Objects in depth in javascript in hindi | chai aur

Visit chaicode.com for all related materials, community help, source code etc.
#javascript #hindi
Sara code yaha milta h
github.com/hiteshchoudhary/
Discord pe yaha paaye jaate h:
hitesh.ai/discord
Instagram pe yaha paaye jaate h:
/ hiteshchoudharyofficial

[@quickSilverXMen]

@1:13 objects intro @7:20 object key using symbol datatype @9:30 adv. @11:00 freezer( ) method in object @12:00 symbol snip again

[@razashah7881]

Sir bundle of thanks, yahan tk pohnch kar mujhe wakeyhi lag ra hey k ye course bohat keemti hey, is sey pehley me 2 bar JS ko doosrey mentors sey bhi kar chuka hun, ab third time aapse seekh raha hun, yahan aa kar mujhe aik bat ki zroor realization hui hey, wo ye k ab me ye dekhta hun k jis mentor sey me seekh raha hun, usey khud ko JS ka kitna pata hey, me sabhi mentor ki izzat karta hun, lakin in depth kabhi na kabhi student k dil esa phase zroor ata hey k wo critical way me sochney lagta hey, aik to aapkey teaching style bohat unique hey, or friendly hey, secondly aap apni tarf sey bharpoor try kartey hen k me jo bat samjha raha hun, wo student k dimagh me literally ghuss jaey.

[@ayaniegain]

The uniqueness of your course, you not only teach the topic but also learn the exact use of it.🥰

[@HydroJudge]

Iss lecture mein jo sir ne concepts bataaye hain woh sach mein in depth hain. Notes banaake aur ache se samajh aata hai. This series is lit.

[@user-eq6mj3fk9x]

finally found a great teacher on youtube , really really helpful

[@Sgsbakers]

in greeting & greetingTwo functions you log messages to the console but don't return anything, so they implicitly return undefined as an output after every console. But when we use return keyword in functions instead of console.log it will not output 'undefined'.

[@agentNirmites]

Why he didn't get it?

[@parvahuja7618]

true, because whenever we are using { } we have to explicitly write return whereas when simply using ( ) we do do not need to write it

[@abdush5830]

love you sir..ye Internet ki best series hai JS ki..Jitna aap deep explain kr rahe hain utna kisi ne ni kia hai Yt pr...very thanks Sir

[@phantomcatprojects8546]

hitesh sir be like raat 12:30 baje hai to best object tutorial to bana lu

[@Quickkit]

@15:15 hello sir,undefined is the return value of the function greeting( ).

[@farazahmed1668]

Q k humne dar-asal value ko print karwaya hai na k return, to jab kuch b return nahi hoga... to by default undifined he return hoga.

[@babarshabbir2554]

"Excellent tutorial, covers JavaScript objects' depths neatly! Loved the chai tea and code puns. #JavaScript" Note: This comment is written in Hindi script, which would look like - "पर excellant ट्यूटोरियल है, सक्षम JavaScript objects की depths निग्रानी करता है! Chai tea और code शब्दों से प्यार लगाया। #JavaScript"

[@tech_channel110]

Best video on internet Shandar lecture Keep making such an amazing video lecture for us These lectures are very helpful for us

[@cherishkansara7851]

Sir woh last mein undefined isliye araha hai kyuki function Console log kar raha hai na ki kuch return kar raha hai or an function ko console log mein print karwa rahe hai toh isliye undefined araha hai

[@user-ob8cv5wy7g]

omg i've seen such a high quality oontent like this on yt , i'm just getting jealous that many people can have access to this video and they'll be getting more info....damnn bro,this playlist is lit

[@vasudev3744]

sir the undefined value that is being printed on the screen is bcoz u r printing the return of the function which is not defined console.log(JsUser.greeting()) is wrong instead use JsUser.greeting() for calling the function

[@youtube_reels..]

thank you

[@rizwansaifi3590]

7:02 the issue with the object property "first name" when trying to access it as (object.first name ) is because of space , if the property name was "first" then in that case it is easily accessible as object.first or object["first"] both will work . As any property name is coerced as string

[@KoushikBiswas-jo7iy]

Yes both should work.

[@AmitRaj.2]

The full name has space in between and thus it cannot be acessed using . Notation but if there is no space and if we type the key in string expression like 'fullname' it can be accesed using . Notation

[@gamingwithme630]

right bro

[@md.talibansari7388]

@14:51 "undefined" is appearing because the function is not returning anything, and you have called the function inside the console.

