Object Literals and Constructors

This tutorial explains what an Object literal is and how it differs from the Object constructor. Also discussed is what happens when you pass different types of values to the Object constructor method.
Code Sample GIST: gist.github.com/prof3ssorSt3v3/c7832cc14976e8bfd224772615ce0844

[@AbdoTech0]

your channel is a javascript HEAVEN 😍😂

[@jungl3ist]

The tempo, the tone, the information, the examples were just perfect for me. I m just diving into Js, and you re my to go explanation channel on day one. Many thanks.

[@dyracho6667]

Thank you, steve. This really makes sense. But I have to this two or three more times to fully understand.

[@bryantruelas9188]

You are extremely good at making concepts so easy to understand. Thanks for all your work.

[@tahasoft1]

The best JavaScript teacher ever. Really the best. Thanks for the great content.

[@rotrose7531]

ten minutes or so, you made clear all things about Object, it is not a easy feat. As always thank you very much. Best javascript channel I found on or beyond youtube.

[@iwswordpress]

Very useful recap on objects and primitives.

[@chesterxp508]

Another very cool tutorial!

[@alexanderhungerford8246]

Great explanation and examples!

[@AndrewDevUA]

awesome explanation!

[@r0mankon]

Awesome

[@michelange5102]

Wooooooow! Thanks!

[@moonagesyndrome]

Yep, this channel still rules.

[@annazmussakib4796]

Great explanation thanks ^_^

[@crashonthehumble]

Thank you

[@romeojoseph766]

sir, I have a confusion, why can "string" get access to String Object methods when it's decalared without anykeyword like this: "string" console.log("string" instanceof string)//prints out false if this is not an instance of String object why can it access the String object's property which is .length in this case console.log("string".length)//prints out the length of the string(6) it can also use method like .split() but console prints out "string" is not an instance os String object tho

[@SteveGriffith-Prof3ssorSt3v3]

A String is a primitive. It is only a value. However, you can create a String Object by writing new String(). If you use a method that belongs to the String Object on a string primitive, then JavaScript will create a parallel string object in the background in order to run the method. let s = 'steve'; let us = s.toUpperCase(); //s is a primitive string //us is also a primitive string A String Object was created behind the scenes and the value of s was sent to that object in order to run the toUpperCase method. The method returns a string primitive.

[@romeojoseph766]

I think it's a bit clear now thanks for clearing up my confusion@@SteveGriffith-Prof3ssorSt3v3

[@KmillionaryShopifyExperts]

Have you played The Stanley Parable?

[@SteveGriffith-Prof3ssorSt3v3]

Nope.