Nodal Analysis (Solved Problem 2)

[@Slygoross]

This Channel is life saving... It's honestly the best part of studying Electrical Engineering!!!!!

[@qemmm11]

Much appreciated Sir😊 V2=-2...(1) V=v2-v1 (V1-5)/1+(v1+2)/2+(v1-v3)/1=0.....(2) (v3+2)/1+3V+(v3-v1)/1=0...(3) 2v3-4v1=4 -2v3+5v1=8 v1=12v,v3=26v,v2=-2v I+i23+i21=0,I=-(-28-7)=35A P=iv=35*2=70w(five minutes)

[@Abdullah.68]

😂

[@roshniyadav1539]

I feel so lucky ❤️ to have this vidoe in KZbin.....Even after joining classes also no one taught us in this way ....My doubt are getting clear thanks u so much @neso academy. Really appreciating your efforts and continuity....

[@byarugabajamesknox32]

at node 3 , you did not collect the terms well.

[@byarugabajamesknox32]

V3 is not added as its in the eqn.

[@kanny8742]

Can't express my gratitude in words!!!! Thank you so much!!🙏🙏

[@chapalapallimunibhargavred3730]

The best teacher I have ever seen ..Thank you so much

[@abhiram6329]

Everybody set your playback speed to 1.25

[@armor5019]

but i set on 2

[@akibhasanomi4633]

Ya 2x is the perfect one

[@chosenverse]

2x

[@shaonsingha9682]

I have set on 2🥹

[@skyrctechie]

Me looking for 4x option, habituated to watch in 2x 😅

[@rizwanalinadaf9623]

Your Teaching is Awesome Sir... Please Give us more knowledge... Thank you so much 🙏🙏🙏

[@arnavlasod8401]

Your all 3 videos on Nodal analysis helped a lot !!

[@bindumadhavi6029]

In node V2, the current is entering negative terminal as considered. So Power = - vi v= - 2V and i=35A So power= -(-2)(35)= 70 W

[@muhammadhammadsarwar698]

no because power is delivered so you cannot put positive sign with it as it shows power sink.... which is not true in this case as power is being delivered. Current is leaving node v2 and entering in the 2V Voltage source.

[@qemmm11]

No

[@qemmm11]

​@@muhammadhammadsarwar698you are right😊

[@satyavathiramakrishna911]

This man is a magician 🤩😘🙏

[@akankshs]

eqn. 3 seems wrong as per my calculation - 2v2 - 4v1 +2v3 = 0 might be the correct eqn.

[@rayyanaghaalnimer5742]

he simplified by dividing the whole thing by 2

[@Praveen-m2i2b]

Ada loosu bunda😂

[@sravanichinta]

Thank you very much sir These are very important topics for us. we hope more videos like this ❤

[@charless704]

Wow. Failed on my first attempt (due to my not sticking with arrows leaving node ALWAYS and botching final KCL) Don't overthink it, it will work out with that convention.

[@jdjsjksk]

You're perfect teacher. Thanks

[@DhananjayKumar-by5dm]

Pls see the polarity of 2 ohm resistance .We know polarity for resistance for incoming current is +ve & for leaving is -ve.

[@viewocity9840]

Yess bro so that the equation is V1-2v=V2 Is it right

[@NOTWHITE-hd6ls]

@@viewocity9840 yes

[@08amitkumarnegi97]

Sir, power formula is ipower2r

[@sumeetkumarroy]

Sir at 6:24 we have to write the kcl,so in the current towards 3V which is dependand source why u didnt considered the resistance which should be zero so the equation will be 2v3 - v2 - v1 = 0 . Could u explain this

[@redemedy8602]

see because in current sources the internal resistance is considered infinite and not 0 (parallel connection). First things first I think you misunderstood that this is a current source and not a voltage source. The current that it provides is 3 times the Voltage across the resistor that says above it in the schema provided. say if the voltage across that resistor happens to be 10V the VCCS source will provide to branch 3*10 = 30A. Hope it was helpful but it has been 2 years...

