle
@bickyou46965 жыл бұрын
@@dwinovianto1250 it isn't exactly 0,but it's small when compared with other terms.
@harjitkaur67296 жыл бұрын
As Idc is constant , Idc(2/2π) integral 0 to 2π I(dwt) To solve :- Integral 0 to 2π I(dwt) 0 to π I(dwt) + π to 2π I(dwt) As for half wave rectifier π to 2π I(dwt) =0 We only left with 0 to π I(dwt) As I=I' sin(wt) Where I' is peak value of output current Such that Integral 0 to π I d(wt) become integral 0 to π I' sinwt d(wt) I' is constant Therefore by integration of sin(wt) we get (-cos wt ) and putting the limits we get value is 2 Thus the value of Integral 0 to 2π I (dwt) = 2I' Thus final value we get is =Idc(2/2π)2I' =Idc(I'/π) As I'/π=Idc ( average value of output dc current) Therefore we get at last is (Idc)^2 🙂🙂
@kanchan9052 жыл бұрын
Thank you 😊
@harshdeepjaywant96572 жыл бұрын
thank you
@santhosh4832 Жыл бұрын
thank u
@studentofcollege8 ай бұрын
thanks a lot
@LeviAckerman-kk2ieАй бұрын
Thanks a lot dude
@LastGladiatorStanding3 жыл бұрын
Integration of I² from 0 to 2π wrt (wt) divided by 2π is (Irms)². "Integration of I from 0 to 2π wrt (wt) divided by 2π is Idc. " :quoted part Written in Millman's electronic devices and circuit page 6.8 Thats explains the third part of the integration. Note:" I " here is output Aslo, Idc=Iav
@KabooM10676 жыл бұрын
I just want to say your channel is a blessing on KZbin. Every time I need to quickly revise a topic I always find your videos. Well organized and comprehensive. Thank you so much for all the work.
@avunoorisaiayushman43993 жыл бұрын
For everyone who is asking how I×I(dc)=I(dc)^2 Since I & I(dc) both are constants we can take I(dc) out of integration then the remaining integration containing only "I" is the formula for I(dc) . Therefore it gives I(dc)^2
@hichembenamara47107 жыл бұрын
in the integration of the last term , we consider Idc as constant , so we have inside the integral I*Dwt and it give us Iav which is equal to Idc , so the result is 2*Idc^2
@shoebemail8 жыл бұрын
Integrating I.Idc, how you got I^2dc?
@محمدمنير-ق4ص6 жыл бұрын
he assume that Iac=0 so I=Idc+Iac=Idc+0 thereby , I=Idc that is what i know
@yajashgoplani67906 жыл бұрын
so we can apply that in 1st integration to. i don't think you are correct
@ranulabewardana59966 жыл бұрын
How can F.F=I(rms)/I(dc) when in the last lecture Form Factor was defined as F.F=V(rms)/V(av)? Didn't understand how you got I(dc) as 'Average value of output'?
@trishuverma59294 жыл бұрын
How you got 121% percent of ac component,I think it can be greatest for AC and it should be 100% for that,so how rectified output has more AC component??
@palmaya419610 ай бұрын
Doing great job guys,taking all points short and crisp factor.
@NonCnse6 жыл бұрын
In the Idc*I integration, Idc is constant so its left out..leaving the integration of I.dwt..now that is equal to the average value of I which is also the dc component i.e Idc. Therefore integration of I.dwt=Idc.. giving us Idc^2 after multiplying with the Idc constant..
@collegetv79866 жыл бұрын
thanks bro
@123playwright5 жыл бұрын
Thank you!!
@MohdSameer-so9bt4 жыл бұрын
thanks bro
@97yogita5 жыл бұрын
Sir, you are a saviour. Thanks a lot for making these videos. We owe you a lot.
@mahmoudmohsen34728 жыл бұрын
how could you get I(dc)^2 from just multiplying I times I(dc) -in the third part of integration - ?
