Number System - Digits - Part 1 | Quantitative Aptitude | CSAT | UPSC CSE 2024 | Sunya IAS

[@sunyaias2144]

For more information and course registrations, kindly visit: www.sunyaias.com/subscription-details/csat-foundation-course-202425-batch-3

[@KomalSingh-tc8re]

Sir teaches from very basic to advance level, in most simplest way. Quant concepts become easy to understand now. Thank you, sir🙏

[@bhanushree.mandal7]

This course covers the entire syllabus of CSAT?

[@Daitya.01]

PLS MAKE A PLAYLIST OF CSAT.

[@kumuddwivedi6614]

Best teacher and the way of teaching is fantastic ❤❤

[@shivaram.k286]

Sir I feel more confident after taking your class, thanks❤

[@mandeepasengupta7172]

Thank u sir for making me comfortable in CSAT . Sir u literally made me confident in number system, average, percentage,etc.I can make difference between what I was during 2023 prelims vs now.Thank uu guru ji🙏✨✨.

[@truthfact9611]

Good class, thank you sir

[@Vinayaksoni80]

Thank you soo much sirr aap se hi smjh aaya sab ❤

[@mlharshavardhanmodimlharsh9293]

Pls make the full complete vedios on CSAT topics

[@mlharshavardhanmodimlharsh9293]

Please share the vedio of the next part session of this

[@lekshmip1215]

Kindly, give the link for the continuation of this lecture

[@AkankshaDaggu]

Yes

[@AkankshaDaggu]

Yes

[@upscaspirant2036]

It's available in hindi

[@VictorinAlli-qw7bs]

1:23:08 explain the question once again sir ..

[@rewardbelo6424]

Question no. 3 , answer should be 3 ,I guess . 1:23:13

[@truthfact9611]

Factorial remainder is difficult

[@bhanushree.mandal7]

Is it a complete course??

[@sunyaias2144]

Check the pinned msg. This is one class of the CSAT Course

[@poojasingh_11543]

Young version of Ajay Devgan😁

[@getharshufied]

in 49:59 how two to the power zero will be four anything power zero will one naa 🤨

[@sunyaias2144]

We are talking about remainders..and not actual value...any power as multiple of 4 will give remainder as 0 ..when divided by 4...hence .. remainder would be determined by power of 4 (not 0)