[@pakarmyisizindabad6206]

Nice explanation and effort

[@saitamapreetsingh3057]

in equation 1 when you put v2 = -2, answer is v1 = 16v not 12v

[@vidyashejwal8875]

Brilliant...tuter... thank you so much

[@shivangsharma4036]

Hope you will comment down since V1-V=V2 as potential drop at resistance or we can write in this way V1-2I=V2 so please verify this'

[@zahidhasankhoka1649]

Sir, when we calculate power delivered why you use only magnituade of V2 ?? Is any impect to use positive or negative sign?

[@amrithavarshini1110]

@Neso Academy Sir as per your previous lectures power absorbed is +vi because it is leaving the - ve terminal and power delivered or supplied is -vi because it's entering positive terminal...here it should be -70w in this case .please do clear this ASAP

[@Zappango]

Ya that's what I thought

[@vaishnavipatil5352]

Sir is correct see previous videos again.

[@vaishnavipatil5352]

See video by gate academy maybe you'll understand coz it's the direction of current which decides the value. The same souce and deliver the power as well as can absorb the power

[@mahirbali1813]

sir in the previous question you said when the voltage source is between the reference node and the non reference node then we dont need to find the kcl equation for that and then you just wrote the value for v1 =0 therefore in this question also we can clearly see that the 5 v voltage source is between the reference node and the non reference node (that is the ground one) therefore why didnt we said the value of v1=5 v. Does that means that this rule is only applicable when the reference node and the non reference node contains voltage source in between but no any resistor????? pls reply at the earliest sir!

[@ZanDuz]

bro how did u solve with the eq 4 and 5 to get the 12 and 26

[@NaveenSword]

Sir isn't it p=-i.v ??? Because current is entering into the -ve terminal of the volt srce (2v)??? I know power can't be negative but as per your previous class explanations u told that if the current is entering into the -ve terminal then it acts as source, if it enters +ve terminal then it acts as deliver. I'm a bit confused...

[@bhaskaralakshmiganisetti3779]

I have a same doubt sir plz clarify

[@kamalabouzhar8469]

I think you are right, power in this example is -70 W. But he is talking about Power delivered, and we know that power delivered is a negative quantity AND power absorbed is a positive quantity. Meaning that saying that P=-70W is similar to say that the power delivered is 70W.

[@sobhanbabu1168]

@@kamalabouzhar8469 thank u

[@UECAshutoshKumar]

Thank you sir ❤️

[@thirumalpriyan3528]

I have a doubt🙋🙋🙋. after solving equation 4 and 5, we get v1=--12 and v3=--26 but how did u get v1=+12 and v3=+26?

[@ShAmS894]

Nice example!!

[@bhaskaralakshmiganisetti3779]

Sir how to take v2 =-2v Current flows same direction I thought it was +2 plz clarify Now I got it

[@MustafaZahidFan]

Thanks from Bangladesh

[@iAbhijeetShukla]

why at node 2 we didnt performed higher potential i.e V2 - reference node i.e 0v = 2v ans hence voltage at node 2 will be 2 v. Instead of this why you have applied kvl in it when similarly you have done in node 1

[@sivakishore6803]

i have a doubt .at node v2 why we took current only in one direction.sirr please replyyyyyy .please

[@SynchronousGamingSGYT]

Thanks for sharing knowledge 👍

[@avethakur9198]

Sir... shouldn't the power be -70W as the current is entering the negative terminal of voltage source? 12:53

[@redemedy8602]

tricky question its "power delivered" and not "power produced". So you don't care what direction it is. You just wanna know how much power is there at x point in time. So ireelevant which side you chose

[@priyamgupta2136]

in equation 3 sir have mistaken in sign of v2 please check if i am wrong or right

[@onepunchman1763]

I didn't understand how did you solved equation 4 and 5 please explain..