@ayushkumar-xk7kp3 жыл бұрын
I=I(ac)+I(dc); I(ac)=I(m)sin(wt); If you integrate sin over its period it results in 0. So integration over I(ac) is 0 and we're left with I(dc) component of I
@prateekapurva34643 жыл бұрын
@aayush Thank you very much
@abhishekkumaryadav19283 жыл бұрын
@@ayushkumar-xk7kp dont try to fool them.. his doubt is correct.. it cant be 0 because.. in positive half cycle it doesn't comes out to be zero
@ayushkumar-xk7kp3 жыл бұрын
@@abhishekkumaryadav1928 I may not be very clear in explaining, but integrating I(ac) over its period will result in zero. Please refer to the definition of alternating voltage, it periodically varies its polarity and changes its magnitude continuously. So whether you consider sinosudal or rectangular or triangular signal, Its Integration over its period will come out to be zero. Also I(dc) may or may not be a constant wrt time, A pulsating voltage may also be dc, refer to wikipedia if necessary.
@ayushkumar-xk7kp3 жыл бұрын
@@balaji2.095 first of all the integral will be -cos(wt)/w. (Though it doesn't matter) And after you put limits the integral will vanish(1-1=0) the
@santhoshthota47784 жыл бұрын
Doubt at 6:01 goes did you get it And how will the percentage be 121 generally percentage men's out of 100
@nageswarrao28484 жыл бұрын
Sir in the last lecture you didn't told about form factor =I RMS/Idc.in you told FF=V RMS/V avg
@nageswarrao28484 жыл бұрын
Please anyone help me
@Kanekikenn9993 жыл бұрын
Same doubt
@vedantbrahmbhatt51753 жыл бұрын
@6:02 integration you are directly writing , I am not getting it ! how Idc square comes ?
@sayantankundu99036 жыл бұрын
In the last lecture you told that rms value of ac is equal to the value of dc. So in this lecture how is av o/p current(Iavg) taken as Idc i.e (Iavg=Idc)? According to the last lecture rms o/p current(Irms) should be equal to Idc i.e (Irms=Idc) right? This is proving that Irms and Iavg is equal which is not equal in practice. Please help.
@abhishekkumarsingh55965 жыл бұрын
No he told rms value is the value of supply so that the supply would give power or brightness to lamp connected to it
@aditipandey69644 жыл бұрын
initially even i was confused,then i came to know that average value is equivalent to dc component of current since the opposing peaks of the ac components get cancelled out
@mohamedkalith76073 жыл бұрын
@@aditipandey6964 how Iav= Idc?
@sheruloves91905 жыл бұрын
Sir, How come avg. Value of output is Idc?
@hm27153 жыл бұрын
@Vinay Kumar Reddy ❌
@hm27153 жыл бұрын
@Vinay Kumar Reddy Thankyou, I understood 85% of what u said..
@hm27153 жыл бұрын
@Vinay Kumar Reddy Which year student U r??? U have good knowledge.. Fourier series is currently going on in our class.
@sayanchakraborty31143 жыл бұрын
@Vinay Kumar Reddy sine waves int. become zero when we consider the int. from 0 to 2pi but in rectified output ac component exist only for 0 to pi range then it becomes dc then again ac component arises from 2pi to 3pi so i am a bit confuse about your explanation
@sayanchakraborty31143 жыл бұрын
@Vinay Kumar Reddy yes i had Fourier in my last semester but how far I understand is we cancel sine part when we calculate the avg from 0-2npi. But here in output we get a sine wave from 0-pi then a straight line(dc part) from pi-2.pi ....
@vijaylaksmikulkarni83236 жыл бұрын
sir u said RMS value is equivalent to the value of effect created by dc value..but in derivation u have replaced the dc value by AVG value..:( please make me to understand
@kayesbinyousuf11574 жыл бұрын
I can't understand the same point ...how can you replace the avg value with dc value ? Sir please explain it...
@zizogo34178 жыл бұрын
can we find the Ripple factor also with Voltage?
@sayanchakraborty3114 Жыл бұрын
in an earlier video you said that 5v rms ac will glow a bulb equivalent to that of 5v dc but here ratio of I(rms) / I(dc) is not 1, I(dc) seems to be equivalent to I(avg), Why so?
@ayushkandpal46002 жыл бұрын
Heat generated in time T is heat generated for T/2 plus zero hence it comes out to be v/2
@SarthakGupta2598 жыл бұрын
I can't understand how can the ripple factor be more than 100%. Ripple factor is the percentage of AC in the output, so if you're taking the entire output to be, say, 100, how can the AC component in that output be 121? I googled it but coudn't find any explanation. Please explain
@shubhammaniyar427 жыл бұрын
ripple factor is the ratio of % of AC comp in output to the DC comp. AC comp is 121% of the DC value not the entire value. Hope it helps.