[@satyanarayandalei-rz2kw]

Exactly

[@vlogs4u968]

Thank you sir ji main thoda research kiya ki KZbin pr available js ki jyadatar playlisto pr really sir ji sabse alak hai aapki playlist concept ko apne alak hi tarike se bataya hai bahut bahut dhanyavad sir ji

[@tusharsachdeva3654]

Thanks! Awesome way of explanation man. Damn

[@learning-shaharyar550]

10:00 The syntax of declaring a symbol inside object still does not seem to be correct because upon console.log(typeof JsUser[mySym]); // It returns *string* , whereas ideally it should return Symbol as its dataType.

[@hobabu7066]

Same doubt, have you got any answer ?

[@shaharyaransari4887]

@@hobabu7066 The Explaination was quite confusing. However following code prints type of symbol: // Objects let mysymbol = Symbol('Key1'); let myobj = { name: "Shaharyar Ansari", id: 1232, [mysymbol] : mysymbol } console.log(typeof myobj[mysymbol]);

[@shaharyaransari4887]

The only reason for using Square brackets inside an object is to assign a dynamic key. Forexample: let key = 'dynamicKey'; let value = 'This is a dynamic value'; let obj = { [key]: value }; console.log(obj); // Output: { dynamicKey: 'This is a dynamic value' }

[@user-np8rk3nh7q]

i think jaldbazi mei sir bhool gye

[@biswaranjansahu66]

There are no words for your teaching skill and knowledge sir.

[@shashankkumarpandey4184]

15:00 , you are using console.log(console.log()) thing thats why undefined coming, just like python when you do print(print("Hi")), it gives hi then none. print statement inside print statement. i don't know if my logic is correct but i can think of this only right now.

[@lokinagure]

Bilkul sahi he.

[@CodeWithDhruv-sy5bs]

The reason of undefined is because the greeting function is not returning anything it is just priniting thats why the return type is undefined

[@milindchaturvedi9770]

The best series on the internet !

[@NiteshChaudhary07.]

Mene bahut video's dekhi par maja nahi aya apki video dekhta hu to sach me apke video's achhe lagte he aur helpfull he thank you

[@YamrajShrestha]

I've been fortunate to have incredible guidance on my journey to becoming a full-stack programmer. Learning with the help of this amazing tutorial, I've been steadily mastering JavaScript, and it's been an enlightening experience. A big thank you to my learning companion for being there every step of the way.

[@zaindev31]

hh

[@zaindev31]

kkk

[@fawaz_exe]

@ 14.46 It gives undefined as we did not use return keyword there. If we use return it will not print undefined.

[@shouviksarkar7900]

14:51 undefined is bcz in greeting function we already had console.log('message') ...but while calling the function you used console.log(greeting()) again. due to to console.log() we are getting an undefined. Just write gretting() and there will be no undefined. same goes for 17:05

[@Bca.Wallah]

This is literally The best javascript playlist on KZbin. Hope the way you guide the students will truly bring a revolution. Lots of love Sir😍❤❤

[@nivilsangwan7352]

his eyes have that dark thing around them indicating the tiredness. BTW I am loving your videos and I am actually a 9th grade student and am able to understand almost everything. This course is better than any other course I've seen on YT. Thank You Sir.

[@harishankarthakur388]

This series is very addictive❤

[@set1675]

THIS SERIES IS SO ADDICTIVE , MY GOD😍😌

[@AbdulHameed-to3sg]

no doubt sir you are great teacher

[@kazitanim007]

When u call the function directly instead of console.log - "undefined" doesn''t show on the console.

[@formeusgamer4327]

Buhat achy sy apny explain kra Hai,🥰

[@saumyadipdutta5419]

Hello @Hitesh Sir, I think undefined in the last , is coming from console.log(). If we write JsUser.greeting() only then undefined will not show

[@WatchNotchK2S]

Sir , JsUser.greeting(); should be used to call the function and print the value in it. as you console.log(JsUser.greeting()) & console.log(JsUser.greetingTwo()); it want function to return a value and give the answer , thus you get udefined in the browser ( Correct me if i am wrong )

[@shashankmishra9014]

undefined @15:10 is due to the fact that console.log print what is returned when so in this case when greeting is used nothing is returned so fun returns undefined which is printed.

[@ranjeetchoudhary112]

I was waiting this type of video

[@user-np8rk3nh7q]

all the comments solve my residual doubts thank you guys

[@JavidSumra786]

Sir I think greeting function giving undefined because of we are printing this function so it expect some value

[@KrishnaArt13]

console.log("=======jsUser.greeting()====",jsUser.greeting()); console.log("=====jsUser.greetingTwo()======",jsUser.greetingTwo());

[@aaaaaannnnnnnaaaaaannnnnnn]

*Sir really React complete karney kay baad dekh raha ho concepts ko clear karney kai liyay ab samjh araha hai in depth course ka matlab😃*

[@saadkashif880]

same bhai react course complete kia hay or ab ye dekhna start kia or boht maza aaraha

[@SuryaKarigar]

Wow [ ] can take my job 😂😂 I better need to be ready for Interview Sir. It’s creating fear and confidence at the same time

[@SyedAsif08]

understood objects in js very well.....................................