[@phanindrareddy4885]

Very nice explanations

[@nadimnayem9539]

My favourite teacher

[@rakshithpranav6159]

Can't you just solve the equation after finding nodes?? What will you do by saving 5 mins?? I really like your explanation but please explain that also

[@ganeshrevanthbalasubramani7834]

😂😂😂😂😂😂😂

[@divyarajsinhpadhiyar4442]

Sahi kaha bhai usme hi confuse ho rahe hai

[@NischhalKarki-k7q]

at node 2, why v2+2=0 without any loop

[@ravimishra9526]

Sir how to contact you for more query like if I have circuit diagram and I am unable to solve it then how to ask you

[@shivangsharma4036]

Also when you divide the current at V1 initially then we considered that V1 is the high potential point so how it come not to V1-V2=V

[@eulzzzz7682]

Same question??

[@olaayman1900]

thank you

[@venkateshdasari4957]

Why should we taken voltage across 2 ohm only , while calculating at node 3 ?

[@triyuda9955]

Is the equation of number 3 wrong? The correct answer is -4V1+2V2+2V3=0

[@sharathkb2397]

yes , i got the same.

[@huzaifasarwar5205]

@@sharathkb2397 he just divided the equation by 2

[@te44aniketdusane86]

It is, -4V1 + 3V2 + 2V3 = 0

[@te44aniketdusane86]

So we can't divide it by 2

[@martiananomaly]

@@te44aniketdusane86 We can easily divide the whole equation by 2 though. Divide LHS and RHS by 2 and the RHS remains same as 0/2 is still 0.

[@moazelsawaf2000]

Thanks sir

[@sunnyitssimple]

dhanyawaad sir

[@eloiseleal3883]

From the solution of equation 4, Please can someone tell me how does 5/2(V1)-2/2-V3=5 becomes 5/2(V1)-V3=4?

[@redemedy8602]

So from combining eq 2 and eq 1 you get the eq 4 which initially is 5/2(V1) - (V3) = 4 you 2x both sides and you get 5V1 - 2V3 = 8 (eq4). What you have written here is equation 1 and you wrote it wrong too. Go slow and methodic so you don't make these mistakes

[@dheerajswaroopsm691]

Sir the power should be -70W according to your previous lectures

[@md.alakib2335]

- 70W means 70W power is being delivered. So, he is right. and when you get positive value of power that means the power is being absorbed by that component. Thanks

[@dixitacharya6342]

at node 2 why did u onlu took v2 , why not {v2-v1}/2 n {v2-v3}/1

[@wetyewruyrtsutrdhjfg]

I don't understand one part. You said that V2 is -2V. Why can we ignore the currents coming in from V1 and V3?

[@ec039venom4]

Bcz we need voltage across v2 nd one thing should be noticed that there is no resistance at v2 But may be muje clear nhi pta .....

[@maddumani6300]

Plz tel how v3 =26 how it came

[@zishan53]

Thank your sir it's is so loviest method to understand ... Thanksgiving again

[@nayanmisra8447]

I think the polarity of V across resistance 2ohm is incorrect.

[@piyushgupta5399]

Yes bro, it should be the other way around

[@sripriyasr1748]

Awesome sir🤗🖤

[@viewocity9840]

Is this equation V1+v=V2 Is right If yes Can u explain

[@veereshkammara9139]

Sir I have a doubt is the power is absorbed by source as current i22 enters the 2v source at negative terminal

[@HimanshuYadav-qy5sm]

Watching the whole playlist at 2x

[@KakashiChidori616]

plz sir complete signals and systems

[@salonikanger2044]

why the current is entering in 5v it should be leaving from positive terminal

[@siddharthmeena7643]

node 2 ke equation mein current ek hi direction mein kyu liya? can anyone explain please?

[@thejareddy4380]

Sir i applied mesh analysis to above n/w ans not coming i got first mesh current 5A for 2nd 6A and 3rd mesh current is 4A is it correct????

[@soombit8586]

you miscalculated do it again

[@neeltej4123]

i got currrent in 2V source as 17.5 amps. i cross checked it multiple time.i.m still geting the same ans. do any one have the same ans? power delivered will be 35 watts.

