Numericals on Lens Formula and Magnification Class 10 | Light Class 10 Science (Physics) Chapter-10

[@VedantuClass9_10_11]

▶ ⏮ Subscribe to Vedantu 9 Channel to get Daily LIVE Classes Notifications👉 kzbin.info/door/TE39PG9dD_qkfjQ_Q18CAw ▶ ⏮ Vedantu9and10Maths 👉 kzbin.info/door/sF-RLz6jXt6Srl_MGFmNnQ ▶ ⏮ Vedantu9and10English 👉kzbin.info/door/rY58RJRPbUPALbNb1ncDjQ ▶ ⏮ Vedantu9and10SST 👉 youtube.com/@Vedantu9and10SST?si=k3ACJ8PcPxCqxq0Y ▶ ⏮ Vedantu9and10Biology 👉kzbin.info/door/JpjVz9KETg3kXTFsR_ALTQ ▶ ⏮ Vedantu9and10Physics 👉kzbin.info/door/D4frmhG3gSuySjK3WuspQg ▶ ⏮ Vedantu9and10Chemistry 👉kzbin.info/door/ocAzk3tn9EbMEh3oP58NKQ ▶ ⏮ Subscribe to Vedantu 9 and 10 Channel to get Daily LIVE Classes Notifications 👉 vdnt.in/YT9n10 📲💻 Join Vedantu Class 9 Telegram Channel 👉 t.me/vedantuclass09 📲💻 Join Vedantu Class 10 Telegram Channel 👉 t.me/Vedantu9n10 ▶ Sprint-X | Class 10 Mid-Term Preparation Playlist 👉 bit.ly/47DCmQP ▶ Class 10 | One Shot Playlist 👉 bit.ly/10thOneShot ▶ Vedantu Class 9 and 10 Preparation Strategy 👉 bit.ly/42inX8M

[@pragyachaturvedi5103]

(i) Yes . If a convex lens of focal length 10 cm is covered one half with a black paper , it can produce an image of the complete object between F2 and2F2. Ab ray digram kaise banau😅 (ii) (Object height)ho=4cm, f = 20 cm, u = - 15, v=?, hi=? 1/f=1/v−1/u =>1/v=1/f+1/u =>1/20+1/(-15)=1/20−1/15 =>1/v=3−4/60=−1/60 V=-60cm m=v/u => -60/-15 =>4= hi/ho =>4 =hi/4cm =>hi= +16cm(virtual erect enlarged vee😅) Lajawab session 🎉🎉❤ Thankyou very much sir!!

[@dineshchoubey5167]

On the 8th questions v + u = 100cm == in the question given v is 3 times the u then when we solve equation we got v=3u put it on equation v+u = 100 so we got 3u+u = 100 easily we got the value of objects distance that is 25cm and v = 75cm just by substitution method

[@iam._.adiii.]

Homework Answer :- When one half of a convex lens is covered with black paper, it will still produce a complete image of an object because light rays can still pass through its optical center. Object size h = +4cm Object distance u = -15cm Focal length f = 20cm Image distance v = ? Image size h' = ? Using Lens Formula 1/f = 1/v - 1/u 1/v = 1/f + 1/u 1/v = 1/20 + 1/-15 v = -60 cm Nature of the image is Virtual and erect Position is Beyond 2F1 Size is Enlarged Exact size in cm is 4 times that of the object Using magnification formula m = v/u m = -60/-15 m = 4 There fore height of image is 60 cm Thank you sir

[@class9th]

Brother the height of the image would be 16cm Since, m=4 m=Hi/Ho 4=Hi/4 (given) Hi=4*4 Hi=16 By the way, It was just a silly mistake so just be careful from such mistake. 😊

[@pokerkillerff1008]

​@@class9th😊

[@AnamtaKhan-qs9mu]

HW a) Yes, the convex lens can produce the image of an object if one half of the lens is covered with black paper. This is because another half of the lens is still transparent and an object produces infinite rays out of which only two rays are sufficient to make the image of the object. However, the brightness and intensity of the image would be low b) ho = 4cm f = 20 cm u = -15 cm 1/f = 1/v - 1/u 1/v = 1/f + 1/u 1/v = 1/20 + 1/(-15) 1/v = 1/20 - 1/15 = 1/-60 v = -60cm m = v/u m = (-60)/(-15) m = 4

