Trigonometric Fourier Series (Example 2)

[@roshanbernard5933]

Easy method .... Make the signal symmetric about t axis by shifting the signal down by 1/2 units now the signal is Odd and symmetric about t axis an,a0 = 0 ... find bn and at last add 1/2 .....to the FS expanision

[@wailalwajeeh6520]

1/2- 1/π (sin⁡t+ sin⁡2t/2+ sin⁡3t/3+⋯) Is this going to be the final series ?

[@Waquar919]

Yaa

[@rakshitkulkarni3060]

Yes

[@Shri_Radhe_Aaditya_Here]

YAA

[@bharatbardiya2362]

Yes this is correct

[@MadhavNagpal-yc4wr]

Yes

[@abhishekpatel1535]

Thank you sooo much Sir!! A True hearted Respect for you 👏👏

[@a2a827]

Sir need more conventional questions on this Fourier series Nd make a playlist for GATE/ESE questions on each topic ❤️

[@rockeykumar3348]

-1/nπ amazing concept sir thanks a lot

[@gaurav_kumar_504]

yes sir i need more solved questions for clearing all doubts .

[@prachetashisbhattacharya5286]

You saved all ECE students sir.

[@zvirus0074]

bn=-1/(n*pi)

[@rakshitkulkarni3060]

Yes

[@HITD47]

What stands you out from others is that they tell your very basics e.g integration by parts, quadrants etc

[@umeshkashyap6070]

yesss!

[@vaishnavimunj3054]

I like your easy to understand accent and fluent English 😄 Thank you so much...

[@chazdaspaz1234]

probably the best example ive found. thanks

[@gskerbecs9513]

Thanks a lot sir!!! Thanks to you and my other teachers, my exam went very well today. Thank you very much sir Jai Shri Ram

[@labanyasengupta8331]

Thank you....very helpful lecture....

[@methmipavithra9646]

Thank you very much sir..this helps me a lot 🙏

[@RazzMojo]

The final signal x(t) is not an odd signal HOWEVER it has an odd component and therefore bn is not equal to zero. The Fourier expansion expression indicates that the signal is composed of 3 components; the average (a0), the even (an term), and the odd (bn term) signals. Imagine removing the average value a0 from the final signal x(t). Since a0=1/2, this means we shift x(t) down with the amplitude of 1/2. With the new waveform, we are theoretically left with the even and odd components if they exist. In our example the new waveform is odd but not even. Edit: Moving forward, it's explained in 162. video: Symmetricities in FS Part 2, under the "hidden symmetry" concept.

[@NaveenKumar-yj7oh]

a0 is easily calculated by using the area of triangle

[@debgandharghosh3981]

Sir this was an odd signal why did we calculate an?

[@gauravnagamaheswarpattem7069]

sir.. since "An = 0" in last... doesn't it mean that the signal is odd?? but I don't see like the signal is odd !! then why did that An get value zero??? clarify!!

[@gauravnagamaheswarpattem7069]

clarify!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[@mayurrajbharati872]

@@gauravnagamaheswarpattem7069 If the signal is odd, an=0 but not conversely

[@gauravnagamaheswarpattem7069]

@@mayurrajbharati872 ok thanks but ,is that said in the video?? I guess no... anyways thanks !

[@surumabarya9398]

sir...the value of cos(180) is -1...isn't...?

[@adibmd.ridwan]

Sir I have a question here An = 0 ; but we see the function x(t) is not odd.........then why An becomes zero?

[@farhanhaikhan7307]

I think it is an odd function... It is explained wrongly... If we perform time reversal and amplitude reversal we get the same function... So its odd.

[@sivachittiboina8671]

@@farhanhaikhan7307 no.... it is not odd function

[@km.s4502]

Its neither even nor odd

[@PoluBalaji]

It's not nesscessary to be a odd function if we get Añ=0, Note:all odd functions have An =0,but not all functions having An=0 are odd...🤗🤗

[@Rajveersingh-mb8fi]

@@PoluBalaji your explaination was good

[@acharyavivek51]

thank you so much brother...kindly solve for more conventional questions please.

[@asifahmad5208]

Sir you say that this is not an odd function than how An= 0 , you said that this is mixture of odd and even component

[@gandrakavya6251]

Ya same doubt for me also But u know if it is not a even signal then it should be an pdd siganl ryt for odd siganl cosnw0 will zero hence an will =0

[@gandrakavya6251]

Odd*

[@deer_d]

Wow, THANK YOU. It helped a lot!!

[@rajkumardas9737]

Thanks for this video ☺️❤️

[@pratikjaiswar907]

Thanks sir, it was very helpful.

[@MuhammadAwais-kv9bm]

we can solve this question by move the signal down half and then we easily find that weather it is even or odd

[@jaganmohan5099]

Sir it is not even signal then why a_n comes as zero

[@debgandharghosh3981]

If signal is even then b_n is 0

[@gyanganga8441]

Such a very nice explaination sir ji, thank u so much sir for ur hard n good work

[@muhammadibnwahid6405]

There is a mistake. cosine of 2*pi*n is not simply 1. If n is odd then then it is -1 and if n is even then it is 1.