[@zahidhasankhoka1649]

8.17 when simplified V3 then how its coefficient 2 remove? Anyone please?

[@dhruvsharma9065]

Hello sir To be very honest I want to inform you that on KZbin many resources are already available for preparation of network theory and basic Electrical engineering We know your capability , please complete the course of power system first , since on KZbin no authenticated resource is available for it's preparation

[@josephinemiezah896]

SIR PLEASE IM THE PROBLEM ONE, AT THE NODE 2, YOU STATED THE CURRENTS LEAVING THE NODE BUT YOU DIDNT DO SAME HERE. PLEASE IM CONFUSED. HELP ME

[@charless704]

You don't need to use KCL at Node2 at first go around. You are trying to find the voltage potential at all nodes. At Node2 specifically, you can get the voltage directly because the 2v independent voltage source lies between Node2 and ground (without a resistor in the branch providing a voltage drop.)

[@josephinemiezah896]

Thank you

[@reficeismail6520]

can you get power delivered used mesh analysis KVL

[@moinansari6988]

How the equation number three comes

[@sujithdissanayakeict]

(v3-v1)/R5 -I +v3/r4 =0

[@RazibulIslam-np5fg]

7:5 can anyone explain how current became 3V

[@haseebsafdar6712]

Isn't it a supernode

[@staywithmeforever]

1.75x Recommend

[@sayanbhowal2108]

I use 1.5x

[@directioner1502]

Y u find v value....? Y u take v...?

[@viewocity9840]

In the question it self they mention that v is a current passing through 2ohm resistor and 3v voltage control current source

[@ec039venom4]

Why do we take polarity of 2ohm resistance - to +?? Can anyone plz help me to out of here ??

[@thesoul3461]

it was given in the question i think.

[@reficeismail6520]

p=-70w

[@jhanvigupta3548]

i love you

[@Sportsman134]

how come node 2 is kvl but every other node is kcl

[@shreyay7866]

bcoz there are no resistors ,only voltages are there

[@maddumani6300]

Plzz tel me v3=26

[@parthraval3883]

* You have done a mistake * 3(V2 - V1) = 3V2 - 3V1 you haven't multiplied "3" in your calculations.

[@Saf-bt8ew]

why we not taken v3=3v

[@mondalsatyam6014]

It's a current source

[@Rahul-hq3en]

8.47 here how 4 it's came but in equation 1 we have only 5

[@kamalabouzhar8469]

he substituted V2 which is equal -2v in Eq 1

[@risharuhi8374]

By substituting v2 also...how 5 will change to 4 in equation 1

[@yashjitechnical3328]

V3-v1/R5+V3/R5-I ans.

[@Manikanta-wz2rl]

V3/R4 not V3/R5 remaining is correct

[@thirumalai186]

my humble request to please start power systems

[@syedismail1849]

🔥🔥🔥🔥

[@thesoul3461]

why did you calculate only one current for V2? not 3 currents going out from node 2.

[@rishabhprasad8333]

This is also my doubt.

[@loveyoubts2002]

Mine too

[@sudeeptagogoi1700]

Some1 plz explain me the 5:12 part.

[@akritisingh2816]

Equation 2 ki value jab equation 1 pe daale To "V" Kaha gaya Atleast explain to kar do Ye adha solution dekhe kitna tym bacha liya

[@Suraj28j]

V2 = 2v mean V2 = 2 volt Now Put the value V2 = 2 in equation 1 & 3

[@surajsingh-nx6zl]

Hahahahahaha

[@dee309sammansaha6]

The node 2 equation is doubtful 😕

[@UttamSingh-ui2hk]

why is it so ?

[@_jatin.69]

He just applied kvl from V2 to group

[@smasher7199]

please avoid writing on the border of screen

[@s.m.senses7199]

🙏❣

[@shivangsharma4036]

Sorry My bad I missed the polarities

[@dayasagar3324]

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