[@MuskanGupta-br7sy]

15:42 m=-v/u

[@parthchavan3312]

SIR YOU SHOULD BE MORE CONFIDENT TO INCREASE YOUR SUBSCRIBERS OTHERWISE YOU ARE A GOOD TEACHER THANKU

[@dakshmehan4114]

Sir in the 8th question you need to take -u + v =100 because they said distance between them and if we take u then we will get a negative value so we need to take -u to get the distance between. That's my understanding, I could be wrong I got the answer 18.75 like the solution given

[@parthchavan3312]

BE ENERGETIC

[@pragyachaturvedi5103]

Sir, u=-1/4 (-0.25)hoga kyuki u=-u likhenge equation (1) me In question no.8

[@ashapande715]

Homework Answer :- A convex lens which can produce the complete image of the object whereas half of the lens is covered. Because light coming from the object can be refracted from the other half of the lens. Therefore, the intensity of light will be reduced. Object size h = +4cm Object distance u = -20cm Focal length f = -10cm Image distance v = ? Image size h' = ? Using Lens Formula 1/f = 1/v - 1/u 1/v = 1/f - 1/u 1/v = -1/20 v = -20 cm The screen should be placed at 20 cm from the mirror . The image is real. Magnification m = -1 So, the image is inverted and enlarged.

[@Riya_Vargotry]

@ashapande715 tum ne copy paste kiu kiya hai....

[@ashapande715]

​@@Riya_Vargotry Copy Paste nahi Kiya khud se solve Kiya Hai.

[@Riya_Vargotry]

​@@ashapande715 Matlab mane bilkul same solution deekha tha but koi baat nahi

[@BishwaThisSide]

Hw ans i) yes the image will be formed but the intensity will decrease the image will be btw 2f2 and f2 ii) v = -60 Likhne main alas aata hai isliye short main ans kiya hai bhaiya😅😅 fingers crossed to be in hw rockers 🤞🤞 Bhaiya abhi bhi us question main jisme aap ko bhi doubt tha wo abhi bhi smaj nhi aaya Pls reply kar dena agar uska koi solution hai to 😊😊

[@moshamosha4584]

2) vitual erect magnified image is formed object is placed between o and f

[@siddiqueahmad8521]

Sir Q. 8 solution is correct. By taking -u+v =100 (in cm).

[@Bikiyatungofficial]

36:55 didn't understand

[@sakshita3879]

Yes

[@ZikraKhan000]

Hw Ans:- if one half is covered with black paper it will still form a full image as rays can pass through it b) v=-60 cm Sirrr monday se marathons 😌💗 the most exciting series 🔥 Sir Sprint x mai itne laddu question kabse aane lage 😌😂 Balle-Balle!! Tararara💗✨

[@fukreyinsan8999]

Q15 ans.)yes

[@rv.582]

12:30 sir hame kaise pata ki image real hai ya inverted, aapne directly +ve mein liya hai "f" Ko?..

[@dimplekapur2340]

Ak no. Sirrr maja hi a gaya

[@pornimabhongle8674]

Sir in 8th que it should be -u+v=1

[@ManojKumar-ev8md]

Sir ques 8 me v + u = 1 nhi hoga v - u = 1 hoga tho correct a jayega apka Shai se thanks for beautiful session 😊😊😊😊😊😊😊

[@Jsr_Ritesh_7]

40 CM 😮

[@kripagarg7480]

Balle balle ✌🏻

[@iamahiranffid]

V=-60 and hi=8 cm virtual and erect image no it cannot form complete image of the object ❤

[@RithvikGireesh]

Will it be v - u = 1 for question 8?

