Emitter-Follower Configuration (Part 2)

[@himanshu6489]

you're the ONLY hope of our future in analog🙏

[@DeltaSigma16]

Ha ha ha :), your are completely wrong !

[@shaugaturrahman5840]

What's your position after four years..?

[@himanshu6489]

@@shaugaturrahman5840 a software developer

[@learnwithsomaya6758]

@@himanshu6489 ☺☺

[@Dhayanandhan_S]

​@@shaugaturrahman5840what's your position now plz tell

[@swmicmajumder2168]

From input side, RB is in parallel with B*re and B*RE connected in series So input current is the total current Output current is current through B*RE From current divider rule, Ai = RB / (B*(re+RE)+RB) Here B* is Bita and only B is subscript. I will be happy to correct my answer if i am wrong.

[@manojsahoo6100]

Can u make a video on that homework part

[@xiaonan238]

U save me so many times,thank u for creating so many awesome tutorials

[@adityavarma1082]

Thank you so much for one of the best lectures series

[@osamamohamed5609]

Thanks very much u r awesome But what is the value of Ai Is it Zi/RE or Zi/re ?

[@balasubramaniam5659]

i have to hand it to you. Excellent explanation.

[@aryankumar87771]

Sir aap naa hote to Mai fail ho jata ... On the contrary Aap Hain to Mai branch mein top karta hu.. Midsem mein 27/30. 🙏🙏

[@rasaqatandaalao1325]

May Almighty God reward u. Thank you

[@basedbarman]

Ai = Rb/[Rb + B(re+Re)] and when we consider the output resistance of the transistor in re model not equal to infinity and some large value. still the value of Zi, Zo and Av remains same as there is no term of Ro involved in those equations.

[@rudrakalyan4567]

Thank you sir

[@王永勳-x3t]

thank you!!

[@PRAVEEN_RAJ.]

Ai=Io/Ii Io=Vi/Re li=Vi/(re+Re) But Re>re So Ii=Vi/Re Then Io=Ii Ai=1

[@mohitagrawal8500]

sir you are great

[@priyashrivastava2230]

Sir ur lectures r awesome but plz provide homework problem solutions atleast provide correct answer

[@anujmishra8766]

sir, i have a question?? will u able to cover all the topics of analog before 15th of january???

[@zinelabidineadriouich6833]

you are the best like always... many tanks from france and morocco

[@samarkumar9888]

is Ai = -RB/(re+RE)

[@astheticcontent5622]

Thank you Sir .. ,🤍

[@prashantdodiya6653]

Ai = -BxRb/(Rb+ BRe)

[@babulaswain9744]

Sir while calculating Zo, there is no effect of Rb resitor.?

[@AnoNymous-po5sx]

In the homework problem...where should we consider ro? Is it parellel to emitter resistance?

[@shibanandasahoo956]

Superbb explanation sir... You really made my day..

[@sankhamitra3862]

Sir please make a video on effect of ro on the Zi,Zo & Av ..I can't understand them from Robert L. Bolylstad .

[@singkreality3041]

ro is parallel to Re

[@BhanuPratapSingh-gr1uj]

sir in finding output impedence...can't we just short our input source i.e Vi and open the current source and then find the impedence as we have done in our previous cases...by doing so Zo=Re+re

[@ankitsihag915]

wonderful and simple

[@sayedmiladpooyesh365]

The current i0 should be equal to -ie because they in the same wire but by kcl at node e i0=-ib

[@MATHEMATICSBYNITianHimanshu]

tq sir

[@niteshsingh2686]

thanks sir

[@Sriharshathimmaraju]

why ro is not added in eq crkt and also beta*re itself represents emitter resistance then we can remove re ryt then why re is not removed

[@nandemonai__]

Thankyou sir! This is a big help for me :)

[@aswathik4709]

the video has some problem? i am not able to see it clearly

[@SejalSakhare-y3u]

current gain (Ai)=- Rb/ (re+Re)

[@amrelkomy3474]

sir can i use the emitter follower in a DC circuit in order to maintain the dc voltage on the base of the transistor on the emitter terminal but with amplification in the current gain ?

[@shubhamkheraliya4086]

how we can find the Av, Ai, Zi and Zo when the output resistance is finite?

[@hiteshsaini4260]

pls tell

[@lakshmipriyanka4490]

Yes sir

[@singkreality3041]

You have ask the right questions.. instead of Re use Re parallel to ro

[@suryasai2847]

Tq sir for giving this information

[@PrabuPrabu-wb4di]

Sir even if small Re is small when it is being multiplied by beta we can't neglect

[@chandanr191]

Beta is taken as common

[@amandeepstj]

sir I ve a doubt. I think that output current and emitter current should be in the same direction

[@pradeepkumar-zf4dl]

No see the polarity of voltage

[@aarushverma643]

@@pradeepkumar-zf4dl but it is breaking junction rule. ib, ic,and io all currents are coming. but nothing is leaving!

[@arunkumark3832]

thank u

[@pallabroy6414]

is the current gain Ic/Ib?

[@alllove6874]

yes...that's beta...the current amplification factor...beta = ic/ib....aka the current gain..

[@perceptrongaming4290]

Ai=zi/(re+Re) or Av *(zi/Re)

[@fayyazahmad5334]

Ai=-Zi when Re>>re is it true sir

[@sauravti]

I think nooooo

[@thebetapower]

I am still much confused with neglection of small and large parameters. In some cases,you neglects small quantities while in others you neglects larger quantites......sad to me......

[@cartoonsondemand_]

In parallel connect if your answer would be small like re||Re then re will be answer of re

[@MajikBox9800]

Why does Output Resistance is not included in the AC Equivalent Circuit?

[@kurono1822]

Because this example assumes ro=infinity

[@boliviakollasuyo]

Is the Ai = - RB/re ??

[@tanzimhasan1118]

Can anyone explain if ro is connected in output side?

[@krishna10075]

Ai for r=infinity is beta+1

[@adityagarg55]

Current gain ans please

[@Spartan7960]

same current dosent flow through Re and re

[@sksalma4377]

can anyone say where we get the homework problems

[@arunkumark3832]

sir can you send the earlier video link to see of that concept

[@SHREEdharSimple]

@6:07 I am not able to figure out ie=(1+b)ib..??

[@alllove6874]

bro, ie=ic+ib......ic=Bib in active region that is necessary to use transistor as amplifier....so ie=Bib+ib...therefore ie=ib(B+1)....just factoring out ib...hope you got it...B is beta btw...

[@ashwinikoppal9645]

Ai= -Rb/(re+Rb) ro=♾️

[@arturminiput7587]

Plz somebody give the link for torrent file to download all this lessons

[@backbenchelectronics2773]

Use tube mate apk Not available in playstore

[@SaurabhKumar-gc1ko]

are bhai kisi bhi ek video main to current gain nikal dete

[@learnwithsomaya6758]

🥰🥰

[@jaysonabayan3279]

jesus christ please don't make homeworks in lecture

[@arunkumark3832]

how we can get ie=(1+beta)ib

[@alllove6874]

bro, ie=ic+ib......ic=Bib in active region that is necessary to use transistor as amplifier....so ie=Bib+ib...therefore ie=ib(B+1)....just factoring out ib...hope you got it...B is beta btw...

[@GauravGupta-pb8mk]

Thank you sir