Numerical problems based on Newton's Ring

[@mrexotic29]

Sir... At 10:49 haw can the value of R×lamda be different in both equations(though the value of R and lamda is same for both eq)

[@EngineeringPhysicsbySanjiv]

That is the question I was expecting.. When we perform the Newton's ring experiment, there may be some error in the reading because of human error or instrumental limitation. This is why when we consider two readings separately, the values of R * λ may be slightly different but almost same. In order to reduce this error, we take two readings and use the above approach to find the value of R * λ. To further reduce the error, we will take multiple readings and plot a graph (Dn^2 vs n). Then from slope of the graph, more accurate value of R * λ can be found out.

[@mrexotic29]

Thanku sir... It really helped me a lot

[@EngineeringPhysicsbySanjiv]

You are welcome

[@ASHUTOSHSINGH-rs9ww]

Sir all this series is so good and crystal clear no body teaches me in this way can you upload videos on polarization also

[@EngineeringPhysicsbySanjiv]

Thank you very much. Please check this brief video to explain polarization.. kzbin.info/www/bejne/jKPHXoOjaa-tmM0

[@yughirlekar1154]

7:48 can we just take the ratio of both diameters and equate it to refractive index ?

[@Jessy.5703]

So good sir thanks for giving more information ......❤❤

[@siddharthchampia5674]

very nice video amazing explantation

[@EngineeringPhysicsbySanjiv]

Thank you

[@balajivenkatramansubasri1247]

At 15:10 Where did the Refractive index go?

[@zastro220]

in your a$$

[@jamileelavenu5711]

Thank you so much sir it is really useful for us..

[@EngineeringPhysicsbySanjiv]

You are most welcome.. keep watching and share with your friends..

[@prateekmethwani3314]

Sir, Please tell me the practical(Real life) Implementation of this concept...Do we really need it yet?... Or Please tell me...Or I have to study this for only some exams..

[@EngineeringPhysicsbySanjiv]

Newton's Ring method is widely used for the quality control of optical surfaces in glass industry for glass surfaces and lens curvatures.

[@nikkykyky]

very good explanation....

[@EngineeringPhysicsbySanjiv]

Glad you liked it

[@abcefg7045]

This video is amazing, one which I needed thank you sir

[@EngineeringPhysicsbySanjiv]

You're welcome.. keep watching..

[@vikaskumarnitrr]

thank you for this problem solving session

[@EngineeringPhysicsbySanjiv]

welcome

[@nikhilsaini930]

Sir or videos upload kro 1 sem ki physics with numerical 🙏🙏🙏🙏🙏

[@EngineeringPhysicsbySanjiv]

All chapters of Sem 1 and Sem 2 are available on the channel.. You can get chapterwise playlists in the playlist section of the channel or Please go through the links provided in the pdf file given below - You can find the links for All Semester 1 Chapterwise Videos Sessions in drive.google.com/file/d/1_dz8Rt7U6jBIvq94JtvUVzTsIDaavHOT/view?usp=sharing Links for All Semester 1 Question wise Videos in Short Video Series are available in drive.google.com/file/d/1gunjRJMMWCD2dR_ssu_2s5XLHXPLzFMs/view?usp=sharing

[@dhawalsharma2022]

@@EngineeringPhysicsbySanjiv thank you sir

[@vaishnavisharma5670]

Amazing session , u earned a subscriber!! 😊

[@EngineeringPhysicsbySanjiv]

👍All the Best..

[@avinash1211]

Very helpful

[@EngineeringPhysicsbySanjiv]

Thank you

[@simranalikhan1436]

Thanku so much sir

[@EngineeringPhysicsbySanjiv]

Most welcome.. Share with your friends also..

[@simranalikhan1436]

In my exam 5 marka numerical come again thanku so much with lots of respect 🙏🏻😇

[@EngineeringPhysicsbySanjiv]

@@simranalikhan1436 great

[@avinash1211]

Dhanywaad apka

[@EngineeringPhysicsbySanjiv]

Aapla swagat hai

[@NeelamGrewal-y9s]

Thank you so much for this video❤

[@mr_noob6361]

Thanks sir

[@EngineeringPhysicsbySanjiv]

Most welcome

[@csevala]

Wow

[@EngineeringPhysicsbySanjiv]

👍

[@extremeff4266]

Sir great

[@EngineeringPhysicsbySanjiv]

Thanks.. share with your friends..

[@aishwaryasrivastava2726]

Thank you sir 💞

[@EngineeringPhysicsbySanjiv]

Most welcome

[@anuragnano4720]

Thank you sir

[@EngineeringPhysicsbySanjiv]

You are welcome..

[@XYZ-io7rz]

1Ao=10*-10

[@EngineeringPhysicsbySanjiv]

10^-10 m

[@ayushigarewal]

thank you

[@EngineeringPhysicsbySanjiv]

You're welcome.. keep watching and share with your friends..

[@mohataseem]

All calculations are correct??

[@sapnajangid650]

thank u sir

[@EngineeringPhysicsbySanjiv]

Welcome

[@naretakbir3350]

Sir last ke 2 questions nhi aaye samjh 😭

[@harshjangid5353]

Sir plz try to solve questions by yourself not explaining the answers

[@arjunp5397]

Armstrong is 10^-10 not 8

[@EngineeringPhysicsbySanjiv]

10^-10 m and 10^-8 cm

[@liptumiah4697]

Thanks sir

[@EngineeringPhysicsbySanjiv]

Welcome.. share with friends also

[@dipakbaral5280]

Thank u sir

[@EngineeringPhysicsbySanjiv]

Most welcome..

[@RITURAJYt-n2z]

Thank u sir

[@EngineeringPhysicsbySanjiv]

Welcome.. and best luck..