@SarthakGupta2597 жыл бұрын
shubham maniyar yes I'd figured that out before my exam. Thanks anyway :)
@harendrasingh_227 жыл бұрын
Oh. Great thanks guys for solving my doubt !
@kaushikbudi69586 жыл бұрын
shouldn't it be rms value of ac component
@udaykiranjadhav51692 жыл бұрын
sir how avarage value of the output will be Idc ??
@127_aqibnabi43 жыл бұрын
Thank You Sir
@puneetray40454 жыл бұрын
How we get - 2 I^2(dc )??
@agulpofviralthings87427 жыл бұрын
I didn't get the 3rd part of the integration which you skipped. Please explain that.
@praveenmishra91277 жыл бұрын
I is a sum of iac and idc for 0 to 2pai interval Av of iac is zero but integration of IDc over dwt in intervel o to 2pai is 2pai into idc.
@jyotipoly4 жыл бұрын
Conversion efficiency of half wave rectifier should be ratio of dc power output on secondary side to ac input power on primary side,which comes to approx. 20 per cent......in your video efficiency is ratio of dc power output at load ,to ac input power at load ,which is 40percent,..... please shed some light on definition of efficiency and why this discrepancy
@ShwetaSingh-di4ik5 жыл бұрын
Sir ur videos are great!!!!
@sahilmakwana78656 жыл бұрын
Thanks a lot sir
@azerahmed6195 жыл бұрын
You are the only man in whole KZbin and google who described every step of derivation at best way.... May Allah give you more knowledge and success in your life
@geethach55965 жыл бұрын
Very good explaination thank you bro
@suryanarayankumar73236 жыл бұрын
Hi sir,thanks for such a helpful lecture....bt i m little bit confused .....how the average current is equal to Idc(output has also ac current)......
@lokesh314155 жыл бұрын
Average value represents - DC content present in the AC (That's why av. value is zero for pure AC), RMS value represents - DC equivalent of AC content. am I correct?
@sahilmakwana78656 жыл бұрын
Can you have any videos about full wave rectifier??
@shwetagautam34936 жыл бұрын
well explained sir!! 😍
@pratikkamble78014 жыл бұрын
Hii sir i am preparing for ese.. in ESE exam have they asked derivation of any of these ????
@RahulRaj-dj9uh6 жыл бұрын
IN Last lecture you told that I(rms)=I(dc) value but in this lecture you are telling that I(av)=I(dc) i am confused now ...!!!!! Help somebody.....!!!!!!
@mohamedkalith76073 жыл бұрын
@Vinay Kumar Reddy what do you mean by DC component of the wave?
@mohamedkalith76073 жыл бұрын
@Vinay Kumar Reddy I don't understand yet...can u please elaborate that Fourier series part
@aditijain71687 жыл бұрын
sir...i did not understand how u integrate I Idc d(wt).....3 term
@harjitkaur67296 жыл бұрын
As Idc is constant , Idc(2/2π) integral 0 to 2π I(dwt) To solve :- Integral 0 to 2π I(dwt) 0 to π I(dwt) + π to 2π I(dwt) As for half wave rectifier π to 2π I(dwt) =0 We only left with 0 to π I(dwt) As I=I' sin(wt) Where I' is peak value of output current Such that Integral 0 to π I d(wt) become integral 0 to π I' sinwt d(wt) I' is constant Therefore by integration of sin(wt) we get (-cos wt ) and putting the limits we get value is 2 Thus the value of Integral 0 to 2π I (dwt) = 2I' Thus final value we get is =Idc(2/2π)2I' =Idc(I'/π) As I'/π=Idc ( average value of output dc current) Therefore we get at last is (Idc)^2 🙂🙂
@mohamedkalith76073 жыл бұрын
@@harjitkaur6729 finally we have Idc(2I'/π). How Idc(I'/π) ???
@zizogo34178 жыл бұрын
Thanks Bro!
@niranjans13755 жыл бұрын
There's a mistake in the final calculation , it's 1.1 not 1.21 , you probably forgot a bracket while using the calculator
@shivamkashyap15434 жыл бұрын
But i think that it comes 0.57 instead of 1.21 or 1.1
@niranjans13754 жыл бұрын
@@shivamkashyap1543 it's 1.1 dude, I think it's written in R Murugesan's modern physics, not sure, but the final value is 1.1.