[@DolaLado]

No. The condition you said is correct for cosine of pi * n. cos(2 * pi * 1) means cos(360) = 1, cos(2 * pi * 2) means cos(720) = 1, cos(2 * pi *3) means cos(1080) = 1

[@muhammadibnwahid6405]

@@DolaLado Thanks Buddy. Now I can understand.

[@SandeepKumar-up9bp]

SIR plz upload some more prblms based on conventional point of view

[@gib6427]

Sir what if the sawtooth signal goes from below the x axis and up above the x axis? its an odd signal obviously but will the calculation be different? will ao be zero or non zero?

[@pasumarthisaiteja5696]

Instead of finding a0 we can just find the area of one right angled triangle

[@JamilKhan-hk1wl]

then divide by the period

[@adityalote9058]

Still you'll need the equation to get an and bn

[@vijetasarswat9610]

Thanks again for the lecture

[@Heisennburg]

Clamp down kar de to odd symmetry aa jayegi .. Then an=0 but bn kaise nikalenge

[@allanraju1570]

Yes Abhishek Ur absolutely right there is an hidden symmetry

[@greenfoodpower6961]

Excellent!!

[@mengistejig5332]

Thanks so much sir!!! Good a explanation...

[@populardo2163]

Thank you!

[@citadel_music123]

Found this video really helpful! Tho I would like to ask, doesn't this make the signal odd, since An = 0?

[@karangidwani3508]

X(-n) = -x(n). The given signal does not follow this condition that is why this is neither odd or nor even signal. This is mix signal of odd and even parts

[@Hiyori___]

so even if signal is not odd and therefore we cannot say directly that an is equal to 0... an could still be equal to 0

[@abhijitkumarmanna2031]

Respect Sir🙏🙏

[@jimmychan8640]

Sir, can I consider the given graph as a odd function which has been shifted 1/2 above the x axis, hence the cosine term would be zero?

[@lyaska9699]

If a_n is zero for all n, does that mean it's kind of like an odd function (but with some DC value)?

[@balabharathvishal]

Since coefficient ( an=0) this signal should be odd signal right sir.But you said it is combination of both odd and even signals.Could you plz explain this sir.

[@KushDave910]

The value I got for bn is -1/pi and you're value is -1/nPi when I substituted the limits I'm getting -1/pi my n is getting canceled out. Could you show the soln for bn please

[@kalapankalapan4228]

It is also called ramp signal??

[@itssamruddhi5664]

How you've calculated bn?

[@sillarohansillarohan9310]

Superb explanation sir ❤️ u helped me a lot ❤️

[@surumabarya9398]

bn=1/2-(sint+sin2t/2+sin3t/3.........)

[@vincentjiang3590]

thank you very much sir!!!

[@nickbeats9883]

-1/n pi

[@haribabureddy1173]

Thank u so much 😊😊

[@kalpanapandu205]

Sir explain in terms of exponenetial

[@rojadontamsetti4198]

How to find out if signal is even or odd signal???

[@echo293]

at first we said a_n is not zero BCS the function is not odd, but we found a_n was indeed 0. How come the graph analysis is wrong?

[@sandhyanimbark3046]

What will be the frequency spectrum for this example!

[@SangitaChatterjee-u1f]

Why didn't we take 1/T instead of 2/T for a0

[@cipherswami]

Hey, here an = 0 but its not odd signal. So, Vice-Versa is not applicable.

[@greenland6873]

How to calculate Bn = -1/n*pi I calculated it was 1/-2*pi*n

[@AdityaTiwari-y4j]

explain selecting ao ,an,bn futher for formula (need urgently solution)

[@akankshaakula7138]

Tqqq soo much sir

[@karishmapandey1068]

🔥amazing

[@Unknown-tl2rq]

Thnq sir i got bn = -1/nπ

[@md.abdulmuhaimeenkhan2803]

I am getting bn = -1/2*pi*n

[@krishnaveni7637]

Tqs for u r lecture

[@dingugaming2388]

Broo what is the formula for bn?

[@nietzschean6987]

It was odd but sir did whole thing..

[@voiceboardmurali]

an=0 but at the start sir you said it did not satisfy x(-t)=-x(t)

[@mrinalmahato_art]

if we consider a0=0 we get an odd signal which is described by the sine part, now if we add a0=0.5 we would get the required signal (another way to visualize : "if by shifting the signal along y-axis if we get an odd or an even signal the argument an=0 or bn=0 respectively is still true"). so the condition was if x(-t)=-x(t) an=0 not the other way round.

[@universalspace3417]

very powerful video. But still not understand why An = 0 .

[@kienhau6790]

Hello sir...I have a similar question like what sir was teaching...but for my question...my sawtooth wave is reversely plotted hence...I have no idea how to find the f(t)...may I know how do I get the solutions? Tq

[@kuchiyashwanth6625]

In any case, your sawtooth waveform will be a straight line from one point to another, right? . A Sawtooth waveform only looks complicated, actually it is a simple straight line between two points . so just use them as your (x1,y1) and (x2,y2) and form a line equation. the resulting line equation , after a final substitution of x with t , will result in an equation that you can work with. you can use that equation for any kind of analysis in that problem.