[@vaibhavpalaria5821]

Sir ji pranam Thanks for a superb video

[@usama5619]

thank you! great teacher !

[@mansoorafzal4344]

Excellent Work Done bro

[@prakhargupta4347]

maza aagaya. thank you so much sir.

[@lovetriangle3232]

Thankyou for theamazing video sir but at 17:05 ,the output undefined occurrs bcoz in the line no 38 you used console.log to print a function(jsuser.greeting()), function directly excute when it called just by jsuser.greeting(),why we need to write console.log(jsuser.greeting()). i guess you miss that part sir.

[@munawarminhas7982]

in my case also there is 12:29 am haha,,, you are doing great sir, I eagerly await the backend series.

[@chaiaurcode]

Kya din, kya raat. Agr mza aa rha to kaam krenge hi

[@munawarminhas7982]

sir the best thing is that we never get bored by your videos,, main ny bht sary courses starrt kiye is sy phly but end kbhi nahi hua koi bhi , but jb sy apka js course dekhna start kiya hai aj 35th video hai within one week,almost 4-6 hours+ daily screen k samny gzr jaty hain time ka pta nahi chlta ,smj b aa jati or practice b ho jati@@chaiaurcode

[@md.abidullahmuhib]

Hi there, in this lecture we are getting undefined because we are executing a function inside console.log();. By executing JsUser.greeting(); we are printing "Hello JS user". And the execution value of JsUser.greeting() = undefined. Which we are printing by console.log(JsUser.greeting());. Waiting for a reply. Correct me if I am wrong. Love from Bangladesh 🇧🇩 .

[@robot6716]

@17:09 undefined in console becuase at line number 37 and 38 in console log greeting() and greetingTwo function are called a which do not return anything explicitly and by default "undefined". is returned.

[@Mahin_katariya]

As of 2024 the part where sir wrote at 6:33 " fullname " : " hitesh choudhary " and while we were trying to access it using the dot method it wasn't accessing but now we can access it using the dot method.✅

[@ammarsiddiqui6486]

sir is tutorial very help full for me jo me chz ki sekhe oski practise kasie kare for eg aj hum ne object seekh hai?

[@nikulkumar6224]

Finally Back ❤

[@srijareddy1088]

Thank you very much sir

[@vivekbhakhri735]

Awesome!!

[@kamilsiddiqui4252]

symbol is getting accessed without using square brackets in both the places in 2024 has the syntax for symbol changed ? I guess so as I used typeof() without square brackets it shows that it is a symbol datatype.

[@krishnavamsi1126]

THANKS A LOT BRO

[@hamvlogwale]

love this playlist

[@Abhinav-ep7vb]

Gold Js Content ON YT . keep Creating more content sir

[@karanbhandari1534]

the undefined in the last part was occurring because he was logging the invocation of the function..?

[@deepakmishra96]

Great video!

[@codethics4033]

@10:09 the methode that you told still shoing that in string even i dicleared it correct way .

[@GazzyYT69]

same problem

[@bngdtutorial2947]

when i am writting jsuser.greeting(); then it simply printing the result but, while writting console.log( jsuser.greeting()); then it printing the result along with undefine. It may due to we are not returning any value and still trying to console.log() .

[@user-ut8wp3uw7y]

@6:55 its giving access by full name by using dot

[@abdulajim9633]

Very nice js Course ✔✔❤❤❤❤❤❤

[@nitishsingh925]

Symbol is new to me 💯

[@aryangaur228]

Thank you very much sir!!

[@rjsuraj1205]

hey can anyone explain as Sir said constructor creates singleton objects , But constructors are used to create instances of objects, not specifically singleton objects.I am confused can anyone explain plz

[@technoyash2970]

Thank you so much bhaiya

[@BitFire007]

"Chai aur Code, you've successfully turned me into a JavaScript enthusiast. Your tutorials are gold!"

[@gauravmangal5191]

Two things, Primarily the undefined you were getting was because you were trying to print the output of the greeting function and since it returned nothing you got "UNDEFINED". Secondly, when I am printing the typeof obj[symbol] its printing undefined. IDK if its supposed to be this way or not. If anyone have time can you elaborate a lil.

[@siddharthrathore-lb8su]

for me obj[symbol] is printing string. Maybe you should check your code for any typo.

[@supernovaveda211]

10:20 me jo sir , key ka syntax shi kiye hai taki uska type symbol aa jae. Lekin syntax shi krke firse check kiye to type string hi hai.

[@nitin_diwakar01]

same problem

[@mrinvisible4095]

10:31 Sir, to use Symbol as a key, what if we use Map data structure!?

