Normal force in an elevator (Hindi)

  Рет қаралды 66,327

Khan Academy India

Khan Academy India

Күн бұрын

Пікірлер: 58
@romavarma8167
@romavarma8167 3 жыл бұрын
great explanation...great platform to learn basics.....my doubts are always cleared here!
@ja7ffshorts212
@ja7ffshorts212 10 күн бұрын
Excellent 👌👌👌
@Tusharrajput0491
@Tusharrajput0491 5 жыл бұрын
Ur voice like professional
@AiTech0786
@AiTech0786 4 жыл бұрын
Right
@a.pal_yt2018
@a.pal_yt2018 2 жыл бұрын
I also want that deep bold voice.. uh
@TheKeshav92
@TheKeshav92 Жыл бұрын
Thanks buddy. Your explanation always related to practical which creates better understanding to know the physics.
@wasifhabibbangladesh1482
@wasifhabibbangladesh1482 3 жыл бұрын
Awesome love from Bangladesh 🇧🇩🇧🇩🇧🇩🇧🇩🇧🇩
@narotam4370
@narotam4370 Ай бұрын
Kanglu 😂
@AmanGupta-cy1gq
@AmanGupta-cy1gq 5 жыл бұрын
Thanks a lot You cleared my concept
@yougotthis4701
@yougotthis4701 2 жыл бұрын
Thanks Sir🙏🙏🙏🙏🙏🙏🙏.Your Explanation Is Awesome Sir👍👍👍👍👍👍👍👍👍👍👍👍👍👍👍
@sarithar5232
@sarithar5232 2 жыл бұрын
Enthusiasm at topmost level !!!
@mrjkfreefire2255
@mrjkfreefire2255 2 жыл бұрын
Briliant
@memesforteens3853
@memesforteens3853 Ай бұрын
Thanks 🎉 facing problems with this theory 😂now its clear
@swetapadma8984
@swetapadma8984 5 жыл бұрын
Fluent explanation
@TsarAayush
@TsarAayush Жыл бұрын
Love his voice
@physicschemistrynumericals6896
@physicschemistrynumericals6896 3 жыл бұрын
Thanku Ram sir ❤️❤️
@sarthakkumarbehera1015
@sarthakkumarbehera1015 4 жыл бұрын
It would be very awesome if you will become my school teacher.
@Allaboutmehina
@Allaboutmehina 6 жыл бұрын
Fabulous video sir
@recognised_me..
@recognised_me.. Жыл бұрын
Thanks sir...🥺♥️
@dhruw9935
@dhruw9935 3 жыл бұрын
Thank god i got a little clarity on this pheeww.
@rupathakkar7367
@rupathakkar7367 5 жыл бұрын
Plz make a video on thermal expansion and various expansion coefficient
@gv4565
@gv4565 5 жыл бұрын
Nice explanation sr
@eyeopener9032
@eyeopener9032 4 жыл бұрын
Sir, ek baar aap again video dekhe. Isme bahut saare logics wrong hai, Really.
@subratasarkhel7505
@subratasarkhel7505 3 жыл бұрын
Tumhe agar sab pata hai to kya sir ki insult karne aye ho
@methane385
@methane385 3 жыл бұрын
I think in 3rd case there is quite mistake. Anyways I am not sure lol I should read again 😌
@eyeopener9032
@eyeopener9032 3 жыл бұрын
@@subratasarkhel7505 no dear. I just ask him to check again and Delete the video and He can upload again, Sabkey pass Wrong information pahuchane ly sey better , sabhi ko bataa diyaa jaaye.
@eyeopener9032
@eyeopener9032 3 жыл бұрын
@@methane385 yes, Dekh lijiyega. And , all the best for the exam you are preparing for. Btw, nice name dude, Methane.
@pranjalarora3193
@pranjalarora3193 Жыл бұрын
​@@eyeopener9032kya aap bata sakte ho konsa logic galat hai
@shuvoofficial6342
@shuvoofficial6342 5 жыл бұрын
Matter clear awesome
@study6326
@study6326 3 жыл бұрын
If I get net normal force in the upright direction, then shouldn't I start flying?
@nandinichakaravarthy8271
@nandinichakaravarthy8271 2 жыл бұрын
normal force isn't a driving force. it cannot cause movement
@AmanSingh-fl4lh
@AmanSingh-fl4lh 3 жыл бұрын
Thx
@salmaparveen9907
@salmaparveen9907 Ай бұрын
Jab normal increase hua to humara weight kyu increase hua wo to decrease hona chahiye tha kyunki normal mg ke opposite lg rha hai . Koi explain krdo??
@sumangupta4848
