Dominant Pole (Solved Problem)

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Neso Academy

Neso Academy

Күн бұрын

Пікірлер: 42
@ojhamridul2552
@ojhamridul2552 4 жыл бұрын
1:10 Let me know who got 'c' as answer. I was confused for rest of video. We were played. 😂🙏
@piyushsoni4100
@piyushsoni4100 4 жыл бұрын
Many students solve and get c as the answer and feel happy. The confusion is clear at the end, I hope!
@ojhamridul2552
@ojhamridul2552 4 жыл бұрын
@@piyushsoni4100 yes making mistakes help understand better and this also makes sure students do remember the concept. Thank you !!
@TheChargingCap
@TheChargingCap 3 жыл бұрын
crystal clear as usual! kudo Neso academy!!
@DarkWolf887
@DarkWolf887 3 жыл бұрын
AMAZING. THANKS!!!
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
Solved problem? More like "More videos? Let me go watch 'em!" Thanks again for making and sharing so much great stuff.
@insanebatchmemoriesbunch680
@insanebatchmemoriesbunch680 4 жыл бұрын
Sir plz do vedios on c++ and python sir.and thank you very much for ur helping nature to all category people
@ChandanKumar-pu5wz
@ChandanKumar-pu5wz 4 жыл бұрын
Please make some videos on compensation networks.
@sanskarkumar6484
@sanskarkumar6484 3 жыл бұрын
thanks Sir🙏❤
@aaka7777
@aaka7777 4 жыл бұрын
In the neso academy app in fuel can i get full course of data structure .reply me please 🙏 In c and CPP.
@piyushsoni4100
@piyushsoni4100 4 жыл бұрын
You will get everything in the app with Neso fuel, the playlists are updated on a regular basis.
@aaka7777
@aaka7777 4 жыл бұрын
@@piyushsoni4100 Actually this course is complete till linked list only. So my doubt is that when i take fuel than full course would be available or lec would be uploaded on daily basis.
@mohamedabdulraseethma9568
@mohamedabdulraseethma9568 3 ай бұрын
Is this included in gate ee syllabus?
@northern4953
@northern4953 4 жыл бұрын
will you cover state space?
@piyushsoni4100
@piyushsoni4100 4 жыл бұрын
Yes
@arnfinos
@arnfinos Жыл бұрын
You call it the transfer function, meaning the Open loop transfer function? It always gets me confused whether it is the Open-loop or the closed-loop that is being considered.
@pbeee2417
@pbeee2417 Жыл бұрын
Thank you
@vinodkumavat8437
@vinodkumavat8437 4 жыл бұрын
thanks🔥
@peterumezinwa5910
@peterumezinwa5910 28 күн бұрын
How did the numerator change from 5 to 1?
@Dragon_Slayer2431
@Dragon_Slayer2431 12 күн бұрын
it was written in G(s) = K(1+ts)......./(1+ts)...... in this form (s+5) becomes 5(s/5+1)..... this 5 cuts the 5 in numerator
@zahidansari9745
@zahidansari9745 4 жыл бұрын
After removal of the term(s+5) how the DC gain become 1? If anybody know the solution of please let me know Thanks
@piyushsoni4100
@piyushsoni4100 4 жыл бұрын
DC gain of the system was always 1.
@theprophetspath9929
@theprophetspath9929 4 жыл бұрын
@ how numerator changed to 1
@himanshumehta3569
@himanshumehta3569 3 жыл бұрын
Dc gain is calculated before converting into lower order approximations. So first we calculated DC gain then we removed s+5
@soumyaghosh4126
@soumyaghosh4126 3 жыл бұрын
@@piyushsoni4100 when u r eliminating (s+5) from denominator they why didn't u write 5 in numerator ?? please explain where did that 5 go in the numerator while eliminating the insignificant term??? Please do reply
@surajtakale
@surajtakale 3 жыл бұрын
in (s+5) put s=0 .. magnitude 5 cannot be neglected hence 5/5 = 1
@theprophetspath9929
@theprophetspath9929 4 жыл бұрын
Why you removed 5 on numerator.... Only (s=-5) was insignificant pole
@surajtakale
@surajtakale 3 жыл бұрын
in (s+5) put s=0 .. magnitude 5 cannot be neglected hence 5/5 = 1
@cgogoi8952
@cgogoi8952 4 жыл бұрын
DC gain of =5/((s+5)(s²+s+2)) Also TF after neglecting insignificant pole. Thanks in advance.
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
The DC gain should be a number, i.e. it shouldn't have any s's left in it. If you plug s = 0 into the TF, you should arrive at the correct DC gain.
@andrewmelean8259
@andrewmelean8259 2 жыл бұрын
Awesome!
@risingking7724
@risingking7724 3 жыл бұрын
Why are you comparing the ratio to 4? Where did u get 4 from?
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
He uses two criteria in order to approximate the system without an insignificant pole. First, the ratio of the insignificant to significant poles has to be at least 4, and second, the DC gain of both the original system and the approximation need to be the same. I'm not sure if different sources use different ratios as a cutoff, but I imagine they might.
@syedmuhammadqasim1494
@syedmuhammadqasim1494 3 жыл бұрын
Thankyou!!!!
@cornilliousmagoche290
@cornilliousmagoche290 Жыл бұрын
thanks to you
@raghuveermeenasir4676
@raghuveermeenasir4676 9 ай бұрын
Thanks sir
@vigneshkannar5733
@vigneshkannar5733 3 жыл бұрын
Hey for (s+5) the pole is -5 and for (s-0.5) it should be 0.5. But u took -0.5 as pole. Can u tell why u took -0.5 as the pole instead of 0.5 ????
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
He got the other two poles by using the quadratic factor on the s^2 + s + 1 term. He goes through the derivation at 1:39.
@mohansai6922
@mohansai6922 4 жыл бұрын
Please resume aptitude videos lecture waiting here. Please sir.:)
@nesoacademy
@nesoacademy 4 жыл бұрын
Editing is going on, you will have the next videos this week.
@PoojaSharma015
@PoojaSharma015 2 жыл бұрын
I loveit
@JonakSon-jv8eb
@JonakSon-jv8eb 2 жыл бұрын
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