[@ritushrivatri6865]

Awesome 😶‍🌫

[@MonikaKumari-er4de]

Thank you sir❤️

[@ShudhanshuShree]

undefined is coming because the function greeting and greetingtwo is not returning anything and you are printing the output inside console.log(greeting());

[@Solanki493]

Chai aur code main mera swagat hi

[@f50achievers10]

We are getting undefined value because of function log, When we just call the function..it won't be undefined...😊

[@RiteshKumar-yq4cx]

wts the meaning of Array.from() , does it mean we are calling a from() method from Array object

[@user-hf6om6ts1q]

15:09 ye undefined line 34 se aa raha h qki at line 30, function greeting is not returning anything.

[@pritamvlogs7061]

sir wo ek excution isliye ho rha hai kyuki apne function call me v console.log krke call kiya hai isliye undefined show ho rha hai

[@akshaybadwaik-nl5ng]

thank you

[@shanksiuu]

15:00 maybe it's becuz of the absence of return value JsUser.greeting = function(){ return "Hello JS user"; } JsUser.greetingTwo = function(){ return `Hello JS user, ${this.name}`; } console.log(JsUser.greeting()); console.log(JsUser.greetingTwo()); OR function jsUser (name) { console.log(`Hello JS user, ${name}`) } jsUser("Hitesh")

[@amansayer4943]

15:15 We are not returning to print it, we just need to call the function with object name ex: User.greeting();

[@MCA_HimanshuSeth]

yeah & the point is that , the function doesn't return any value that is why it is printing undefined

[@FairyhunterGG]

Why can't I use the 'this' keyword in an object method with an arrow function?

[@anonymous6501]

const ob1 = { name : "Prateek", age : 30, "add" : "Prayagraj" } console.log(ob1["add"]); console.log(ob1.add); I checked today Now both syntax is working.

[@All-about-lea_rning]

the reason of undefined kyu ki aap ne function me console kiya hai aur execute ke time per bhi aap console kar rhe hai ya to execute ke time console mat kijiye ha to function me se console ko hata ke return kardo

[@manemanoj3068]

Just insane..

[@sanjoyal_world_07]

Guru jee ..next video upload kijiye js chapter 49 k baad se ...

[@sahilgupta7001]

the function was showing undefined because you logged a function which was not returning anything, how could you not get this simple thing

[@user-ub4er8ij5j]

I too started watching this video at 12:30 AM

[@BABABENNETT]

hitesh sir op

[@Tech_Space_Warrior]

Hi Sir! when you say that we didn't access the the value of a key when its in "full name" this formate but if we didn't give space it can and declear the key as full_name it can easily be access by consloe.log(User1.full_name). So what is that? explain please.

[@songsbattle]

Brother it was for understanding purpose only. In this, Sir wanted to show us the other ways of accessing the object key.

[@soumadip_skyy_banerjee]

🔥

[@rajatkatal9311]

appko 34th line pr console log nhi krna tha ye usika "undefined" aa rha hai. usse direct call krte to sirf ek baar print hota woo...

[@pushpendra10001]

sir tell me one thing after using square brackets it still give me type of symbol is string why ???? it only show under the object but if check the sybol type of on console it shows it is string

[@varchasvh02]

I was thinking the same.

[@AnishKarchuli]

Sir, I have some doubts. I am able to access full_name with a dot. We can't access it if we provide space between full and name. But usually, the key is declared without spaces. At 10:32, the typeof of [mySym] is also string. Although we put it in a square bracket, it is not showing as a symbol. Can you explain that?

[@zahidsarang2999]

console.log(typeof (JsUser[mySym)) is giving string Because the value you've assigned to the Symbol key in the JsUser object is a string So, when you fetch the value of this key and check its type, it tells you it's a string. and if you pass like this const mySym = Symbol("user1"); const JsUser = { [mySym]:mySym,} now it will give typeOf Symbol

[@MuhammadAbbas-m-6442]

If you want to determine that the property uses a Symbol key, you can check the property keys of the object and see if any of them are Symbols. Here's an example of how you can do this: if (Object.getOwnPropertySymbols(obj1).includes(mySym)) { console.log("the property has a Symbol key."); } else { console.log("the property does not have a Symbol key"); }

[@armorkinggaming1933]

it will show type as 'undefined' instead of symbol

[@adnanahmad1234]

@@zahidsarang2999 Thanks dear. It worked !!

[@ECommerceNews]

Function execute hone k baad jo "undefined" print ho raha hy wo function ki return value hy. am i right?

[@angshumanpathak2300]

Sir in the symbol part, even the console.log(typeof JsUser[mysym]); returns a string , is that correct representation ?

[@iam_PiyushKumar]

Brother use console.log(typeof Object.keys(JsUser)[2]); to check the type of key

[@iam_PiyushKumar]

Output will be undefined because Symbol are enumerable