Lecture 8 - Forces acting when a vehicle move

[@abhijeetmane9799]

to convert watt-sec to KWh, Dividing factor is 3600000, Not 3.6 at 28.50 min

[@gopalbhowal2081]

Why we are converting value of degree in radian for climbing resistance calculation

[@n.p.9997]

28:25 slight correction : To convert from watt-sec to kWh, you have to divide by 3.6*(10)^6

[@gagandangwal7011]

Won't the rolling resistances be multiplied by the factor of the number of tyres? Please clarify.

[@ptiwaridotin]

the given formula is correct because if you calculate rolling resistance per wheel then you must divide the total mass accordingly too. Through both the ways, answer will come out to be same.

[@juststart8387]

Thank you sir

[@h7opolo]

25:27 lol "revolutions per meter" lol

[@h7opolo]

lol that's after the traction power has become perpendicularly oriented.

[@Romanticcouple284]

20.18 9.81 how can calculate this value

[@mohamedthoufiqm8108]

It's gravitational value (some sort of science thing) You need to memorise it g=9.8m/sec (acceleration of gravity)

[@roshandeshmukh9818]

@@mohamedthoufiqm8108 tq

[@etimaniebiet1215]

someone please explain why the conversion of 30kmph was 3/3.6 but the conversion of 80kmph was 8/3

[@kedara6865]

Hi Etim, for velocity of 30kmph aerodynamic drag = 22.5 N then what will be the drag at velocity 80kmph? Simply, drag@80kmph = (80/30)*22.5 = (8/3)*22.5.

[@mainakdatta6443]

how is that? @@kedara6865

[@henryvolt6305]

don't get the fact that why theta is converted to radian inside cos ?

[@kedara6865]

Because we are calculating force which is translation value unlike torque which is rotational value.

[@mohitsoni3051]

Sir why we not go for aluminum fuel cell ?

[@kartikkumbhare3900]

14:55 Assignment 2.1

[@akhiljames5089]

better text for reference

[@rosscraig3339]

thank you sir