Mesh Analysis with Current Source

[@UniversalSaad]

Every teacher of NESO ACADEMY is Perfection. They have removed the word complexity from my dictionary. My HUGE respect to you, sir. Thanks for all the efforts you did for us.

[@HimanshuYadav-qy5sm]

Teaching is 2nd best thing of this channel Dark theme is still n.o 1

[@fanman420]

youre a life saver for electrical engineering classes

[@imtiazahmad5344]

sir your style of teaching is amazing

[@nadeeM.H-t7v]

sir your service is extremely valuable for us . sharing knowledge with humble is the most best human quality

[@ayushsinghpawar4191]

Watching at 1.5x speed. Even considering 2x

[@vinayakisd9849]

😂

[@aanisamanzoor1495]

Same here.... 🙂

[@adhishumarani8567]

God

[@shahidparvez8712]

Same here bro😂

[@sadatiqbalpriom7389]

Here I am contemplating why doesn’t make watching at 2.25/2.5x speed possible

[@YouKnowMeDuh]

So simple, why didn't I realize this 2 days ago 🤔 thank you for your help! Hope I remember this for the duration of my circuits learning...

[@shahidparvez8712]

Thank you sir. I'm dependent on you for my GATE preparation 🥰

[@ArbinSama00]

Best education on KZbin ❣️❣️❣️

[@harrytaylor4360]

Really helpful! just wanted to add that using resistances of 1 ohm in examples like this could be confusing, since as as the coefficient of one is implied, it may appear as though our equations are solely based around current, rather than voltages in terms of (unknown current * resistance constant). Also, what happened to the passive sign convention? is it not standard?!

[@rohitsingla4420]

Best explanation ever

[@munireddy3600]

Determine loop current and power delivered by voltage source, Use mesh analysis

[@munireddy3600]

Answer tell me

[@munireddy3600]

Fast

[@percybyssheshelley9403]

Thank you...You're a great teacher🖤

[@nithyat9025]

Awesome explanation 👍

[@meck_billions]

thanks much Sir i have understood well your solution keep on going

[@shreya_das99]

plz explane how could you get the value of I2...

[@tunji7120]

you're a life saver g

[@jaybhattacharya4665]

Thanks for help I was not able to understand mesh analysis in college classes.Now all my doubts are clear.

[@madhumitha5199]

Thank you sir

[@Kavyakommu_5089]

Good explanation sir

[@theadvocate3947]

This helped a lot! Thank you!

[@varunchowdary1961]

Good explanation 👍

[@olaayman1900]

thank you

[@nehalkr1924]

Nice explanation

[@deepikarani8309]

Very helpful Thanks

[@Facts_i_n_Telugu]

thank u sir for best explanation

[@bharathkumar3307]

U r best 👍💯👍💯👍💯👍💯than lecture s ☺☺☺☺☺☺☺

[@hamzausmani8015]

Shouldn't the equation for mesh 1 be -4i+i2+i3=+2 instead of -2 since the KVL indicates the direction to be negative for the voltage source of 2V.

[@parikalpsingh9231]

its +VE since its going from -ve towards the +ve

[@vasemantwist]

Was taught this too, I’m pretty sure you’re right

[@corpliner1506]

No, you are completely wrong. It is flowing from negative to positive so its a positive voltage gain. If there current was reversed then it would be a voltage drop, therefore it would be -2v, but that is not the case.

[@jokanolayusuff4820]

Really, helpful.

[@rohitsingla4420]

Excellent

[@mitchythekid5596]

God bless you sir

[@continnum_radhe-radhe]

Thank you so much 🔥🔥🔥

[@chalapakaramya8868]

Gud explanation sir I can understand now this problem

[@sreekanth2339]

Thank you SIR

[@Hemalatha-o2m]

Thank you so much sir ❤

[@rebekahmoncada8980]

Why is the voltage from I1 not (-2) in the equation? Initially he marks it down as +2 but I was taught that it should be negative as it is going in through the negative terminal...

[@davidhhhh721]

I'm not sure I understand, in Mesh 1 you have -(I1-I2) but in Mesh 2 you have -(I2-I1), I'm confused about the signs, and the polarities. I thought we care about the voltage polarity. If we assign the resistor in the middle to be positive at the top and negative at the bottom, then wouldn't Mesh 1 be -(I1-I2) and Mesh 2 to be +(I2-I1)?

[@rahmatamale2401]

This is wat is confusing me too

[@rahmatamale2401]

@nesoacadamy

[@yawg333]

how are you combining equation 5 and 4 like that can we have the full method as to how you reached that conclusion

[@yawg333]

i understood. you multiplied equation 5 by 4 times to eliminate current variable I1 when you subtract equation 5 from 4

[@MANOJSAHOO-ku5et]

Super lecture.

[@trevorgleeson5281]

Thank you!! very helpful

[@mahendradabgar8107]

Sir ...I can understand very well ...bcz your method is great ..I am student of engineering . I have a equation = what is the use of mesh analysis in real life ,? Means ..any example for device which has this type of circuit and is there use in industry ? Sir please answer .....

[@MrMineHeads.]

Mesh analysis has wide applications and is primarily used when analyzing circuits for voltages and currents. However, saying anything more specific than that is difficult since it is so widely used. It is as similar as calculus to the field of engineering. Fear not, these have a lot of uses when designing circuits and machines, so you are not wasting your time learning it.

