Number Theory | Linear Congruences Proposition 2

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Michael Penn

Michael Penn

Күн бұрын

Пікірлер: 18
@georgesadler7830
@georgesadler7830 3 жыл бұрын
Professor Penn, thank you for analyzing and explaining Linear Congruences in introductory Number Theory.
@programstix3837
@programstix3837 4 жыл бұрын
This and next video out of order in this short playlist "Modular Arithmetic and Linear Congruences" FYI. Much appreciated videos!!
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
Congruence? More like con-fluence, of a bunch of amazing information! Thanks again so much for making and posting these videos!
@adrilmanurung1730
@adrilmanurung1730 4 жыл бұрын
Thank you very much sir, I'm truly being helped by your videos
@snipergranola6359
@snipergranola6359 4 жыл бұрын
How to solve linear congruence using Diophantine eq
@ronycb7168
@ronycb7168 Ай бұрын
Are they the only solutions to any linear congruence
@ronycb7168
@ronycb7168 Ай бұрын
ohk that's what distinct means right? got it after watching the whole video
@prathikkannan3324
@prathikkannan3324 3 жыл бұрын
Consider 2r = -3(mod 55), by the theorem there should be gcd(2,55) = 1 solution. But this is obviously false, why?
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
I think there is a solution. r = 26 is a solution, since 2(r) = 2(26) = 52 and -3 ≡ -3 + 55 ≡ 52 mod 55.
@prathikkannan3324
@prathikkannan3324 3 жыл бұрын
@@PunmasterSTP yes you are right, I was probably being stupid when I wrote that comment :)
@PunmasterSTP
@PunmasterSTP 3 жыл бұрын
@@prathikkannan3324 You're good; a lot of times I can get totally confused myself, especially with number theory!
@thayanithirk1784
@thayanithirk1784 4 жыл бұрын
R u working as a professor ??
@MichaelPennMath
@MichaelPennMath 4 жыл бұрын
Yes, I teach at Randolph College in central Virginia.
@thayanithirk1784
@thayanithirk1784 4 жыл бұрын
😊
@paulkohl9267
@paulkohl9267 4 жыл бұрын
missed 12...
@omiz8916
@omiz8916 2 ай бұрын
i like it when he says good to himself lol
@metehanturan8181
@metehanturan8181 2 жыл бұрын
x = 3 (mod 5) is the solution.
@tonk6812
@tonk6812 4 жыл бұрын
U must first explain for the existence of the soln if d|b . If X°is a soln of ax=b(modn). Then n|aX°-b =>d.k|d.lX°-b =>d.k|d(l.X°-b/d) =>b/d€Z =>d|b
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