[@AnuAnu-kj6su]

I love u sir

[@suryansh4722]

Amazing

[@admiralbg9854]

Why is sin n2pi = 0?

[@mahmoudabdolaty4442]

n is an integer value 1,2,3 .etc.. so it is multiple of 2pi hence sin of any multiple of 2pi =0

[@maheryagub]

bn = 1/(2*n*π) in the solved example, thanks for the lecture.

[@amitsoni4393]

Sir notes provide kr wa skte ho kya plss 🙏🏻

[@nabeelafatima9220]

If the signal doesn't pass through origin how can we find x(t)? I mean by taking intercept how can we?

[@313Ritesh]

y=mx+c where, m=slope, c= y-intercept Then replace y by x(t) and x by t. if any line is there in the signal.

[@nareshprasad7322]

but in odd symmetey an&a0 both are zero then we find bn

[@abhijeetkm1]

@14.15 u say cos2nπ=0 but cos 2nπ = (-1)^n . So how this could be zero.

[@satyamverma05]

Cos nπ = (-1)^n Cos2nπ = 1

[@swapnilbawaskar5541]

Please upload video of programmable logic devices.. Exam is there..on 28th Nov.. Plzz upload asap... And ur videos r awesome 😊

[@N.E.0.N]

Now what happened after 5 years?

[@MahmutEbrarACIKVEVO]

So an is 0. Which means our signal is in fact odd after all.

[@padma1285hirave]

Hello sir where I can get all videos of signal and system

[@emanianjana1781]

just type "signals and systems neso academy" in search bar u will get to see a playlist of 314 videos this has all videos regarding S&S please try it PADMA HENDRE just follow carefully u will get the concept

[@reshifabrics7438]

Sir I m getting bn=1÷2π^2

[@leeaaron5085]

I don't get why sir you using different by part formula instead of: int u dv = uv - int v du Sir can you explain?

[@MegaXenon123]

If you look at the method, it is exactly this formula, just that it expressed in a different way. If you use your formula you will get the same answer

[@nihadabbikar5788]

sir i am getting bn=1/n*pi...plz tell me if i am wrong

[@Crusader2]

I do get the same answer

[@sahanaravinder7058]

i also got the same ans bn=1/n*pi

[@NCHINNINTITULASI]

Me toooo

[@Unknown-tl2rq]

Sinnt value is -cosnt the value of -cosnt is -1 then u will get -1/nπ

[@viveknirmalkar2966]

awsm video superb

[@chaytanya2298]

How x=t?

[@Jalaj-fc6gi]

Equation of line in terms of y&x And also y=x(t) so x axis is t

[@osamaelzubair1203]

Can someone prove that the above signal is not even ?

[@harsh9222]

why an is equal to zero sir???

[@zedlepplin9450]

because the signal is an odd signal

[@abdelrahmanmohammed3561]

@@zedlepplin9450 The signal is not odd

[@riponhossain6399]

Please,anyone say how to compare x(t)=x(-t)

[@keerthanasaravanan8557]

Sir can you pls take the gate exam related problems....it will be useful to us

[@nesoacademy]

Already available in the playlist goo.gl/spqKtg

[@GurpreetSingh-zz3mj]

sir kindly reply to my question sir can we have cosine terms with odd harmonics means a^n =a1,a3,a5..... and sin terms with even harmonics means b^n=b2,b4,b6...... if this is so pls make a video of this kind of problems. but b4 that pls reply are these cases possible. actually mein ek Q pe fas gaya hoon Sgn(cost) pe iska answ aa raha hai odd harmonics for a^n where n=odd no. Pls consider my request.

[@shambhukeshav801]

Sir ,ao=π÷2 aa raha hai

[@neeltej4123]

@Vedprakash Meena its not area.. its avg value. 1/2

[@dragoniyt5346]

Is't the signal not s odd one 😅

[@LYehiaX]

ILAET NOT ILATE ??????

[@Jalaj-fc6gi]

ILATE is correct

[@adityavikram2825]

sir my Bn is coming 0

[@allanraju1570]

Then Ur wrong Mr Aditya😂😅

[@adnanahmad-sj7xn]

Bn = -pi/ (pi)^2

[@NoorAlam-kv7sv]

Nooooooooooway😭😭😭 i was watching this much long video and a(n) came out to be 0 . Noooooooooooooooo

[@kyrillosakram]

thank u ^_^

[@ap8835]

god bless u and jesus and allah and budha

[@justagirl2744]

I get bn=0. Anyone else?

[@Hydgodharollu]

No its - 1/npai

[@aazadjewellers5832]

@@Hydgodharollu but i get -npi^2

[@chandran-youtube]

❤

[@chandran-youtube]

Luv u guys... U r amazing...

[@shruthakeerthipurushothkum2724]

A0 =2/t but u have given a0=1/t

[@shruthakeerthipurushothkum2724]

Ur a0 ee is wrong