[@MohitKumar-iz6bs]

Thanks sir ♡

[@asadahmadkhan1054]

Sir you are the bast

[@shivasrivastava721]

Very nice sir

[@moazelsawaf2000]

Thanks sir

[@jaydobariya7602]

If current source and voltage source both present in one mesh then what happened??

[@al-raffysarip4812]

How to calculate using mesh method when there's a current source and a resistor between two meshes?

[@sritulasigayathrikandiband3520]

use super mesh method

[@avinashchowdhury2533]

How do we know the voltage across 2 amp resistance

[@TheRisingSun-INDIA]

Sir you say I3 direction clockwise but you draw it anticlockwise direction

[@m.varunreddy7365]

thanks a lot

[@bableekumari3143]

Nice sir

[@temngum48]

thanks prof it took me days untill i found this

[@temngum48]

very easy

[@girisvlogs1152]

Tysm sir🙂

[@mohsinkhan-ps5wl]

how to apply kvl in a circuit having dependent current and voltage source

[@aaryainfernolucario3519]

how to solve equation 4 and 5? i didnt exactly understand how to do that to get the answer, can anyone tell me please

[@rounaknag68]

Can we solve the mesh analysis problem by nodal analysis method?

[@anitalayal9171]

If current source is given ,, then there is no need to convert it into voltage source? Can u plz tell me when we need to convert the current source to voltage source

[@shex9002]

Only if the question says to, else, it's easier with current sources

[@tarunchelumalla007]

Thank u bro

[@pierrefabela]

excellent video but the little logo gets in the way...

[@sathviknandyala8413]

What if current direction chamged plzz reply

[@TB-my5ij]

How did you find 12/11 ? I don't understand

[@eg9418]

2 equations, 2 unknowns

[@jatinkohli4279]

Did not get the same

[@kaus05]

Multiply eq by 4 to eliminate I1

[@lbu5543]

@@kaus05 im getting 14/11 can you help

[@gonepavankumar207]

Tnqq sir

[@daydreameryt7871]

Hello sir I have a question of mesh analysis but I can't solve it can u help me

[@pawanraj-vu9wd]

thanks sir

[@shex9002]

Frkn love u man

[@kirandevanga6344]

How we will get I2= 12/11?

[@tekkemteja2003]

How sir

[@ibrajeem]

How do I find the voltage across the current source?

[@harshavardhan9399]

current * equivalent resistance of that mesh

[@dipeshkumar4001]

I1 will be 14/11

[@shex9002]

And i2 12/11

[@vishnuvamshi2927]

Super

[@kaus05]

What is I1? - 11/12?

[@Stekaren]

5:15 mesh 3 how did you get -(i3-i1)? the resistor 1 ohm has polarity according to its current direction + -. you're going from - to +, thats +, so 1*(i3-i1) = i3-i1 = +I3-I1?? im thinking at resistor 1 ohm you're doing KVL from the middle essential node and going to the left, with the mesh current not against it so why is the mesh current i3 negative and not positive?

[@engineeringjoe]

you did the first mesh in the wrong direction... it should start with -2V + 2*I1 ...

[@nhitc6832]

He used the other sign convention. But it doesnt matter. If you take your equation (whatever you had) and multiply both sides by -1, you'll get the same equation as his

[@priyanshigupta1117]

Should not we perform source transformation here

[@MuskanKhan-xu2gi]

.

[@ShashiKumar-fh3pc]

Sir final answer I not understand

[@AcayoScovia-tn2rc]

I didn't get mesh 2 analysis

[@Ancestor_kcd]

Shouldn't your equation 1 be -I1 + 4I2 - 1I3 = 2?

[@nimitgarg2531]

No the eqn is correct only

[@shex9002]

No it's 4i1 - i2 = 4

[@sreekanth2339]

Yes sir

[@syedismail1849]

🔥🔥🔥

[@immanuelbasil806]

shouldn't i be 12/10 rather?

[@abdullahalrakibalif3420]

i1=14/11 ,kindly check

[@powerofpriceaction91]

Why I2=I

[@mosesraja1234]

yes i2=1A

[@RajeshKumar-ot4er]

I=5/4

[@the_indian4606]

👍👍

[@s.m.senses7199]

🙏❣

[@davalasabnadaf767]

sir how to calculate I3

[@krzysztofbera7089]

it's current from current source- 2 A

[@pavankata6099]

i2=12/13

[@rajeshverma9246]

sir ji please Z-transform finish kar dijiye...please

[@naveensatyadurgatadicherla9877]

How I2= 12/11

[@Subha269]

i=(14/11}

[@Upsc-i6q]

I also got same

[@Upsc-i6q]

I also get same

[@kavithav9656]

This sum was not correct.

[@divyansh_kashyap2901]

😍

[@shortzz220]

aaaaai 1 aaaaai 2 aaaaai 3 💩💩💩💩

[@gowshikram6604]

there is no need for solving 3rd mesh I know that sinc we have i3=2A . but if I want use that equation in mesh 3 it give me wrong answer why?.i substituted i3 =2 using in 3rd mesh got equation but doesn't work

[@rajdeep2105]

Thanks Sir

[@subhasishmallik5603]

Thanks sir

[@yxxshvs]

Thankyou sir