NFA to Regex Conversion Example #2, "More Complicated" (GNFA Method)

[@Dhiren_]

You are an absolute legend, makes so much more sense than reading my lecture notes. Thank you.

[@johann_reimann_2077]

Thank you!

[@EasyTheory]

You're welcome!

[@elijahbrady950]

This problem is literally a problem on my homework. Thank you

[@vimalathithand917]

Cool video! An absolute Masterpiece!

[@okaudi]

So , self loop does not count as one in and one out?

[@explosiongalaxy7334]

what if the start state is also the accept state

[@ghazalasaleem4250]

thanks man. you are really amazing

[@ErickIsGaming]

Amazing

[@tinnokkwok8510]

I find out your answer is not correct because epsilon isn’t accept in your answer. 6:37 R1 misses a Union between epsilon and ((b U c)(a U b)).

[@mohammedrakib3736]

Anything multiplied by epsilon is itself. So, R.ε = R. So, his answer is correct

[@TheAmazingLife19]

🐐🐐🐐

[@priyamvashi2187]

Thank you!