Number of Antisymmetric relations

[@tirthpatel20]

Video starts at : 3:36

[@wimpywarrior6792]

Bless

[@sergeykas90]

Thank you so much.

[@akashsuna5160]

Well explained 🙌

[@jovanantic136]

Very helpful

[@ramashishkumar8773]

how( 0,0) is possiable its antisymmetric if (a,b) belongs to R so (b.a) doesnt belongs to R so how it possiable ?

[@lighteningggg]

very clear which is the best i've seen, and thanks for subtitle. but I have other stupid question, which is why we made 3^((n^2-n)/2), is there any function lead to 3^elements? (I know nC0+nC1+nC2+...+nCn=2^n) but i don't konw why we can use 3^ to do this. I will be very appretiate anwsering this question.

[@rguktiiit371]

we have 2ways of filling in diagonal Elements Either we can choose (1)or we can leave (0)..Since we have 2possibilities ,it is 2^n in diagonal Similarly In Upper And lower triangle,we have 3 possibilities i.e.(0,0),(1,0),(0,1) but not (1,1) --> coz if u Fill (1,1) it violates the rule of Anti Symmetry. Since we have 3possibilities, it is 3^

[@govardhanreddy690]

if we have 1 position blank, but we have three ways to fill that blank they are {(0,0),(0,1),(1,0)}, if we have 2 places then we have 3*3 ways to fill blank . same way if we have n places blank then 3*3*3*......up to n.....*3 = 3^n ,but in this case we have (n^2/2)-(n/2) places blank in lower triangle we can fill them with 3^(n^2/2)-(n/2). nC0+nC1+nC2+...+nCn=2^n this is same as filling n places with {0,1}

[@ArunSharma-ye4sx]

Which software use

[@hemakaushik9316]

Ye ques kahan se h konsi book se h plz reply

[@KT-oz1md]

what a genius

[@satyam4410]

Lauda genious

[@DVDmathsacadmy]

3 way of selection ka reason galat bataya aapane (0,0 )possible (1.1) possible And (1,2) (2,1) mein se koi ek possible tab anti- symmetric relation hoga matlab (0,0) ,(1,1) , (1,2) ya phir ye (0,0), (1,1) ,(2,1). Sorry sir bura lga ho to 🙏🙏