[@padmavatinayak1526]

Balle balle

[@kartikpal2143]

40

[@kripagarg7480]

Yesss sir

[@RanjitKumarpatel-g8h]

Magnification positive j

[@Riya_Vargotry]

HW ANS (a) In a convex lens if a half lens is covered then, light will come from the obj object and form a image but it's intensity will get reduce (b) v = -60 cm image will formed virtual and erect.. ❤❤❤❤❤❤❤❤❤ Sir 14 question samajh nahi aaya 🥺🥺 Samajh do ek bar please sir Balle balle 🔥

[@Indianofficial-bb7xp]

Hi sir

[@kripagarg7480]

Yessss

[@Indianofficial-bb7xp]

10

[@moshamosha4584]

Magnification positive 3 liya hai

[@AhiranpankajYadav-ms3wz]

B

[@wavelbeast3854]

Sir how to across this question ❓

[@AhiranpankajYadav-ms3wz]

C

[@AhiranpankajYadav-ms3wz]

A

[@tamashrichakraborty7883]

Homework Answer:- Yes. when a convex lens of focal length 10 cm is covered one half with a black paper, it can produce an image of the complete object between F2 and 2F2. focal length (l) = +20cm(since it is a convex lens) object distance (u) = -15cm (since it is a convex lens) Therefore, by lens formula, 1/f = 1/v - 1/u =>1/20 = 1/v - (-1/15) => 1/20 = 1/v + 1/15 => 1/20 - 1/15 = 1/v => 1/v = 3-4/60 (taking LCM) => 1/v = -1/60 => v = -60 cm (since the image is formed on the side of object and opposite to the direction of incident ray) Therefore image distance is 60 cm object height (O) = +4 cm We know, magnification (m) = I/0 = v/u => m = -60/-20 = v/4 => m = 4 = v/4 => m = v = 16 cm Therefore size of image is four times the size of object, i.e., 16 cm. Thus, Since the object was between the optical center and focus so the image is formed on the same side as the object, enlarged, virtual and erect. Amazing session sir

[@moshamosha4584]

1st answer is yes it will form complete image but not HD IMAGE 😂

[@Indianofficial-bb7xp]

Sir 2minute se jyada ho gya

[@AnamtaKhan-qs9mu]

Sir Question no.8 me u negative lena tha, Given, -u + v = 100 ......eq (1) Magnification = v /u = -3 (real and inverted image) v = -3u ........eq (2) Focal length 1/f = 1/v - 1/u ......eq (3) Substitute eq (2) in eq (1), we get u = -25 cm eq (2) v = -3 u = - 3 *- 25 = 75 cm Substitute eq (2) in eq (3), we get f = - 3 u/4 = -3 * -25/4 = 18.75 cm.

[@kumkumlata3219]

Hw

[@Indianofficial-bb7xp]

No

[@vinaypandey906]

Sir i think aapko physics ka teacher hona hi nhi chahiye tha aap bahut mistake karte ho sir itna mistake mat kiya karo kuch samjh nhi aata hai Best teacher for physics are rakshak sir and alakh sir. You are not best fot physics😢😮😅

[@AtharvBorse-h5c]

Nfjf

[@Bikiyatungofficial]

Sir is much better than prasand sir

[@narendrashrimali6669]

Behen please don't compare anyone's teaching it's just your mindset..😅🙌🫡

[@ApexGamer64]

Legend who watch this video before exam😂 like kro jo exam se ek din phele dekh rhe hai

[@FreeFire-gg4rv]

Isko khud nahi aata hai ye kya padhayega Sir aap se na ho payega Padhana band kijiye

[@Shriyathakur123]

Kiska exam 2 March ko hai......😅

[@madhukarnarayan8970]

wrong formola -v/u=m

[@SAMAR309.]

bro ywh mirror ka formula hota h

[@P.avy_2706]

Ye formula sahi hi to hai nahi magnification=-v/u

[@P.avy_2706]

Bro mirror formula to 1/f=1/v-1/u hota hai

[@4327Jojo]

Formula is right,- sign mirror formula mae lagtai

[@madhukarnarayan8970]

@@4327Jojo solution me wrong hai ko pehle se laga hai

[@padmavatinayak1526]

Balle balle

[@P.avy_2706]

Balle balle 💃💃🕺🕺

[@AhiranpankajYadav-ms3wz]

D