at the k2 part...why there is (y+k1*h/2)....most of the books don't have that h part
@numericalmethodsguy7 жыл бұрын
Asfaque Khan The formula may look like y(i+1)=y(i)+(k1+.........)*h Some people write it is y(i+1)=y(i)+(k1p+.........) Both are right as the h is bundled with k1 as k1p=k1*h.
@asfaquekhan66147 жыл бұрын
oh..right!! got it...thanks sir for such early reply☺
@louiebarrett52803 жыл бұрын
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@danezechariah82573 жыл бұрын
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@shristithakur51073 жыл бұрын
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@juanmontalvo579110 жыл бұрын
This guy teaches way better than my worthless numerical methods professor at UTPA. I don't understand how my professor even got hired or how he gets such good scores on his course evaluations.
@vladishta7 жыл бұрын
just a heads up, for the third derivative in the Taylor series expansion, you have dx^2 in the denominator
@numericalmethodsguy12 жыл бұрын
@yousafkazmi The formula may look like y(i+1)=y(i)+(k1+.........)*h Some people write it is y(i+1)=y(i)+(k1p+.........) Both are right as the h is bundled with k1 as k1p=k1*h.
@SEPHi27.12 жыл бұрын
Thank you for the explanations.
@ashidilkhan11 жыл бұрын
elegant explanation
@numericalmethodsguy11 жыл бұрын
Yes, you can.
@iteeshaashwath16574 жыл бұрын
In deriving Runge-Kutta method of 4th order, how many unknown coefficients are involved originally and how many equations you get to find the values of these unknown coefficients? Hence how many coefficients can be chosen arbitrarily?
@pydamma11 жыл бұрын
for solving higher oder derivatives can we apply heuns method that i learnt from this video link nmmathforcollege
@skeeeeeeeert12 жыл бұрын
i love you sir!
@seanpo0312 жыл бұрын
Hello, how do you alter this formula to calculate a second order differential equation?
@sumitshrestha32616 жыл бұрын
Can you please explain why is it called the 4th order as the order of the derivative in the equation is one?
@numericalmethodsguy6 жыл бұрын
4th order as it uses up to 4th derivative terms in Taylor series.
@IceyJunior9 жыл бұрын
can you show the proof ?
@askfskpsk13 жыл бұрын
I think the subscript of derivatives should be x(i) when y(i+1) is expanded with Taylor series.