@sumangupta4848 Ай бұрын
Nhi nhi Normal mg ke opposite hi lagta hai but usko balance karta hai to Agar lift rest pe hoti hai to dono equal hote hai Agar lift rest pe nahi hoti to normal mg se Kam ya zyaada hota hai but hame hamara weight normal ki vajah se feel hota h na ki mg ki wajah se isliye normal zyaada to apparent weight zyaada aur normal Kam to apparent weight Kam kyunki apparent weight normal hi hai
@sumangupta4848
@sumangupta4848 Ай бұрын
I hope you got it now??
@RamishRajpoot-bw9pl
@RamishRajpoot-bw9pl 29 күн бұрын
You're applying Newton's third law correctly, but missing a crucial point. Normal force (N) is indeed opposite to weight (mg), but: *Normal force is not equal to weight* N ≠ mg (in all cases) When you're standing on a surface: N + mg = 0 (equilibrium) Here: N = normal force (opposite to mg) mg = weight (force due to gravity) Now, when normal force increases: *It doesn't mean your weight increases* Instead: *The surface is exerting more force on you* This can happen when: 1. You're on an inclined surface. 2. You're experiencing an upward acceleration (e.g., elevator). 3. The surface is applying more pressure. In these cases: N > mg Your weight remains the same (mg), but the normal force adjusts to balance the forces. *Weight remains constant* Weight is determined by: mg = mass × acceleration due to gravity Which doesn't change unless: 1. You gain/lose mass. 2. You're in a different gravitational field. Did you got it now?
@sayancharlie3010
@sayancharlie3010 4 жыл бұрын
Thanks for this video.
@chakupatel4490
@chakupatel4490 6 жыл бұрын
Sir please make biology and camistry please please ☺☺☺👍👍👍👍👍👍👍👍
@hamza_developer
@hamza_developer Жыл бұрын
Camistry😂
@shiva-420
@shiva-420 5 жыл бұрын
Sir thanks a lot
@rubydevi600
@rubydevi600 4 жыл бұрын
Good
@rupathakkar7367
@rupathakkar7367 5 жыл бұрын
Thank a lot
@rajivranjan5475
@rajivranjan5475 2 жыл бұрын
I am I class 9 still watching
@shivangi335
@shivangi335 3 ай бұрын
im proud of you
@Kingmahesh290
@Kingmahesh290 22 күн бұрын
Mene bi dekha ta 9 th class me aur ab me 11 th class me dekh ra hu😂
@mohammadsarim3865
@mohammadsarim3865 3 жыл бұрын
Thnx
@rehankhushi8078
@rehankhushi8078 3 жыл бұрын
Why in the 4th case normal reaction is 78 newton not 98 newton
@realbh4rgav
@realbh4rgav 2 жыл бұрын
coz gravity is always constant so it cant increase
@Swarit_Kshirsagar0809
@Swarit_Kshirsagar0809 Ай бұрын
Coz there we already calculated that there was a downward deceleration of. 20 m/s2 and the force of weight is 98m/s2 which makes normal force to be 98 - 20 =78 m/s2 hope this helps u after 2yrs 😂😂
@Swarit_Kshirsagar0809
@Swarit_Kshirsagar0809 Ай бұрын
Btw what r u doing now?? I mean what r u pursuing rn…..😂 9:14
@dabralcoachingclasses4172
@dabralcoachingclasses4172 3 жыл бұрын
ya rgajab bolte ho ram
@arjuntyagi5860
@arjuntyagi5860 6 жыл бұрын
sir, if lift going up with an acceleration 'a' then mass will be m= 1 + a/g or m = 1 - a/g plz answer
@brainenhancer4743
@brainenhancer4743 6 жыл бұрын
Than pseudo force act in downward direction So equation become N - mg = ma N= mg +ma For detail explanation you can visit my channel video elevator problem
@sagarkaleri918
@sagarkaleri918 5 жыл бұрын
Wow
@ANILKUMAR-oc3yt
@ANILKUMAR-oc3yt 4 жыл бұрын
🎊🎊🎊🎊🎊🎊
@dhurbarajpuree2992
@dhurbarajpuree2992 3 жыл бұрын
Wow
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