@vijaylaksmikulkarni83236 жыл бұрын
please some one explain me the clear difference between the RMS value and AVG value
@dwinovianto12506 жыл бұрын
Im sorry sir, in 6:06 How did u get 2(Idc^2) cz depend on my note should be 2I(Idc) thanks anyway.
@rameshakhila68026 жыл бұрын
exactly... , have the same ques too
@yaswanthbandaru22355 жыл бұрын
we'll take Idc outside as a constant I = I av + I dc but integration of I av through complete circle is zero then ...
@Vermasir113926 жыл бұрын
Thanks sir
@Vermasir113926 жыл бұрын
L type LC filter? ?
@naurin62157 жыл бұрын
thanks for ripple factor theory
@preetichauhan83856 жыл бұрын
I don't understand ripple factor
@Vince02088 жыл бұрын
Please explain 6:05 further. the third expression inside the square root. thanks
@rassulbolatkanuly38448 жыл бұрын
I didn't quite get how to do the integration of the part you skipped
@rassulbolatkanuly38448 жыл бұрын
The part with 2/pi integral from zero to 2pi of ( I*Idc *d(wt)) at the minute of 6. 02
@Vince02088 жыл бұрын
i didn't get it too
@abdoyasser58058 жыл бұрын
integration from 0 to 2pi of ( I * dwt ) / 2pi = Im / pi = Iav = Idc , as for mixed signal Iav represent dc current
@saraswatisharma78617 жыл бұрын
what does the mixed signal means
@youmah256 жыл бұрын
it's the average value of the ripple current I witch is equal to Idc
@sonusambharwal88285 жыл бұрын
Best sir...
@darshansonagara57596 жыл бұрын
what is differance between RMS and AVERAGE value....???????
@youtubeuserlovesyoutube2207 Жыл бұрын
Can anyone explain what is meant by ac and dc component of output current?
@phetolomalele85237 жыл бұрын
I dnt understand how u integrated 2*(I total)*(I dc)
@shwetagautam34936 жыл бұрын
well expained😍
@laasyayeluri36656 жыл бұрын
Can we take Iac=Idc sin(wt)
@culturechannel46135 жыл бұрын
Ripple factor is equal to Vp-p\Vavg
@nitinreddy44213 жыл бұрын
sir how the does output current have both ac and dc current?
@mohamedkalith76073 жыл бұрын
I too have the same doubt
@mohamedkalith76073 жыл бұрын
You never answer to the comment section, then what is point of asking us to comment here?
@LinoAckenjiro20 күн бұрын
this video was posted 8 years ago mate . he isnt gonna answer .its common sense
@alterguy43277 жыл бұрын
Thanks :)
@UBEPRADEEPTASEN2 жыл бұрын
sir can you just increase your voice a little bit? its amazing to learn from you
@jananisubash63774 жыл бұрын
Can somebody please tell me how to derive the voltage regulation of half wave rectifier, full wave center tap and full wave bridge rectifier? Plz plz plz
@nageswarrao28484 жыл бұрын
This video not properly understanding.sir please make one more video on this topic
@nothingspecial45 жыл бұрын
Can anyone tell me how I.Idc is equal to 2Idc sqr ?
@tapobratdas16274 жыл бұрын
This is so perfect !!! 😍
@phymath-jisanislam96397 жыл бұрын
Anybody understood the 3rd part of the integration!
@harendrasingh_227 жыл бұрын
121 or 12.1?
@physicsim-possible630 Жыл бұрын
121℅ of 200℅ or what I'm confused121℅ of 200℅ or what I'm confused how it can be more than 100℅ how
@hostel..vibs.2 жыл бұрын
Studying just for my mdcat exam held by pmc😂🤣👍
@praveenmishra91277 жыл бұрын
I is sum of iac +idc av of iac for 0 to 2pai is zero.
@sheruloves91905 жыл бұрын
Bro, wonderful. Got it!
@praveenmishra91277 жыл бұрын
I is sum of iac and idc and av of iac is zero but average of idc is idc
@praveenmishra91277 жыл бұрын
av of Idc is idc because idc is constant but in rectifer av of iac is zero because we want only constant supply that is over requirement.